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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • C Offline
      Concerndad
      last edited by

      (6r-7t)(3q-2s)+(2s-3q)(3r-2t)

      =(6r-7t)(3q-2s)-(3q-2s)(3r-2t)
      =(3q-2s)[(6r-7t)-(3r-2t)]
      =(3q-2s)(6r-7t-3r+2t)
      =(3q-2s)(3r-5t)

      Rgds,
      Concerndad

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      • S Offline
        suiyuan
        last edited by

        Secondary Two Maths


        Hi

        Solve this equation
        (x-2)^2 = 3(2x-3)(2-x)

        (x-2)^2 means (x-2) to the power of 2.

        Please help.

        Thank you.

        1 Reply Last reply Reply Quote 0
        • PiggyLalalaP Offline
          PiggyLalala
          last edited by

          suiyuan:
          Secondary Two Maths


          Hi

          Solve this equation
          (x-2)^2 = 3(2x-3)(2-x)

          (x-2)^2 means (x-2) to the power of 2.

          Please help.

          Thank you.
          (x-2)^2 = 3(2x-3)(2-x)
          (x-2)^2 = -3(2x-3)(x-2)
          (x-2)^2 + 3(2x-3)(x-2) = 0 ( note: (2-x) = -(x-2)
          (x-2)[(x-2) + 3(2x-3)] = 0
          (x-2)[ x- 2 + 6x -9] = 0
          (x-2)( 7x - 11) = 0
          x- 2 = 0 or 7x - 11 = 0
          x = 2 or 11/7

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          • F Offline
            FrekiWang
            last edited by

            suiyuan:
            Secondary Two Maths


            Hi

            Solve this equation
            (x-2)^2 = 3(2x-3)(2-x)

            (x-2)^2 means (x-2) to the power of 2.

            Please help.

            Thank you.
            (x-2)^2-3(2x-3)(2-x)=0
            (x-2)^2+3(2x-3)(x-2)=0 (note that -(2-x)=+(x-2))
            (x-2)[(x-2)+3(2x-3)]=0
            (x-2)(7x-11)=0
            x=2 or x=11/7

            1 Reply Last reply Reply Quote 0
            • J Offline
              JadeDry
              last edited by

              hometutors.sg:
              JadeDry:

              I currently use \"New Syllabus Mathematics\" (8th Grade) books, and would appreciate if you could recommend additional good quality publications.


              Thanks in advance.

              A good tutor / mentor would be able to select what is good for the student.

              Thank you for your time.

              I have just finished:

              Secondary one Mathematics Tutor: 1A and 1B.

              Shinglee New Syllabus Mathematics 6th edition 1

              and Singlee Mathematics Workbook 1.

              I am homeschooled and have been studying singapore math from 1st grade, since my parents are my teachers I would like to see what you people think I should get for 8th Grade.

              Thank you in advance for your assistance.

              1 Reply Last reply Reply Quote 0
              • S Offline
                suiyuan
                last edited by

                Sec Two Maths


                1) Given that x^2 = 5x – 1, find the value of 2x^4 + 2/x^4

                2) a)Factorise 2x^10 – 13x^5 -15 completely.
                b)Factorise 10x^10y – 65x^5y-75y

                Note a) ^2 means to the power of 2 b) 2/x^4 means 2 divided by x^4

                Please help.

                Thank you

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                • CoffeeCatC Offline
                  CoffeeCat
                  last edited by

                  suiyuan:
                  Sec Two Maths


                  1) Given that x^2 = 5x – 1, find the value of 2x^4 + 2/x^4

                  2) a)Factorise 2x^10 – 13x^5 -15 completely.
                  b)Factorise 10x^10y – 65x^5y-75y

                  Note a) ^2 means to the power of 2 b) 2/x^4 means 2 divided by x^4

                  Please help.

                  Thank you
                  Do you happen to be from some IP school or sth?
                  Your teacher probably koped qns 1 from SMO.

                  Qns 1)
                  Lousy Method : solve for x, substitute and torture yourself in the process.
                  Proper Method : divide the quadratic equation by x throughout to get
                  x + 1/x = 5
                  You will get x^2 + 1/x^2 = 23 by squaring the above.
                  Repeat the process one more time.
                  Final ans should be 1054 if I have no calculation error.

                  Qns 2a)
                  Notice 10 is twice that of 5. hence imagine you substitute y=x^5. You will reduce the problem to factorising a quadratic expression.

                  Qns 2b)
                  Ambiguous.......Please use brackets.
                  10x^10y means 10x^(10y) or 10(x^10)y

                  Since it's part b, i will assume the latter.
                  First extract common factors from all terms, which is just 5y. After that what you have should be part a.

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                  • J Offline
                    JadeDry
                    last edited by

                    Hello again, I have a problem that I am unsure about:


                    Simplify the following expression:

                    3/4((x squared)(y)) X 5/9((x)(z cubed)) / ((20/9)(x quadrupled)(y squared)(z))

                    These are my workings:
                    3/4((x squared)(y)) X 5/9((x)(z cubed))=

                    15/36((x cubed)(y)(z cubed))


                    15/36((x cubed)(y)(z cubed)) / ((20/9)(x quadrupled)(y squared)(z))=

                    3(Z squared) / 16(xy)

                    Are my calculations correct?

                    On a side note, is Z cubed/ Z= Z squared or Z cubed?

                    Thanks in advance.

                    1 Reply Last reply Reply Quote 0
                    • S Offline
                      suiyuan
                      last edited by

                      Sec Two Maths


                      Find the smallest possible value of the expression 3x^2 + 27y^2+5z^2-18xy-30z+125.

                      Note a) ^2 means to the power of 2

                      Please help.

                      Thank you

                      1 Reply Last reply Reply Quote 0
                      • F Offline
                        FrekiWang
                        last edited by

                        suiyuan:
                        Sec Two Maths


                        Find the smallest possible value of the expression 3x^2 + 27y^2+5z^2-18xy-30z+125.

                        Note a) ^2 means to the power of 2

                        Please help.

                        Thank you
                        Note that
                        3x^2-18xy+27y^2=3(x^2-6xy+9y^2)=3(x-3y)^2
                        5z^2-30z=5(z^2-6z)=5(z^2-6z+9-9)=5(z^2-6z+9)-45=5(z-3)^2-45

                        So the original express is
                        (3x^2-18xy+27y^2)+(5z^2-30z)+125
                        =3(x-3y)^2+5(z-3)^2-45+125
                        =3(x-3y)^2+5(z-3)^2+80

                        Since the square of any number is non-negative (0 is the smallest possible), the minimum value of the whole expression is 80.

                        PS: A bit too much for a sec 2 student, probably from one of the top schools?

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