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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • D Offline
      Denise
      last edited by

      Jack bought some pens and erasers for a total of $100.10.

      He spent $9.10 more on the pens than the erasers.
      Each pen costs $3.70 more than each eraser.
      Jack bought 6 times more ereasers than pens. How much does each pen cost?

      1 Reply Last reply Reply Quote 0
      • M Offline
        mrswongtuition
        last edited by

        I'm not sure if this is right, but based on my interpretation of the question:


        Quantity of P:E is 1:7
        P [__]
        E [__][__][__][__][__][__][__]

        Price of P & E (in total)
        P [_______][_$9.10_] ````` } Total
        E [_______] ````````````` }$100.10

        By Price:
        $100.10 - $9.10 = $91
        2u -> $91
        1u -> $45.50

        Since there are 7 units of erasers, each unit of erasers will cost $45.50/7 = $6.50

        The price of the pens is $45.50 + $9.10 = $54.60

        Price of pens take away the price of 1 unit of erasers (to find the difference in amount if the same amount of pens & erasers were bought):
        $54.50 - $6.50 = $48.10

        Since each pen is more expensive than each eraser by $3.70,
        $48.10/$3.70 = 13 pens

        To find the price of each pen:
        $54.60/13pens = $4.20

        1 Reply Last reply Reply Quote 0
        • D Offline
          Dharma
          last edited by

          Denise:
          Jack bought some pens and erasers for a total of $100.10.

          He spent $9.10 more on the pens than the erasers.
          Each pen costs $3.70 more than each eraser.
          Jack bought 6 times more ereasers than pens. How much does each pen cost?
          Its correct

          1 Reply Last reply Reply Quote 0
          • D Offline
            Dharma
            last edited by

            mrswongtuition:
            I'm not sure if this is right, but based on my interpretation of the question:
            Sorry ...the answer is right

            1 Reply Last reply Reply Quote 0
            • F Offline
              fxchow
              last edited by

              Hi,


              Can someone help to solve this problem. TIA šŸ˜„

              Allen, Raymond and Tom ran at a speed of 5km/h, 6km/h and 7km/h respectively.
              They ran along the same route and started at 6.00 am, 6.30 am and 7.00 am respectively.
              When Raymond passed Allen, he gave Allen a message to pass to Tom.
              What time will Tom receive the message?

              1 Reply Last reply Reply Quote 0
              • D Offline
                Denise
                last edited by

                ack bought some pens and erasers for a total of $100.10.

                He spent $9.10 more on the pens than the erasers.
                Each pen costs $3.70 more than each eraser.
                Jack bought 6 times more ereasers than pens. How much does each pen cost?
                How many pens and how erasers did he buy then?

                1 Reply Last reply Reply Quote 0
                • D Offline
                  Dharma
                  last edited by

                  fxchow:
                  Hi,


                  Can someone help to solve this problem. TIA šŸ˜„

                  Allen, Raymond and Tom ran at a speed of 5km/h, 6km/h and 7km/h respectively.
                  They ran along the same route and started at 6.00 am, 6.30 am and 7.00 am respectively.
                  When Raymond passed Allen, he gave Allen a message to pass to Tom.
                  What time will Tom receive the message?
                  for

                  Hi,

                  At 7am, Allen already travelled (5x1)km. Need to calculate time for Tom catch up this dist.

                  Time for Tom to catch up = 5km/ (Speed of Tom - Speed of Allen)
                  = 5/(7-5) = 2.5hrs.

                  Tom will pass Allen at 9.30am ...is the time Allen passes the message to him

                  1 Reply Last reply Reply Quote 0
                  • D Offline
                    Dharma
                    last edited by

                    Denise:
                    ack bought some pens and erasers for a total of $100.10.

                    He spent $9.10 more on the pens than the erasers.
                    Each pen costs $3.70 more than each eraser.
                    Jack bought 6 times more ereasers than pens. How much does each pen cost?
                    How many pens and how erasers did he buy then?
                    Hi,

                    Qty:
                    Pens : 1 unit
                    Erasers : 7 units

                    Cost:
                    Pens : 1 part +$3.70
                    Eraser : 1 part

                    Value :
                    Pens : (1 unit)x(1 part +$3.70)
                    Erasers : (7 units)x(1 part)

                    (8 units)(1 part) +(1unit)($3.70) = $100.10
                    (1 unit)($3.70) - (6 units)(1 part) = $9.10

                    (14 units)(1 part) = $ 91
                    (1 unit)(1 part) = $6.50
                    (8 units)(1 part) = $52

                    (1 unit)($3.70) = $100.10 - $52 = $48.10
                    1 unit = 13

                    No. of pens : 13
                    No. of erasers : 13 x 7 = 91

                    1 Reply Last reply Reply Quote 0
                    • D Offline
                      Denise
                      last edited by

                      Ok. I get it. Thank you very much

                      1 Reply Last reply Reply Quote 0
                      • F Offline
                        fxchow
                        last edited by

                        Dharma:
                        fxchow:

                        Hi,


                        Can someone help to solve this problem. TIA šŸ˜„

                        Allen, Raymond and Tom ran at a speed of 5km/h, 6km/h and 7km/h respectively.
                        They ran along the same route and started at 6.00 am, 6.30 am and 7.00 am respectively.
                        When Raymond passed Allen, he gave Allen a message to pass to Tom.
                        What time will Tom receive the message?

                        for

                        Hi,

                        At 7am, Allen already travelled (5x1)km. Need to calculate time for Tom catch up this dist.

                        Time for Tom to catch up = 5km/ (Speed of Tom - Speed of Allen)
                        = 5/(7-5) = 2.5hrs.

                        Tom will pass Allen at 9.30am ...is the time Allen passes the message to him

                        Hi Dharma,

                        I got it. Thanks so much!

                        1 Reply Last reply Reply Quote 0

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