Tutor MathsGuru: Ask me for your burning Maths questions!

[yeonee]

Need Help!


The sum of Ben’s age and his younger brother’s age is 26. The product of their ages is 144.
What is Ben’s age in 20 years’ time?

[Bunny27]

Thanks again, Yu Xuan!

Yu Xuan:

Bunny27:

Hi,
In the 1st week of a fund raising campaign, class 6a raised 4 times as much as class 6b. In the 2nd week, 6a raised another $240 while 6b raised another $160. Given that 6a raised thrice as much as 6b within these 2 weeks, what was the total amount of money raised by the 2 classes?

Hi

First week;
6a --> 4 units
6b --> 1 unit

2 weeks;
6a --> 4 units + $240 = 3 parts

6b -->1 unit + $160 = 1 part
------> 3 units + 480 = 3 parts

Using a model;

6a [ ][ ][ ][ ][--$240--]
6b [ ][ ][ ][----$480---]

Hence ;
1unit --> $480 - $240 = $240
5units --> $240 * 5 = $1200

$1200 + $240 + $160 = $1600

[Dharma]

yeonee:

Need Help!


The sum of Ben's age and his younger brother's age is 26. The product of their ages is 144.
What is Ben's age in 20 years' time?

144 = ( 2 x 2 x 2 ) x ( 2 x 3 x 3 ) = 8 x 18
Ben’s age now = 18
Ben’s younger brother’s age = 8
Ben’s age in 20 years’ time = 18 + 20 = 38

[ozora]

Need help again

1. Tom had 2 boxes, A and B, containing an equal number of white beads. He divided the white beads in BoxA into groups of 60 and to each group, he added 4 red beads before stringing them up to make necklances.

He divided the white beads in BoxB into groups of 90 and to each group, he added 5 blue beads before stringing them up to make necklances.
When he had finished, there was no more white beads in either boxes and he had used 28 more red beads than blue beads. How many red beads did he use altogther?

2. Jane and Shelia shared a sum of money.
If Jane gave 1/4 of her share to Shelia, Shelia would have $400 more than Jane
If Jane gave 1/5 of her share to Shelia, Shelia would have $154 more than Jane.
How much money did they have altogther?

3.A total of 350 children joined Camp A and CampB. Camp A was for girls and Camp B was for boys. THere were 2/5 as many girls as boys. More children joined in. For every 2 additional girls joined in Camp A, 1 additional boy joined CampB. Thus after the 1st day, there was an equal number of boys and girls. How many additional boys joined Camp B?

[rossypolly]

hi there! Pls help me with this qn


Sam bought some vanilla cookies and gave 1/2 of them to Mike.
Mike bought some chocholate bars and gave 1/2 of them to Sam.
Sam ate 8 chocolate bars and Mike ate 16 vanilla cookies.
The ratio of Sam’s vanilla cookies to chocolate bars became 8:1 and the ratio of Mike’s vanilla cookies to chocolate bars became 3:1.

How many vanilla cookies did Sam buy?

(Really appreciate your help)

[trytry]

LaiHeng:

Need help again

1. Tom had 2 boxes, A and B, containing an equal number of white beads. He divided the white beads in BoxA into groups of 60 and to each group, he added 4 red beads before stringing them up to make necklances.

He divided the white beads in BoxB into groups of 90 and to each group, he added 5 blue beads before stringing them up to make necklances.
When he had finished, there was no more white beads in either boxes and he had used 28 more red beads than blue beads. How many red beads did he use altogther?

BOX-----------------------------..........................--A.......................B
no of white bead in each gp.........................60......................90
Ratio of white beads in each gp....................2........................3
Ratio of no of gp.........................................3........................2
Ratio of additional beads in each box.........3x4=12..............2x5=10
....................................................................6.....................5


Difference of 6units-5units=1unit---------------------28

Number of red beads used=6x28=168

BTW LaiHeng, where did you get the question from?

[trytry]

LaiHeng:

2. Jane and Shelia shared a sum of money.

If Jane gave 1/4 of her share to Shelia, Shelia would have $400 more than Jane
If Jane gave 1/5 of her share to Shelia, Shelia would have $154 more than Jane.
How much money did they have altogther?

?

After condition 1.
Jane has.....................[....][....][....]
Shelia has...................[....][....][....]{400}

Reinstate condition before condition 1,
ie Shelia returned 1/4 of jane's to her.
.................................-------------20u-------
Jane...........................[||||][||||][||||][||||]
Shelia.........................[||||][||||]{400}
..................................----10u.....

Now condition 2.
..................................-------16u--------154
Jane...........................[||||][||||][||||][]==
Shelia.........................[||||][||||][|||]{400}
..................................-------14u-----

..................................................2 u-------->400-154=246
..................................................1u--------->246/2=123

They have................20u+10u+400=30u+400=30x123+400
.....................................=4090




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[trytry]

LaiHeng:

3.A total of 350 children joined Camp A and CampB. Camp A was for girls and Camp B was for boys. THere were 2/5 as many girls as boys. More children joined in. For every 2 additional girls joined in Camp A, 1 additional boy joined CampB. Thus after the 1st day, there was an equal number of boys and girls. How many additional boys joined Camp B?

No of girls= 350x2/7=100
No of boys=350x5/7=250

.......................Girls..................Boys
Number of.........100....................250
Joined.................2u.....................1u

girls..............|[][]{100}|
boys.............|[]{.250.}|
....................|--same---|

1u-------->250-100=150
150 additional boys joined.

[peterch]

Morning…


Please help me with this P5 Math:

The following numbers are the factors of a certain number.

1 , 2 , 3 , __ , 6 , 12 , 18 , __ , 36

a) What is the number?
b) Fill in the missing factors in the 2 boxes above.

Thanks a lot …

Regards

[atutor2001]

peterch:

Morning....


Please help me with this P5 Math:

The following numbers are the factors of a certain number.

1 , 2 , 3 , __ , 6 , 12 , 18 , __ , 36

a) What is the number?
b) Fill in the missing factors in the 2 boxes above.

Thanks a lot .....

Regards

Pair them
1x36 = 36
2x18=36
3x12=36
4x9=36
6x6=36

missing numbers are 4 & 9