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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • T Offline
      tianzhu
      last edited by

      teddy7171:

      The scale of map P is 1/p and the scale of map Q is 1/q. Suppose a street is represented by lines of 12cm long and 16cm long on maps P and Q respectively.
      a) find p/q and express the answer in the simplest form.
      b) if p=5000, find (i) the value of q, (ii) the actual length, in m, of the street.
      c) if p=5000 and the actual area of a plot of land in 2812.5metre square, calculate its area on (i) map P and (ii) map Q.
      Hi

      I did some reading using my boy’s textbook and will attempt to answer your question.

      a)A scale of 1:p means that 1cm represents pcm
      Therefore 12cm represent 12pcm in map P
      Likewise, 16cm represent 16qcm in map Q
      12p=16q
      Hence p/q = 4/3

      b)q = 3750
      The actual length of the street is 12*5000 = 600m

      c)For map P
      1cm represents 50m
      1 cmsq represents 2500 cmsq
      2812.5/2500 = 1.125 cmsq

      For map Q
      1cm represents 37.5m
      1 cmsq represents 1406.25 cmsq
      2812.5/1406.25 = 2 cmsq

      Are my answers correct?

      Best wishes

      1 Reply Last reply Reply Quote 0
      • T Offline
        teddy7171
        last edited by

        a)A scale of 1:p means that 1cm represents pcm

        Therefore 12cm represent 12pcm in map P
        Likewise, 16cm represent 16qcm in map Q
        12p=16q
        Hence p/q = 4/3

        b)q = 3750
        The actual length of the street is 12*5000 = 600m

        c)For map P
        1cm represents 50m
        1 cmsq represents 2500 cmsq
        2812.5/2500 = 1.125 cmsq

        For map Q
        1cm represents 37.5m
        1 cmsq represents 1406.25 cmsq
        2812.5/1406.25 = 2 cmsq

        Are my answers correct?

        Best wishes[/quote]


        Hi Tianzhu,
        My boy does not have the answers for the question and doesn’t know how to solve it.

        His answer for (a) is 3/4 instead.

        Please enlighten us how do u arrived at 4/3 and q = 3750.

        Sorry for the trouble and thanks.

        1 Reply Last reply Reply Quote 0
        • T Offline
          tianzhu
          last edited by

          Hi teddy7171


          In order to solve this question, students need to understand the concepts of Scales and Maps. You may refer to your son’s textbook for a more detailed explanation.

          A scale of 1:p means that 1cm represents pcm
          Therefore 12cm represent 12pcm in map P

          Likewise, 16cm represent 16qcm in map Q

          The same street is represented by different scales as in map P and Q
          12p=16q
          Hence p/q = 4/3

          Here p is given as 5000
          p/q = 4/3
          5000/q = 4/3
          Hence q = 15000/4 = 3750

          Best wishes

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          • S Offline
            Sahimi
            last edited by

            Hi! pls help!!


            If n is a number, show that for all values of n, (n3 + 11n) is divisible by 6. (sec Two maths)
            😢 Thks

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            • I Offline
              iFruit
              last edited by

              Sahimi:
              Hi! pls help!!


              If n is a number, show that for all values of n, (n3 + 11n) is divisible by 6. (sec Two maths)
              😢 Thks
              n³ + 11n = n³ -n + 12n = n(n²-1)+12n = n(n-1)(n+1)+12n = (n-1)n(n+1)+12n


              (n-1)n(n+1) is the product of 3 consecutive numbers which is always divisible by 6 ( you can use induction to prove if necessary) and 12n is divisible by 6.

              So, n³ + 11n is divisible by 6

              HTH

              1 Reply Last reply Reply Quote 0
              • S Offline
                Sahimi
                last edited by

                iFruit:
                Sahimi:

                Hi! pls help!!


                If n is a number, show that for all values of n, (n3 + 11n) is divisible by 6. (sec Two maths)
                😢 Thks

                n³ + 11n = n³ -n + 12n = n(n²-1)+12n = n(n-1)(n+1)+12n = (n-1)n(n+1)+12n


                (n-1)n(n+1) is the product of 3 consecutive numbers which is always divisible by 6 ( you can use induction to prove if necessary) and 12n is divisible by 6.

                So, n³ + 11n is divisible by 6

                HTH

                thks very much, iFruit.

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                • K Offline
                  k1ndan
                  last edited by

                  E:{x:30<x<=100}

                  A:{x: Multiples of 3}
                  B:{x: unit digit is 10}

                  What is A’n B’?[/url]

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                  • K Offline
                    k1ndan
                    last edited by

                    http://i300.photobucket.com/albums/nn19/k1ndan/Maths_Sec2_Set1.jpg\">

                    1 Reply Last reply Reply Quote 0
                    • K Offline
                      k1ndan
                      last edited by

                      k1ndan:
                      http://i300.photobucket.com/albums/nn19/k1ndan/Maths_Sec2_Set1.jpg\">

                      Sorry, typo error, the condition should be if a=b, what is the value of W?

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                      • K Offline
                        k1ndan
                        last edited by

                        € = {x : x is an integer, 30 < x≤100}

                        A: {x : x is divisible by 3}
                        😄 {x: units digits of x is 0}

                        List the elements of A’ n C’

                        1 Reply Last reply Reply Quote 0

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