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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      turquoise
      last edited by

      Thanks Dharma.

      1 Reply Last reply Reply Quote 0
      • D Offline
        Dharma
        last edited by

        turquoise:
        Thanks Dharma.

        No pbm

        1 Reply Last reply Reply Quote 0
        • F Offline
          faith2u
          last edited by

          Hi everyone, I need help in the below questions…thanks in advance.


          1). In a Primary school of 1960 students, ¼ of the boys and 1/5 of the
          girls make up 400 children. How many girls are there? (Ans : 1800)

          2). A carp cost $12. A goldfish cost 75% less than a carp. Ramli bought
          some carps and goldfish for $198. 60% of the fish he bought were
          goldfish.
          (a). how many carps did he buy? (Ans : 12)
          (b). how many goldfish did he buy? (Ans : 18)
          ©. how much more money did he spend on the carps than goldfish?
          (Ans : $90)

          3). Mr Huang knocked 160 nails along the perimeter of the ceiling of a
          function room measuring 20m long by 12m wide. The distance
          between each nail was equal. He hung 3 balloons on each nail.
          (a). how many nails were knocked along the width of the ceiling?
          (ans : 31 nails)
          (b). how many balloons did he buy in all if he has 20 left? (ans : 500)

          1 Reply Last reply Reply Quote 0
          • F Offline
            faith2u
            last edited by

            Hi everyone, here is another set of question which I need help…thks.


            1). Uncle Seng bought some fruits. 1/3 of the fruits were apples, 1/9 of
            them were mangoes and the rest were oranges. The prices of the
            fruits are as shown :
            Apples – 20cents each
            Mangoes – 70cents each
            Oranges – 30cents each
            Uncle Seng spent $15.60 on the apples and mangoes. How much did
            he spend on the oranges? (ans : $18 )

            2). Meili has a total of 20 mangoes and oranges. If she exchanges every
            mango for 3 oranges, she will have 32 oranges. How many oranges
            does she have? (ans : 6).

            3). Tank A and tank B had 48litres and 8litres of water respectively at
            first. Then an equal amount of water was added into each tank. As a
            result, the ratio of the amount of water in tank A to that of tank B
            became 3:1. How much water was added into each tank?

            4). Meimei would be given 20cents for each greeting card she sold. In
            addition, she would get $4 for every 10 greeting cards scold. How
            many cards did she sell if she earned $80?

            1 Reply Last reply Reply Quote 0
            • K Offline
              kitty2
              last edited by

              Please help to solve these 2 problems,thanks


              1)Find the sum of all the odd numbers from 1 to 210


              2)The ratio of the number of horses to the number of cows is 3:8.The number of sheep is twice the number of horses.After 30 cows were sold,1/4 of the remaining animals were cows.What was the total number of sheep and horses?

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              • B Offline
                bwpj2000
                last edited by

                1)Sum of first 2 odd numbers = 1+3 = 4

                Sum of first 3 odd numbers = 1+3+5 = 9
                Therefore sum of the first n odd numbers is n^2
                So sum of first 210 odd numbers is 210^2= 44100

                Not too sure about Q2. :?

                1 Reply Last reply Reply Quote 0
                • D Offline
                  Dharma
                  last edited by

                  bwpj2000:
                  1)Sum of first 2 odd numbers = 1+3 = 4

                  Sum of first 3 odd numbers = 1+3+5 = 9
                  Therefore sum of the first n odd numbers is n^2
                  So sum of first 210 odd numbers is 210^2= 44100

                  Not too sure about Q2. :?
                  Q1 Sum of odd nos. from 1 to 210 = (210/2) x (210/2) = 11025

                  To derive :
                  Sum of all nos. from 1 to 210 = 105 x 211 = 22155 (210 x 211)/2
                  Sum of all even nos. from 1 to 210 = 2(1+2+...+104+105) =2(105 x 106)/2 = 11130
                  So, (1+3 + ...+ 209) = 22155 - 11130 = 11025

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                  • B Offline
                    bwpj2000
                    last edited by

                    Oops. :oops:

                    Sorry, my bad.

                    1 Reply Last reply Reply Quote 0
                    • K Offline
                      kitty2
                      last edited by

                      [

                      To derive :
                      Sum of all nos. from 1 to 210 = 105 x 211 = 22155 (210 x 211)/2
                      Sum of all even nos. from 1 to 210 = 2(1+2+...+104+105) =2(105 x 106)/2 = 11130
                      So, (1+3 + ...+ 209) = 22155 - 11130 = 11025[/quote]

                      Thanks for the answer,where do you get the 105 from? :?:

                      1 Reply Last reply Reply Quote 0
                      • J Offline
                        john.09525316
                        last edited by

                        bwpj2000:
                        1)Sum of first 2 odd numbers = 1+3 = 4

                        Sum of first 3 odd numbers = 1+3+5 = 9
                        Therefore sum of the first n odd numbers is n^2
                        So sum of first 210 odd numbers is 210^2= 44100

                        Not too sure about Q2. :?
                        In fact your approach is good, except the last part should be
                        n= 210/2 = 105

                        Therefore, the answer is 105*105 = 11025

                        1 Reply Last reply Reply Quote 0

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