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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • C
      Chan09
      last edited by

      Need some help:

      In a test, A,B,C and D scored an average of 73.25marks. D score was 60% of A. A scored 4 marks more than C. B scored 27 marks less than A. Calculate B scores?

      Ans: 63 marks

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      • A
        atutor2001
        last edited by

        Chan09:
        Need some help:

        In a test, A,B,C and D scored an average of 73.25marks. D score was 60% of A. A scored 4 marks more than C. B scored 27 marks less than A. Calculate B scores?

        Ans: 63 marks
        Let me try using ratio.

        60% = 3/5 i.e. D is 3/5 of A

        Ratio of D : A = 3U : 5U
        Ratio of D : A : C = 3U : 5U : (5U-4)
        Ratio of D : A : C : B = 3U : 5U : (5U-4) : (5U-27)

        Total score = 73.25 x 4 = 293

        Total of 3U, 5U, (5U-4) and (5U-27) must be equal to 293

        If we add 4 to (5U-4), it will become 5U
        If we add 27 to (5U-27), it will also become 5U
        Because of 4 & 27 added, the total will be increased to 293+27+4 =324

        Therefore, 3U(D) + 5U(A) + 5U(C with 4 added) + 5U(B with 27 added) = 324

        18U = 324
        U = 18

        B = 5U - 7
        = (5x18) - 27
        = 63

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        • J
          jtparent
          last edited by

          Hi another 2 q to seek ur assistance


          1. Shaoquan had less than 40 cookies. If he packs them in packets of 5, he will have 2 cookies left. If he packs them in packets of 7, he will be short of 3 cookies. How many cookies does he have?

          2. Lee Bin, Vanessa & Sarah had $900 altogether. After Lee Bin spent 3/5 of her money, Vanessa spent 1/2 of her money and Sarah spent 3/7 of her money, the ratio of the amount of money they had left was 2:3:4 respectively. How much did each girl have at 1st?

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          • MathIzzzFunM
            MathIzzzFun
            last edited by

            jtparent:
            Hi another 2 q to seek ur assistance


            1. Shaoquan had less than 40 cookies. If he packs them in packets of 5, he will have 2 cookies left. If he packs them in packets of 7, he will be short of 3 cookies. How many cookies does he have?

            2. Lee Bin, Vanessa & Sarah had $900 altogether. After Lee Bin spent 3/5 of her money, Vanessa spent 1/2 of her money and Sarah spent 3/7 of her money, the ratio of the amount of money they had left was 2:3:4 respectively. How much did each girl have at 1st?
            Hi

            1. If we add 3 more cookies, the total can be packed into packets of 5, and packets of 7 exactly ie the total will be a multiple of both 5 & 7 = 35 (less than 40).

            So, number of cookies = 35 - 3 (since we added 3 cookies) = 32.

            Alternatively, you could also use the listing method to solve.

            2. Amount left:
            Lee Bin = 2u = 2/5 of her money, so initially Lee Bin had 5u
            Vanessa = 3u = 1/2 of her money, so initially Vanessa had 6u
            Sarah = 4u = 4/7 of her money, so initially Sarah had 7u

            Total = 5u + 6u + 7u = 18u = $900, 1u = $50

            Initially,
            Lee Bin had 5 x $50 = $250
            Vanessa had 6 x $50 = $300
            Sarah had 7 x $50 = $350

            cheers.

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            • J
              jtparent
              last edited by

              MathIzzzFun:
              jtparent:

              Hi another 2 q to seek ur assistance


              1. Shaoquan had less than 40 cookies. If he packs them in packets of 5, he will have 2 cookies left. If he packs them in packets of 7, he will be short of 3 cookies. How many cookies does he have?

              2. Lee Bin, Vanessa & Sarah had $900 altogether. After Lee Bin spent 3/5 of her money, Vanessa spent 1/2 of her money and Sarah spent 3/7 of her money, the ratio of the amount of money they had left was 2:3:4 respectively. How much did each girl have at 1st?

              Hi

              1. If we add 3 more cookies, the total can be packed into packets of 5, and packets of 7 exactly ie the total will be a multiple of both 5 & 7 = 35 (less than 40).

              So, number of cookies = 35 - 3 (since we added 3 cookies) = 32.

              Alternatively, you could also use the listing method to solve.

              2. Amount left:
              Lee Bin = 2u = 2/5 of her money, so initially Lee Bin had 5u
              Vanessa = 3u = 1/2 of her money, so initially Vanessa had 6u
              Sarah = 4u = 4/7 of her money, so initially Sarah had 7u

              Total = 5u + 6u + 7u = 18u = $900, 1u = $50

              Initially,
              Lee Bin had 5 x $50 = $250
              Vanessa had 6 x $50 = $300
              Sarah had 7 x $50 = $350

              cheers.


              Tks so much.

              The listing method for q1 is it call guess & check method?

              BTW re u a tutor / teacher?

              1 Reply Last reply
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              • MathIzzzFunM
                MathIzzzFun
                last edited by

                jtparent:
                MathIzzzFun:

                [quote=\"jtparent\"]Hi another 2 q to seek ur assistance


                1. Shaoquan had less than 40 cookies. If he packs them in packets of 5, he will have 2 cookies left. If he packs them in packets of 7, he will be short of 3 cookies. How many cookies does he have?

                2. Lee Bin, Vanessa & Sarah had $900 altogether. After Lee Bin spent 3/5 of her money, Vanessa spent 1/2 of her money and Sarah spent 3/7 of her money, the ratio of the amount of money they had left was 2:3:4 respectively. How much did each girl have at 1st?

                Hi

                1. If we add 3 more cookies, the total can be packed into packets of 5, and packets of 7 exactly ie the total will be a multiple of both 5 & 7 = 35 (less than 40).

                So, number of cookies = 35 - 3 (since we added 3 cookies) = 32.

                Alternatively, you could also use the listing method to solve.

                2. Amount left:
                Lee Bin = 2u = 2/5 of her money, so initially Lee Bin had 5u
                Vanessa = 3u = 1/2 of her money, so initially Vanessa had 6u
                Sarah = 4u = 4/7 of her money, so initially Sarah had 7u

                Total = 5u + 6u + 7u = 18u = $900, 1u = $50

                Initially,
                Lee Bin had 5 x $50 = $250
                Vanessa had 6 x $50 = $300
                Sarah had 7 x $50 = $350

                cheers.


                Tks so much.

                The listing method for q1 is it call guess & check method?

                BTW re u a tutor / teacher?[/quote]Hi

                We can use the listing or systematic listing method -

                List the multiples of 5 & 7 and add the remainders as follows:

                multiple of 5 : 5 , 10, 15, 20, 25, 30, 35, 40

                total = +2 (cos left 2 cookies) : 7, 12, 17, 22, 27, 32, 37

                multiple of 7 : 7, 14, 21, 28, 35

                total = +4 (cos short of 3 cookies to form another group of 7= remainder 4): 11, 18, 25, 32, 39

                By comparing the totals of both, we can see that there is only one match = 32.

                cheers.

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                • 2
                  2DMommy
                  last edited by

                  Need help with these two percentage questions :


                  1) The ratio of Alan’s total marks to that of Benji’s total marks in their Mid-Year Examination
                  was 4 : 5 . Alan’s marks increased by 50% in the End-of-Year Examination. By what
                  percentage must Benij’s marks be increased so that their total marks would be equal ?


                  2) Timothy had a box of strawberry sweets and pineapple sweets. When he added in 30 strawberry
                  sweets, 20% of the sweets were pineapple sweets. When he added in another 100 pineapple sweets,
                  60% of the sweets were pineapple sweets. How many strawberry\tsweets were there in the container
                  at first ?\t\t\t\t\t\t\t\t\t

                  Thanks !!

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                  • A
                    Andrew Lee
                    last edited by

                    http://i52.tinypic.com/nmzzep.jpg\"> :roll:

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                    • M
                      MadScientist
                      last edited by

                      Here goes…


                      A) [ 5 / (5+9) ] = 35.71% of the circle is shaded.

                      B) 168 * 35.71% = 60 sqcm
                      Since AE = EB, Triangle is an isoceles triangle (ie. two equal sides)
                      And shaded part is 40% of triangle, therefore, 60 sqcm is 40% of triangle.
                      Area of triangle DEC = (100/40) x 60 = 150 sqcm

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                      • A
                        Adam Ma
                        last edited by

                        May I know what level of class this problem comes from?

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