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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • B Offline
      blitz
      last edited by

      Thank you MathIzzzFun....will forward this to my child. 😄

      1 Reply Last reply Reply Quote 0
      • 2 Offline
        2DMommy
        last edited by

        Please help me with these questions again :

        1) A stack of bookmarks was shared among Peter, Tom and Jerry. Peter received 3 more than 50% of the bookmarks. Tom received 5 more than half of the remaining bookmarks. After Peter and Tom had taken their share, Jerry received 50% of the remainder and the last 3 bookmarks. What percentage of the stack of bookmarks did Jerry receive ?\t

        2) Kailing and Jim had a total of $63. Kailing gave 0.3 of her share to Jim. Jim then gave 1/3 of the total amount of money he had to his brother. In the end, all the three children had the same amount of money. How much money did Kailing have at first?\t\t

        Thanks !

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        • MathIzzzFunM Offline
          MathIzzzFun
          last edited by

          2DMommy:
          Please help me with these questions again :

          1) A stack of bookmarks was shared among Peter, Tom and Jerry. Peter received 3 more than 50% of the bookmarks. Tom received 5 more than half of the remaining bookmarks. After Peter and Tom had taken their share, Jerry received 50% of the remainder and the last 3 bookmarks. What percentage of the stack of bookmarks did Jerry receive ?\t

          2) Kailing and Jim had a total of $63. Kailing gave 0.3 of her share to Jim. Jim then gave 1/3 of the total amount of money he had to his brother. In the end, all the three children had the same amount of money. How much money did Kailing have at first?\t\t

          Thanks !
          Hi

          you should be able to solve by working backwards:

          1) Jerry received 50% of the remainder (final) and last 3 bookmarks, so the last 3 bookmarks is also = 50% of final remainder, final remainder = 6 .. from here, you can work backwards to solve .. Total bookmarks = 50, Peter 28, Tom 16, Jerry 6.

          2) this was discussed in an earlier thread - http://www.flickr.com/photos/62167097@N02/6020796670/in/photostream

          cheers.

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          • R Offline
            rainbow75
            last edited by

            Mr Tan drives to work everday .The distance from home to office is 40 km.He was sick one day and he drove 20km/h slower and was 10 minutes late for work.what was his usual speed to work?

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            • MathIzzzFunM Offline
              MathIzzzFun
              last edited by

              rainbow75:
              Mr Tan drives to work everday .The distance from home to office is 40 km.He was sick one day and he drove 20km/h slower and was 10 minutes late for work.what was his usual speed to work?

              Hi

              The solution involved solving of quadratic equation. For P6, the usual way is to use Guess & Check to solve.

              http://i55.tinypic.com/es3slw.jpg\">

              cheers.

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              • R Offline
                rainbow75
                last edited by

                hi mathguru

                thank you for your help.however I still don’t understand what does ‘n’ represent ? please explain more clearly .Thank you.

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                • A Offline
                  atutor2001
                  last edited by

                  rainbow75:
                  Mr Tan drives to work everday .The distance from home to office is 40 km.He was sick one day and he drove 20km/h slower and was 10 minutes late for work.what was his usual speed to work?

                  Hi rainbow 75

                  This question is actually a typical secondary school question for application of algebra. It should not be in P6 paper.

                  I agree with MathIzzFun that for P6, the only way to solve is to use guess and check but the kid would need very good sense of proportion to get the answer as it involves hours and minutes.

                  Just for information, the secondary solving method using algebra is as follows :

                  Let the normal Time needed = T and the normal Speed be S

                  Time = Distance/Speed

                  T = 40/S (for normal situation)
                  T + 1/6 = 40/(S - 20) (when he is sick) so T = 40/(S - 20) - 1/6

                  Now we have expression of T in 2 ways and can compare them to find S :

                  40/S = 40/(S - 20) - 1/6

                  Solving the above is definitely too difficult for normal pr children

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                  • N Offline
                    northernstar
                    last edited by

                    hi rainbow75,


                    i’ve PMed you the solution with another method. feel free to reply if there is any doubt.

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                    • K Offline
                      kwcllf
                      last edited by

                      Please help with the following Maths question:


                      A group of people met at a party. Each person shook hands with everyone else. Mr Li shook hands with 3 times as many men as women. Mrs Li shook hands with 4 times s many men as women. How many men and how many women were there at the party?

                      Thanks!

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                      • Y Offline
                        YumYum
                        last edited by

                        Hi, I need help with these 2 questions:


                        1. Ali has some 50 cent coins and Martin has some $1 coins. Ali has 49 more coins than Martin but has $4.50 less than him. How much money do they have alltogether?

                        2. Joshua counted the number of digits of all the page numbers in a book. He found that a total of 1359 digits were used. How many pages were there in the book? (ans=489)

                        thank you.

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