Tutor MathsGuru: Ask me for your burning Maths questions!

[Muffins]

HVR:

There were 258 pupils in the hall. After 1/3 of the boys left and 22 girls entered, the number of boys and girls is equal.

Q1) how many boys were in the hall at first?
Q2) how many more boys than girls were in the hall at first?

Thanks!

Will try for fun

so, the total numbers of boys and girls will be 2x (since x is for boys, and x for girls, assuming they are equal)

So in the beginning,

Girls = x - 22
Boys = x + 0.5x

so, 2.5x - 22 = 258

2.5x = 280

therefore, x = 112

112 X 1.5 = 168

that's for a, need to go now hope that helped

[Muffins]

HVR:

There were 258 pupils in the hall. After 1/3 of the boys left and 22 girls entered, the number of boys and girls is equal.

Q1) how many boys were in the hall at first?
Q2) how many more boys than girls were in the hall at first?

Thanks!

Will try for fun

so, the total numbers of boys and girls will be 2x (since x is for boys, and x for girls, assuming they are equal)

So in the beginning,

Girls = x - 22
Boys = x + 0.5x

so, 2.5x - 22 = 258

2.5x = 280

therefore, x = 112

112 X 1.5 = 168

that's for a, need to go now hope that helped

[Chan09]

Need some help on this question. Male and female participants were divided equally into team A, B and C. Number of males in A is equal to number of females in B. 1/5 of males were in C. There were 160 more females than males altogether. What was total number of females? :stupid:

[ADoc]

Chan09:

Need some help on this question. Male and female participants were divided equally into team A, B and C. Number of males in A is equal to number of females in B. 1/5 of males were in C. There were 160 more females than males altogether. What was total number of females? :stupid:

Hi there! Not sure if I understand the question correctly. The answer would be 560. Pls see image for solution. Do note that actual solution need not be as wordy. Mine is elaborated due to explanation. Hope it's useful. Cheers!

ADoc
http://postimage.org/image/21onjf81w/

[Dharma]

Chan09:

Need some help on this question. Male and female participants were divided equally into team A, B and C. Number of males in A is equal to number of females in B. 1/5 of males were in C. There were 160 more females than males altogether. What was total number of females? :stupid:

Hi Chan09,

This is an alternative to ADoc's solution.

http://postimage.org/image/ad1jln8k/

[Chan09]

Thank you. Is there a good maths book to learn this? :lol:

[Yu Xuan]

Dharma:

Chan09:

Need some help on this question. Male and female participants were divided equally into team A, B and C. Number of males in A is equal to number of females in B. 1/5 of males were in C. There were 160 more females than males altogether. What was total number of females? :stupid:

Hi Chan09,

This is an alternative to ADoc's solution.

http://postimage.org/image/ad1jln8k/

Hi Dharma & Adoc

I would like 2 view your solution, but hv problem opening it. Seems 2 hv this probl everytime. Thk you.

Regds
Yu Xuan

[Dharma]

Yu Xuan:

Dharma:

[quote=\"Chan09\"]Need some help on this question. Male and female participants were divided equally into team A, B and C. Number of males in A is equal to number of females in B. 1/5 of males were in C. There were 160 more females than males altogether. What was total number of females? :stupid:

Hi Chan09,

This is an alternative to ADoc's solution.

http://postimage.org/image/ad1jln8k/

Hi Dharma & Adoc

I would like 2 view your solution, but hv problem opening it. Seems 2 hv this probl everytime. Thk you.

Regds
Yu Xuan[/quote]Hi Yu Xuan,

Just left click on the image.

[Yu Xuan]

Hi Dharma,


Have done that many times… but i’ve got blank screen.
Thanks for the trouble.

Yu xuan

[Dharma]

Yu Xuan:

Hi Dharma,


Have done that many times... but i've got blank screen.
Thanks for the trouble.

Yu xuan

No. of males (Team A) = 1p
No. of females (Team B) = 1p

If the total number of males in Team C (1u) is 1/5 of the total number of males, the total number of males will be 5u.

Since the males and females are divided equally into the 3 teams (A, B and C); each of the 3 teams must have the same number of participants.

We can say that
No. of females (Team A) = 1u
No. of males (Team B ) = 1u
No. of females (Team C ) = 1p

Total number of males is 5u,
1p + 1u + 1u = 5u
1p = 3u

Total no. of females = 1u + 1p + 1p = 7u
Total no. of males = 1p + 1u + 1u = 5u

Difference between females and males = 7u – 5u = 160
2u = 160
1u = 80

Total number of females = 7u = 7 x 80 = 560