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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • S Offline
      skyjuice
      last edited by

      Any one has a tuition centre to recommend for Sec 2 Math? Right now DS is borderline pass case but need a quick jump to at least 70 to be offered a Double Science class next yr.


      We put up in Bukit Merah area but don’t mind travelling a bit if the teacher is gd. I just checked Learning Lab and its fees are $900+ a term. Is this the going rate for Sec Math classes?

      1 Reply Last reply Reply Quote 0
      • Y Offline
        YLH88
        last edited by

        skyjuice:
        Any one has a tuition centre to recommend for Sec 2 Math? Right now DS is borderline pass case but need a quick jump to at least 70 to be offered a Double Science class next yr.


        We put up in Bukit Merah area but don't mind travelling a bit if the teacher is gd. I just checked Learning Lab and its fees are $900+ a term. Is this the going rate for Sec Math classes?

        You may want to check out with maths hub at

        http://www.mathshub.com.sg/

        1 Reply Last reply Reply Quote 0
        • E Offline
          elkniwt
          last edited by

          Hello,


          Helping my niece ask this qn:

          Find an expression f(x) such that d/dx [f(x)] = 1/(xlnx)

          Thanks for help.

          1 Reply Last reply Reply Quote 0
          • J Offline
            jieheng
            last edited by

            elkniwt:
            Hello,


            Helping my niece ask this qn:

            Find an expression f(x) such that d/dx [f(x)] = 1/(xlnx)

            Thanks for help.
            d/dx [f(x)] = 1/(xlnx)

            = (1/x ) / (ln x)

            f(x) = ln (ln x) + c (Ans)

            1 Reply Last reply Reply Quote 0
            • A Offline
              Acsian
              last edited by

              hello can i get help for the following algebra question…


              (m+2)/3 + 2(m-5)/4

              Sorry new to algebra solved untill 10m-22 / 12 stuck after it

              1 Reply Last reply Reply Quote 0
              • J Offline
                jieheng
                last edited by

                Acsian:
                hello can i get help for the following algebra question......


                (m+2)/3 + 2(m-5)/4

                Sorry new to algebra solved untill 10m-22 / 12 stuck after it


                (m+2)/3 + 2(m-5)/4

                = [(m+2)*4]/(3*4) + [2(m-5)*3]/(4*3)

                = [ (4m+8)+ (6m-30) ] / 12

                = (10m-22) / 12

                = (5m-11) / 6 (Ans)

                1 Reply Last reply Reply Quote 0
                • A Offline
                  Acsian
                  last edited by

                  jieheng:
                  Acsian:

                  hello can i get help for the following algebra question......


                  (m+2)/3 + 2(m-5)/4

                  Sorry new to algebra solved untill 10m-22 / 12 stuck after it



                  (m+2)/3 + 2(m-5)/4

                  = [(m+2)*4]/(3*4) + [2(m-5)*3]/(4*3)

                  = [ (4m+8)+ (6m-30) ] / 12

                  = (10m-22) / 12

                  = (5m-11) / 6 (Ans)

                  actually the answer in my math handbook is 5m-5/6 and i typed the equation wrongly :oops:

                  correct equation

                  (m+2)/3 + 2(m-5)/4 +1

                  1 Reply Last reply Reply Quote 0
                  • J Offline
                    jieheng
                    last edited by

                    Acsian:
                    jieheng:

                    [quote=\"Acsian\"]hello can i get help for the following algebra question......


                    (m+2)/3 + 2(m-5)/4

                    Sorry new to algebra solved untill 10m-22 / 12 stuck after it



                    (m+2)/3 + 2(m-5)/4

                    = [(m+2)*4]/(3*4) + [2(m-5)*3]/(4*3)

                    = [ (4m+8)+ (6m-30) ] / 12

                    = (10m-22) / 12

                    = (5m-11) / 6 (Ans)

                    actually the answer in my math handbook is 5m-5/6 and i typed the equation wrongly :oops:

                    correct equation

                    (m+2)/3 + 2(m-5)/4 +1[/quote]
                    (m+2)/3 + 2(m-5)/4 +1

                    =[ (10m-22) / 12 ] + 12/12

                    = (10m-22+12) / 12

                    = (10m-10) / 12

                    = (5m-5) / 6 (Ans)

                    1 Reply Last reply Reply Quote 0
                    • A Offline
                      Acsian
                      last edited by

                      jieheng:
                      Acsian:

                      [quote=\"jieheng\"]


                      (m+2)/3 + 2(m-5)/4

                      = [(m+2)*4]/(3*4) + [2(m-5)*3]/(4*3)

                      = [ (4m+8)+ (6m-30) ] / 12

                      = (10m-22) / 12

                      = (5m-11) / 6 (Ans)

                      actually the answer in my math handbook is 5m-5/6 and i typed the equation wrongly :oops:

                      correct equation

                      (m+2)/3 + 2(m-5)/4 +1


                      (m+2)/3 + 2(m-5)/4 +1

                      =[ (10m-22) / 12 ] + 12/12

                      = (10m-22+12) / 12

                      = (10m-10) / 12

                      = (5m-5) / 6 (Ans)[/quote]
                      Thanks Alot jieheng Thanks :thankyou:

                      1 Reply Last reply Reply Quote 0
                      • J Offline
                        jieheng
                        last edited by

                        Acsian:




                        Thanks Alot jieheng Thanks :thankyou:
                        Hi Acsian ,

                        You are welcome.

                        Regards,

                        1 Reply Last reply Reply Quote 0

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