Tutor MathsGuru: Ask me for your burning Maths questions!

[jieheng]

YumYum:

hi,


Can anyone pls assist with the foll Qns:

2. The total number of pupils in the two classes 6A and 6B is 84. 5/8 of 6A pupils and 3/4 of 6B pupils add up to 58. Fing the number of pupils in 6B.

Note : There is no direct relationship between pupils in 6A and pupils in 6B

6A [--][--][--][--][--][--][--][--] (total 8*[--])

6B {---}{---}{---}{---} (total 4*{---})

[--] = [--] and {---} = {---}

given [--][--][--][--][--] + {---}{---}{---} = 58

[--][--][--] + {---} = 84 - 58 = 26 (1 set)

12*[--] + 4*{---} = 26*4 = 104 (4 sets)

8*[--] + 4*[--] + 4*{---} = 104

4*[--] + 84 = 104

4*[--] = 104 - 84 = 20

8*[--] = 20*2 = 40

number of pupils in 6A = 40

number of pupils in 6B = 84 - 40 = 44 (Ans)

[jieheng]

YumYum:

hi,


Can anyone pls assist with the foll Qns:

3. Allan had 60 more stamps than Becky. They each gave some of their stamps to their friends. The number of stamps Becky gave away was 2/5 of the number of stamps Allan had at first; the number of stamps Allan gave away was 2/3 of the number of stamps Becky had at first; Both had an equal number of stamps left. How many stamps did Allan have at first?

A [----15u------][--60--]

B [----15u------]

reason for using 15u because it is the common multiples of 3 and 5

2/5 of A is 6u+24

2/3 of B is 10u


A [----15u------][--60--] - 10u

B [----15u------] - (6u+24)

15u + 60 - 10u -----> 15u - (6u+24)

5u + 60 -----> 9u - 24

4u -----> 84

1u -----> 21

15u -----> 21*15 = 315

number of stamps Allan had at first = 15u + 60 = 315 + 60 = 375 (Ans)

[YumYum]

jieheng:

YumYum:

hi,


Can anyone pls assist with the foll Qns:

3. Allan had 60 more stamps than Becky. They each gave some of their stamps to their friends. The number of stamps Becky gave away was 2/5 of the number of stamps Allan had at first; the number of stamps Allan gave away was 2/3 of the number of stamps Becky had at first; Both had an equal number of stamps left. How many stamps did Allan have at first?

A [----15u------][--60--]

B [----15u------]

reason for using 15u because it is the common multiples of 3 and 5

2/5 of A is 6u+24

2/3 of B is 10u


A [----15u------][--60--] - 10u

B [----15u------] - (6u+24)

15u + 60 - 10u -----> 15u - (6u+24)

5u + 60 -----> 9u - 24

4u -----> 84

1u -----> 21

15u -----> 21*15 = 315

number of stamps Allan had at first = 15u + 60 = 315 + 60 = 375 (Ans)

Hi JieHeng,

Thank you for the detailed explanations. They certainly help.

[MUMMYOF3]

Hi,


Can someone assist me with the following P5 question : -

Alan, Benny, Clement and Danny has 105 marbles. Alan lost 3 marbles and Danny lost 1/2 of what he had. Benny’s sister gave Benny another 6 marbles. Clement’s aunt rewarded Clement by doubling what he had originally. In the end, the 4 boys had an equal number of marbles. How many more marbles than Danny did Alan at first ?

[Daddy]

Thanks jieheng.

[Daddy]

Thanks jieheng.

[pixiedust]

Mummyof3


Start with the after situation :

A […]
B […]
C […]
D […]

Then add the clues to get to the starting situation

A […][…][3]
B […][6]
C […]
D […][…][…][…]

A : 2U +3
B : 2U -6
C : U
D : 4U

9U -> 105
U -> 12

Ans: Danny has 21 marbles more.

[pixiedust]

Mumyof3


I read the question again, it should be how many more marbles than Alan did Danny have?

Check:
Before:
Alan 27
Benny 18
Clement 12
Danny 48

After : each 24

[jieheng]

YumYum:

Hi JieHeng,

Thank you for the detailed explanations. They certainly help.

Hi YumYum ,

You are welcome.

Regards,

[jieheng]

Daddy:

Thanks jieheng.

Hi ,

You are welcome.

Regards