Q&A - PSLE Math

[wanderlust-alm]

After resignation of members , % of man is 10% ( of the original number ) as 1/4 of 40% is 10%.

After reignation of members, % of woman is 48% ( of original number ) as 80% x 60% ( original % ) is 48%.
hence members who quit is 100-10-48 = 42% ==> 210 members.

Number of woman in the club at first = 60% x 210 / 42 = 300 women
Number of men resigned from club = 30% x 210 / 42 = 150 men.

[pensiveowl]

Nice! - thanks!

wanderlust-alm:

After resignation of members , % of man is 10% ( of the original number ) as 1/4 of 40% is 10%.
After reignation of members, % of woman is 48% ( of original number ) as 80% x 60% ( original % ) is 48%.
hence members who quit is 100-10-48 = 42% ==> 210 members.

Number of woman in the club at first = 60% x 210 / 42 = 300 women
Number of men resigned from club = 30% x 210 / 42 = 150 men.

[raghupavithra]

round off 378.71 to the nearest whole number


1. 376
2. 378
3. 379
4. 380

pls help

[CloudeeDaz]

Hi

need help withthis question

Mdm Zhang packed some beads into 14 small boxes and 15 big boxes. There were equal no of beads in each small box and equal no of beads in each big box. Each big box contained 5 more beads than each small box. 3/8 of the beads were packed in small boxes. How many beads were there in each small box?

thanks

[MathIzzzFun]

CloudeeDaz:

Hi

need help withthis question

Mdm Zhang packed some beads into 14 small boxes and 15 big boxes. There were equal no of beads in each small box and equal no of beads in each big box. Each big box contained 5 more beads than each small box. 3/8 of the beads were packed in small boxes. How many beads were there in each small box?

thanks

Hi

this was discussed in an earlier post..

http://www.flickr.com/photos/62167097@N02/5664739745/in/photostream

cheers.

[CloudeeDaz]

thanks for the link!

[wanderlust-alm]

CloudeeDaz:

Hi

need help withthis question

Mdm Zhang packed some beads into 14 small boxes and 15 big boxes. There were equal no of beads in each small box and equal no of beads in each big box. Each big box contained 5 more beads than each small box. 3/8 of the beads were packed in small boxes. How many beads were there in each small box?

thanks

Each big box has 5 more beads ==> extra beads over the small box ==> 75 beads.

14 small box + 15 small box + 75 beads = total amount of beads ( Y beads )

each small box contain ( 3/8 y ) / 14 beads ==> 3/112 y
Beads in big box = 3/8 y + 3/112 y + 75 beads

hence total number of beads = 3/8 y + ( 3/8 y + 3/112 y + 75 )

Work out to common denominator

42/112 + 42/112 + 3/112 + 75 beads = total number of beads

87/112 + 75 beads = total number of beads

==> 25 /112 = 75 beads
hence 3 / 8 = 126 beads

hence each small box has 126/14 = 9 beads

[wanderlust-alm]

wanderlust-alm:

CloudeeDaz:

Hi

need help withthis question

Mdm Zhang packed some beads into 14 small boxes and 15 big boxes. There were equal no of beads in each small box and equal no of beads in each big box. Each big box contained 5 more beads than each small box. 3/8 of the beads were packed in small boxes. How many beads were there in each small box?

thanks

Each big box has 5 more beads ==> extra beads over the small box ==> 75 beads.

14 small box + 15 small box + 75 beads = total amount of beads ( Y beads )

each small box contain ( 3/8 y ) / 14 beads ==> 3/112 y
Beads in big box = 3/8 y + 3/112 y + 75 beads

hence total number of beads = 3/8 y + ( 3/8 y + 3/112 y + 75 )

Work out to common denominator

42/112 + 42/112 + 3/112 + 75 beads = total number of beads

87/112 + 75 beads = total number of beads

==> 25 /112 = 75 beads
hence 3 / 8 = 126 beads

hence each small box has 126/14 = 9 beads

Thanks for link too. The illustration by units is much clearer . My method is more like the old style although eventually answer still the same but definately easier to view through units . Thanks Too !!

[pixiedust]

Need some help, thanks in advance :


A box contained 50-cent and 20-cent coins in the ratio 2:3.
Some 50-cent coins were taken out and exchanged for 20-cent coins.
The ratio of the number of 50-cent coins to the number of 20-cent coins became 2:7.
Find (a) the total value of money in the box (b) the number of 50-cent coins which were taken to exchange for 20-cent coins.

[acehkr3009]

Let the number of coins taken out (50 cents) and exchange (20 cents) be U numbers.


Before exchange,

50 cents : 20 cents
2 : 3
After the exchange of U numbers of 50 cents with 20 cents,

50 cents = 2 - U
20 cents = 3 + U

New ratio becomes,
2 : 7

So 7 times number of 50 cents = 2 times number of 20 cents

2 X (3 + U) = 7 X (2 - U)
6 + 2U = 14 - 7U
9U = 8
U = 8/9 (fraction)

Now we know each of ratio unit of 50 cents & 20 cents is subdivided into 9 smaller units. Of which, 8 units (or 8 numbers of coins) of 50 cents coins is used to exchange for 8 units of 20 cents coins.

Before the exchange,
Based on the ratio (50 cents: 20 cents) 2:3,
There will be 2 x 9 = 18 number of 50 cents coins
Value of 50 cents coins = 18 x 50 cents = $9
There will be 3 x 9 = 27 number of 20 cents coins
Value of 20 cents coins = 27 x 20 cents = $5.40
Total value at first will be $14.40

After exchanging 8 number of 50 cents with 20 cents,
There will be 18 - 8 = 10 number of 50 cents &
10 number of 50 cents coins: 10 x 50 = $5
There will be 27 + 8 = 35 number of 20 cents.
35 number of 20 cents coins: 35 x 20 = $7
Total value after the exchange = $12.

Hope the above lenghtly solution is correct & acceptable.
Pls advise if there is simpler solutions.
Thanks in advance.