Tutor MathsGuru: Ask me for your burning Maths questions!

[MathIzzzFun]

Superbugs:

To MathIzzzFun


Thank you for all the solutions! Appreciate it that you can reply me with the solutions of the other 2 questions. Sorry I am not able to upload the diagram and have incoporated the missing part for the other question.

Btw --> Are you currently a Maths Teacher?

Hi

I have provided the solution for the ratio question. As for the overlapping squares, I can't confirm the configuration so I am not able to provide the solution. If the diagram is such that the small square is inside the medium square and the medium square is inside the big square, then the shaded area is 12/25 or 48% of the big square.

I have pm you.

cheers.

[Superbugs]

MathIzzzFun:

Superbugs:

P5 Question:


The ratio of the amount of money Jenny had to the amount of money Siti had was 3:4. The next day, their parent gave each of them some money. Siti received twice as much as Jenny. The ratio then became 5:8. If both girls had a total of $70 at first, how much did Siti receive?

Pls help.

Hi

http://i56.tinypic.com/2v0jvus.jpg\">



cheers.

I dont get the part on the receive from parents. Why must 1u+6 multiply by 8 and why 10u + 40 = 8u +48? Appreciate your reply soon. Tks

[Superbugs]

MathIzzzFun:

Superbugs:

To MathIzzzFun


Thank you for all the solutions! Appreciate it that you can reply me with the solutions of the other 2 questions. Sorry I am not able to upload the diagram and have incoporated the missing part for the other question.

Btw --> Are you currently a Maths Teacher?

Hi

I have provided the solution for the ratio question. As for the overlapping squares, I can't confirm the configuration so I am not able to provide the solution. If the diagram is such that the small square is inside the medium square and the medium square is inside the big square, then the shaded area is 12/25 or 48% of the big square.

I have pm you.

cheers.

Wow impressive. Without the digram you are still able to solve it within such short span of time. This is the right answer but how to get 12/25 or 48% of the big square?

[MathIzzzFun]

Superbugs:

MathIzzzFun:

[quote=\"Superbugs\"]P5 Question:


The ratio of the amount of money Jenny had to the amount of money Siti had was 3:4. The next day, their parent gave each of them some money. Siti received twice as much as Jenny. The ratio then became 5:8. If both girls had a total of $70 at first, how much did Siti receive?

Pls help.

Hi

http://i56.tinypic.com/2v0jvus.jpg\">

cheers.

I dont get the part on the receive from parents. Why must 1u+6 multiply by 8 and why 10u + 40 = 8u +48? Appreciate your reply soon. Tks[/quote]Hi

Jenny and Siti received money in the ratio of 1:2 = 5 units : 10 units
Originally, Jenny had 30, Siti had 40

So, total that Jenny had = 5 units + 30 = 5 x (1 unit + 6) --- (A)
total that Siti had = 10 units + 40 ---- (B)

Also given is : after receiving the money from their parent, the ratio becomes Jenny : Siti = 5 : 8

From (A), 1 share = 1 unit + 6, so 8 shares = 8 x (1 unit + 6) = 8 units + 48

so, (B) becomes 10 units + 40 = 8 units + 48

cheers.

[MathIzzzFun]

Superbugs:

MathIzzzFun:

[quote=\"Superbugs\"]To MathIzzzFun


Thank you for all the solutions! Appreciate it that you can reply me with the solutions of the other 2 questions. Sorry I am not able to upload the diagram and have incoporated the missing part for the other question.

Btw --> Are you currently a Maths Teacher?

Hi

I have provided the solution for the ratio question. As for the overlapping squares, I can't confirm the configuration so I am not able to provide the solution. If the diagram is such that the small square is inside the medium square and the medium square is inside the big square, then the shaded area is 12/25 or 48% of the big square.

I have pm you.

cheers.

Wow impressive. Without the digram you are still able to solve it within such short span of time. This is the right answer but how to get 12/25 or 48% of the big square?[/quote]Hi

small square : medium square = 1 : 5
medium square : big square = 3 : 5

equalize the shares for medium square and we have

small square : medium square : big square = 3u : 15u : 25u
shaded area is medium square - small square = 15u - 3u = 12u
total area = 25u (basically area of big square)

So, shaded area = 12u/25u = 48%

cheers.

[Superbugs]

Hi


I have provided the solution for the ratio question. As for the overlapping squares, I can’t confirm the configuration so I am not able to provide the solution. If the diagram is such that the small square is inside the medium square and the medium square is inside the big square, then the shaded area is 12/25 or 48% of the big square.

I have pm you.

cheers.[/quote]

Wow impressive. Without the digram you are still able to solve it within such short span of time. This is the right answer but how to get 12/25 or 48% of the big square?[/quote]

Hi

small square : medium square = 1 : 5
medium square : big square = 3 : 5

equalize the shares for medium square and we have

small square : medium square : big square = 3u : 15u : 25u
shaded area is medium square - small square = 15u - 3u = 12u
total area = 25u (basically area of big square)

So, shaded area = 12u/25u = 48%



My dau got up to 3u : 15u : 25u and she got the difference at 12u. However, she has forgotten to express as a percentage.

Thanks a lot for your solution. Really appreciate it.

[MathIzzzFun]

Superbugs:

My dau got up to 3u : 15u : 25u and she got the difference at 12u. However, she has forgotten to express as a percentage.

Thanks a lot for your solution. Really appreciate it.

Hi

u r welcome

cheers.

[Superbugs]

P5 Question:


Before a game, Azmi and Peiqin had the same no. of pitcure cards. During the first round, Azmi lost 12 of his picture cards to Peiqin. During the second round, Peiqin won 16 picture cards from Azmi. In the end, Peiqin had 3 times as many picture cards as Azmi.

a) How many more picture cards did Peiqin have in the end?
b) How many pitcure cards did both of them have in all?

a)
Azmi= 1u
Peiqin=3u+28

2u=28
1u=14
3u+28=3x14+28=56 picture cards

b) 4u+28=84 picture cards

Part a) is correct but for part b) the answer sheet shows 112? Appreciate help on part b) pls. Tks

[Superbugs]

P5 question:

Mr Tan had some oranges for sale. The first customer bought 1/2 of the oranges and received 8 oranges free. The second customer bought 45% of the remaining and received 5 free oranges free. The third customer bought 70% of the remaining oranges and received 3 oranges free. Mr Tan then had 1 dozen oranges left. How many oranges did he have at first?

This is what I gathered from the question but I can’t solve it, pls help:
1st Customer bought =1/2u+ 8 oranges
Remaining =1/2u- 8 oranges
2nd Customer bought = 45% of (1/2u-8 oranges)
Remaining = 55% of (1/2u-8oranges)
3rd Customer bought = 70% of 55% of (1/2u-8oranges)
Remaining = 30% of 55% of (1/2u-8 oranges)= 12 oranges
1u=16
Pls help as I am unable to get d answer. Tks

[MathIzzzFun]

Superbugs:

P5 question:

Mr Tan had some oranges for sale. The first customer bought 1/2 of the oranges and received 8 oranges free. The second customer bought 45% of the remaining and received 5 free oranges free. The third customer bought 70% of the remaining oranges and received 3 oranges free. Mr Tan then had 1 dozen oranges left. How many oranges did he have at first?

This is what I gathered from the question but I can't solve it, pls help:
1st Customer bought =1/2u+ 8 oranges
Remaining =1/2u- 8 oranges
2nd Customer bought = 45% of (1/2u-8 oranges)
Remaining = 55% of (1/2u-8oranges)
3rd Customer bought = 70% of 55% of (1/2u-8oranges)
Remaining = 30% of 55% of (1/2u-8 oranges)= 12 oranges
1u=16
Pls help as I am unable to get d answer. Tks

Hi

Work backwards to get to the initial number.

Steps:
Quantity Left ---- Quantity Bought
Initial ---- 1st: ½ Initial + 8

½ initial–8=R1 ---- 2nd : 45% of R1 + 5

55% of R1-5=R2 ---- 3rd: 70% of R2 + 3

30% of R2- 3 = 12

work backwards,

30% of R2 = 15, R2 = 15/3 x 10 = 50

55% of R1 – 5 = R2 = 50, R1 = 55/55 x 100 = 100

½ initial -8 = R1 = 100, Initial = 108 x 2 = 216

cheers.