O-Level Additional Math
-
Any one has a tuition centre to recommend for Sec 2 Math? Right now DS is borderline pass case but need a quick jump to at least 70 to be offered a Double Science class next yr.
We put up in Bukit Merah area but don’t mind travelling a bit if the teacher is gd. I just checked Learning Lab and its fees are $900+ a term. Is this the going rate for Sec Math classes? -
skyjuice:
Any one has a tuition centre to recommend for Sec 2 Math? Right now DS is borderline pass case but need a quick jump to at least 70 to be offered a Double Science class next yr.
We put up in Bukit Merah area but don't mind travelling a bit if the teacher is gd. I just checked Learning Lab and its fees are $900+ a term. Is this the going rate for Sec Math classes?
You may want to check out with maths hub at
http://www.mathshub.com.sg/ -
Hello,
Helping my niece ask this qn:
Find an expression f(x) such that d/dx [f(x)] = 1/(xlnx)
Thanks for help. -
elkniwt:
d/dx [f(x)] = 1/(xlnx)Hello,
Helping my niece ask this qn:
Find an expression f(x) such that d/dx [f(x)] = 1/(xlnx)
Thanks for help.
= (1/x ) / (ln x)
f(x) = ln (ln x) + c (Ans) -
hello can i get help for the following algebra question…
(m+2)/3 + 2(m-5)/4
Sorry new to algebra solved untill 10m-22 / 12 stuck after it -
Acsian:
hello can i get help for the following algebra question......
(m+2)/3 + 2(m-5)/4
Sorry new to algebra solved untill 10m-22 / 12 stuck after it
(m+2)/3 + 2(m-5)/4
= [(m+2)*4]/(3*4) + [2(m-5)*3]/(4*3)
= [ (4m+8)+ (6m-30) ] / 12
= (10m-22) / 12
= (5m-11) / 6 (Ans) -
jieheng:
actually the answer in my math handbook is 5m-5/6 and i typed the equation wrongly :oops:Acsian:
hello can i get help for the following algebra question......
(m+2)/3 + 2(m-5)/4
Sorry new to algebra solved untill 10m-22 / 12 stuck after it
(m+2)/3 + 2(m-5)/4
= [(m+2)*4]/(3*4) + [2(m-5)*3]/(4*3)
= [ (4m+8)+ (6m-30) ] / 12
= (10m-22) / 12
= (5m-11) / 6 (Ans)
correct equation
(m+2)/3 + 2(m-5)/4 +1 -
Acsian:
actually the answer in my math handbook is 5m-5/6 and i typed the equation wrongly :oops:jieheng:
[quote=\"Acsian\"]hello can i get help for the following algebra question......
(m+2)/3 + 2(m-5)/4
Sorry new to algebra solved untill 10m-22 / 12 stuck after it
(m+2)/3 + 2(m-5)/4
= [(m+2)*4]/(3*4) + [2(m-5)*3]/(4*3)
= [ (4m+8)+ (6m-30) ] / 12
= (10m-22) / 12
= (5m-11) / 6 (Ans)
correct equation
(m+2)/3 + 2(m-5)/4 +1[/quote]
(m+2)/3 + 2(m-5)/4 +1
=[ (10m-22) / 12 ] + 12/12
= (10m-22+12) / 12
= (10m-10) / 12
= (5m-5) / 6 (Ans) -
jieheng:
actually the answer in my math handbook is 5m-5/6 and i typed the equation wrongly :oops:Acsian:
[quote=\"jieheng\"]
(m+2)/3 + 2(m-5)/4
= [(m+2)*4]/(3*4) + [2(m-5)*3]/(4*3)
= [ (4m+8)+ (6m-30) ] / 12
= (10m-22) / 12
= (5m-11) / 6 (Ans)
correct equation
(m+2)/3 + 2(m-5)/4 +1
(m+2)/3 + 2(m-5)/4 +1
=[ (10m-22) / 12 ] + 12/12
= (10m-22+12) / 12
= (10m-10) / 12
= (5m-5) / 6 (Ans)[/quote]
Thanks Alot jieheng Thanks :thankyou: -
Acsian:
Hi Acsian ,
Thanks Alot jieheng Thanks :thankyou:
You are welcome.
Regards,
Hello! It looks like you're interested in this conversation, but you don't have an account yet.
Getting fed up of having to scroll through the same posts each visit? When you register for an account, you'll always come back to exactly where you were before, and choose to be notified of new replies (either via email, or push notification). You'll also be able to save bookmarks and upvote posts to show your appreciation to other community members.
With your input, this post could be even better 💗
Register Login