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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • M
      mrswongtuition
      last edited by

      I'm not sure if this is right, but based on my interpretation of the question:


      Quantity of P:E is 1:7
      P [__]
      E [__][__][__][__][__][__][__]

      Price of P & E (in total)
      P [_______][_$9.10_] ````` } Total
      E [_______] ````````````` }$100.10

      By Price:
      $100.10 - $9.10 = $91
      2u -> $91
      1u -> $45.50

      Since there are 7 units of erasers, each unit of erasers will cost $45.50/7 = $6.50

      The price of the pens is $45.50 + $9.10 = $54.60

      Price of pens take away the price of 1 unit of erasers (to find the difference in amount if the same amount of pens & erasers were bought):
      $54.50 - $6.50 = $48.10

      Since each pen is more expensive than each eraser by $3.70,
      $48.10/$3.70 = 13 pens

      To find the price of each pen:
      $54.60/13pens = $4.20

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      • D
        Dharma
        last edited by

        Denise:
        Jack bought some pens and erasers for a total of $100.10.

        He spent $9.10 more on the pens than the erasers.
        Each pen costs $3.70 more than each eraser.
        Jack bought 6 times more ereasers than pens. How much does each pen cost?
        Its correct

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        • D
          Dharma
          last edited by

          mrswongtuition:
          I'm not sure if this is right, but based on my interpretation of the question:
          Sorry ...the answer is right

          1 Reply Last reply
          Reply Quote 0
          • F
            fxchow
            last edited by

            Hi,


            Can someone help to solve this problem. TIA 😄

            Allen, Raymond and Tom ran at a speed of 5km/h, 6km/h and 7km/h respectively.
            They ran along the same route and started at 6.00 am, 6.30 am and 7.00 am respectively.
            When Raymond passed Allen, he gave Allen a message to pass to Tom.
            What time will Tom receive the message?

            1 Reply Last reply
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            • D
              Denise
              last edited by

              ack bought some pens and erasers for a total of $100.10.

              He spent $9.10 more on the pens than the erasers.
              Each pen costs $3.70 more than each eraser.
              Jack bought 6 times more ereasers than pens. How much does each pen cost?
              How many pens and how erasers did he buy then?

              1 Reply Last reply
              Reply Quote 0
              • D
                Dharma
                last edited by

                fxchow:
                Hi,


                Can someone help to solve this problem. TIA 😄

                Allen, Raymond and Tom ran at a speed of 5km/h, 6km/h and 7km/h respectively.
                They ran along the same route and started at 6.00 am, 6.30 am and 7.00 am respectively.
                When Raymond passed Allen, he gave Allen a message to pass to Tom.
                What time will Tom receive the message?
                for

                Hi,

                At 7am, Allen already travelled (5x1)km. Need to calculate time for Tom catch up this dist.

                Time for Tom to catch up = 5km/ (Speed of Tom - Speed of Allen)
                = 5/(7-5) = 2.5hrs.

                Tom will pass Allen at 9.30am ...is the time Allen passes the message to him

                1 Reply Last reply
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                • D
                  Dharma
                  last edited by

                  Denise:
                  ack bought some pens and erasers for a total of $100.10.

                  He spent $9.10 more on the pens than the erasers.
                  Each pen costs $3.70 more than each eraser.
                  Jack bought 6 times more ereasers than pens. How much does each pen cost?
                  How many pens and how erasers did he buy then?
                  Hi,

                  Qty:
                  Pens : 1 unit
                  Erasers : 7 units

                  Cost:
                  Pens : 1 part +$3.70
                  Eraser : 1 part

                  Value :
                  Pens : (1 unit)x(1 part +$3.70)
                  Erasers : (7 units)x(1 part)

                  (8 units)(1 part) +(1unit)($3.70) = $100.10
                  (1 unit)($3.70) - (6 units)(1 part) = $9.10

                  (14 units)(1 part) = $ 91
                  (1 unit)(1 part) = $6.50
                  (8 units)(1 part) = $52

                  (1 unit)($3.70) = $100.10 - $52 = $48.10
                  1 unit = 13

                  No. of pens : 13
                  No. of erasers : 13 x 7 = 91

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                  • D
                    Denise
                    last edited by

                    Ok. I get it. Thank you very much

                    1 Reply Last reply
                    Reply Quote 0
                    • F
                      fxchow
                      last edited by

                      Dharma:
                      fxchow:

                      Hi,


                      Can someone help to solve this problem. TIA 😄

                      Allen, Raymond and Tom ran at a speed of 5km/h, 6km/h and 7km/h respectively.
                      They ran along the same route and started at 6.00 am, 6.30 am and 7.00 am respectively.
                      When Raymond passed Allen, he gave Allen a message to pass to Tom.
                      What time will Tom receive the message?

                      for

                      Hi,

                      At 7am, Allen already travelled (5x1)km. Need to calculate time for Tom catch up this dist.

                      Time for Tom to catch up = 5km/ (Speed of Tom - Speed of Allen)
                      = 5/(7-5) = 2.5hrs.

                      Tom will pass Allen at 9.30am ...is the time Allen passes the message to him

                      Hi Dharma,

                      I got it. Thanks so much!

                      1 Reply Last reply
                      Reply Quote 0
                      • T
                        tianzhu
                        last edited by

                        Other than Guess and Check, what are the other alternatives to solve this problem?


                        Annie wrote her mother’s age followed by her own age to form a 4-digit number.She used the difference between their ages to subtract from the 4-digit number. Then Annie obtained the number 4489.What was Annie’s age ? (RGPS P6 Prelim 2008 Q47)

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