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    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
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    • F Offline
      FrekiWang
      last edited by

      leeven:
      1. A number is a called palindrome if it reads the same from left and from right. example 130031 is a palindrome. writing all palindroms we get 1,2,3,4,5,....9,11,22,,....what is the 2007th palindrome. do you have formula to find the nth palindrome.


      please help
      First of all, I do not believe this is a secondary school question. The standard of this problem is for competition at upper secondary school level, e.g. SMO (Senior)

      So, here is my solution, assuming you have some basic knowledge about competition mathematics.

      There are 9 1-digit palindroms.
      There are 9 2-digit palindroms.
      For 3-digit palindroms. You can choose a number from 0 to 9 (10numbers here) and insert into a 2-digit palindrom to form a 3-digit palindrom. Therefore 9 2-digit palindroms can produce 9 x 10 = 90 3-digit palindroms.
      For 4-digit palindroms. You can choose a number from 00, 11 to 99(10numbers here) and insert into a 2-digit palindrom to form a 4-digit palindrom.
      Therefore 9 2-digit palindroms can produce 9 x 10 = 90 4-digt palindroms.

      Similarly, insert a number from 0 ... 9 into a 4-digit palindrom to form a 5-digit palindroms, there are 90 x 10 = 900 of them.
      Insert a number from 00 ... 99 into a 4-digit palindrom to form a 6-digit palindroms, there are 90 x 10 = 900 of them.

      Now we have 9 + 9 + 90 + 90 + 900 + 900 = 1998 palindroms in totoal, we need 9 more.
      Let's start counting the 7-digit palindroms from the least: (inserting 0..9 into 100001)
      1000001, 1001001, 1002001, 1003001, 1004001, 1005001, 1006001, 1007001, 1008001 - this is the 9th, so the answer is 1008001.

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      • H Offline
        Herbie
        last edited by

        hi how to solve this qqn


        a team of 8 men can build 3 swimming pools in 5 weeks. Find the no. Of men required to build 6 swimming pools in 4 weeks? Tq

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        • T Offline
          tianzhu
          last edited by

          Herbie:
          hi how to solve this qqn


          a team of 8 men can build 3 swimming pools in 5 weeks. Find the no. Of men required to build 6 swimming pools in 4 weeks? Tq
          Hi

          One way is to use compound units which in this question is \"man-weeks\"

          3 swimming pool ------ 8*5 ------ 40 man-weeks
          6 swimming pools ------ 2*40 ------- 80 man-weeks

          80/4 ------ 20 men

          Best wishes

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          • H Offline
            Herbie
            last edited by

            hi tianzhu, many thanks!


            I hv another qn.

            15 men working 8 hours a day can build a bridge in 30 days.
            How long will 9 men working 8 hours a day take to buiild the same ridge assuming that the rate at which they work remains unchanged? My ans is 50 days.

            B. How many hours a day must 25 men work to build the same bridhe in 16 days!

            Tq

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            • T Offline
              tianzhu
              last edited by

              Herbie:

              15 men working 8 hours a day can build a bridge in 30 days.
              How long will 9 men working 8 hours a day take to buiild the same ridge assuming that the rate at which they work remains unchanged? My ans is 50 days.

              B. How many hours a day must 25 men work to build the same bridhe in 16 days!
              Hi

              Your answer of 50 days for part A is right.

              For part B,
              1 bridge ------ 15*30*8 ------- 3600 man-hours

              Number of men*number of days*number of hours ------- 3600 man-hours

              25*16*h ------- 3600 where h refers to the number of hours the men must work.

              h ------- 9 hours.

              Best wishes

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              • T Offline
                tutor4kids
                last edited by

                Hi, thank you for the solution.

                Could you have me with the following question?

                In the diagram below, ACB is a tangent to the circle at point C. This tangent is parallel to the line FE. Points F, G and H lie on the circle.
                i) Prove that (EC)(CG) = (CF)^2.
                ii) The line FE is extended to meet the circle at H. Prove (FE)(EH) = CF^2 - EC^2.

                http://i52.tinypic.com/33zd7hv.jpg\">

                Thank you.

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                • F Offline
                  FrekiWang
                  last edited by

                  (i) (this is a very standard A Maths Question, Similarity is one of the standard approaches)

                  In FEC and GFC,
                  AngleEFC=AngleFCA=AngleFGC (hopefully you know why)
                  AngleFCE=AngeGCF
                  Thus FEC is similar to GFC
                  FE/GF=EC/FC=FC/GC
                  Cross-multiply 2nd and 3rd, we have EC x GC = FC^2(proven)

                  (ii) (usually (ii) is related to (i))
                  RHS=CF^2-EC^2
                  =EC x GC - EC^2 (from part (i))
                  =EC x (GC - EC)
                  =EC x GE
                  =FE x EH (intersecting chords thereom)
                  =LHS (proven)
                  Seriously, part(ii) is much easier. In the exam/test, if you cant prove part(i), you can always assume part(i) result and use it to prove part(ii)

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                  • T Offline
                    tutor4kids
                    last edited by

                    Hi,


                    Thank you very much for the prompt reply! I can understand the solution.
                    Thanks once again.

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                    • F Offline
                      FrekiWang
                      last edited by

                      tutor4kids:
                      Hi,


                      Thank you very much for the prompt reply! I can understand the solution.
                      Thanks once again.
                      Seriously, if you are a home tutor teaching A Maths, I would like to advise that you need more preparation for this topic. A lots of students are having problems in this topic so most likely they are going to ask a lot.

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                      • T Offline
                        tutor4kids
                        last edited by

                        Hi, thanks for the advice. I am not a home tutor for A Maths though, just seeking help on behalf of a friend. Anyway, thanks for your help.

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