Q&A - PSLE Math
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Jack bought some pens and erasers for a total of $100.10.
He spent $9.10 more on the pens than the erasers.
Each pen costs $3.70 more than each eraser.
Jack bought 6 times more ereasers than pens. How much does each pen cost? -
I'm not sure if this is right, but based on my interpretation of the question:
Quantity of P:E is 1:7
P [__]
E [__][__][__][__][__][__][__]
Price of P & E (in total)
P [_______][_$9.10_] ````` } Total
E [_______] ````````````` }$100.10
By Price:
$100.10 - $9.10 = $91
2u -> $91
1u -> $45.50
Since there are 7 units of erasers, each unit of erasers will cost $45.50/7 = $6.50
The price of the pens is $45.50 + $9.10 = $54.60
Price of pens take away the price of 1 unit of erasers (to find the difference in amount if the same amount of pens & erasers were bought):
$54.50 - $6.50 = $48.10
Since each pen is more expensive than each eraser by $3.70,
$48.10/$3.70 = 13 pens
To find the price of each pen:
$54.60/13pens = $4.20 -
Denise:
Its correctJack bought some pens and erasers for a total of $100.10.
He spent $9.10 more on the pens than the erasers.
Each pen costs $3.70 more than each eraser.
Jack bought 6 times more ereasers than pens. How much does each pen cost? -
mrswongtuition:
Sorry ...the answer is rightI'm not sure if this is right, but based on my interpretation of the question:
-
Hi,
Can someone help to solve this problem. TIA
Allen, Raymond and Tom ran at a speed of 5km/h, 6km/h and 7km/h respectively.
They ran along the same route and started at 6.00 am, 6.30 am and 7.00 am respectively.
When Raymond passed Allen, he gave Allen a message to pass to Tom.
What time will Tom receive the message? -
ack bought some pens and erasers for a total of $100.10.
He spent $9.10 more on the pens than the erasers.
Each pen costs $3.70 more than each eraser.
Jack bought 6 times more ereasers than pens. How much does each pen cost?
How many pens and how erasers did he buy then? -
fxchow:
forHi,
Can someone help to solve this problem. TIA
Allen, Raymond and Tom ran at a speed of 5km/h, 6km/h and 7km/h respectively.
They ran along the same route and started at 6.00 am, 6.30 am and 7.00 am respectively.
When Raymond passed Allen, he gave Allen a message to pass to Tom.
What time will Tom receive the message?
Hi,
At 7am, Allen already travelled (5x1)km. Need to calculate time for Tom catch up this dist.
Time for Tom to catch up = 5km/ (Speed of Tom - Speed of Allen)
= 5/(7-5) = 2.5hrs.
Tom will pass Allen at 9.30am ...is the time Allen passes the message to him -
Denise:
Hi,ack bought some pens and erasers for a total of $100.10.
He spent $9.10 more on the pens than the erasers.
Each pen costs $3.70 more than each eraser.
Jack bought 6 times more ereasers than pens. How much does each pen cost?
How many pens and how erasers did he buy then?
Qty:
Pens : 1 unit
Erasers : 7 units
Cost:
Pens : 1 part +$3.70
Eraser : 1 part
Value :
Pens : (1 unit)x(1 part +$3.70)
Erasers : (7 units)x(1 part)
(8 units)(1 part) +(1unit)($3.70) = $100.10
(1 unit)($3.70) - (6 units)(1 part) = $9.10
(14 units)(1 part) = $ 91
(1 unit)(1 part) = $6.50
(8 units)(1 part) = $52
(1 unit)($3.70) = $100.10 - $52 = $48.10
1 unit = 13
No. of pens : 13
No. of erasers : 13 x 7 = 91 -
Ok. I get it. Thank you very much
-
Dharma:
Hi Dharma,
forfxchow:
Hi,
Can someone help to solve this problem. TIA
Allen, Raymond and Tom ran at a speed of 5km/h, 6km/h and 7km/h respectively.
They ran along the same route and started at 6.00 am, 6.30 am and 7.00 am respectively.
When Raymond passed Allen, he gave Allen a message to pass to Tom.
What time will Tom receive the message?
Hi,
At 7am, Allen already travelled (5x1)km. Need to calculate time for Tom catch up this dist.
Time for Tom to catch up = 5km/ (Speed of Tom - Speed of Allen)
= 5/(7-5) = 2.5hrs.
Tom will pass Allen at 9.30am ...is the time Allen passes the message to him
I got it. Thanks so much!
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