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    Q&A - P4 Math

    Scheduled Pinned Locked Moved Primary 4
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    • C Offline
      chokos
      last edited by

      @ Tianzhu

      Thank you very much.

      1 Reply Last reply Reply Quote 0
      • U Offline
        usaik
        last edited by

        MathIzzzFun:

        Hi

        Find the common factors for 102 and 54...

        54 = 1 x 2 x 3 x 3 x 3 = 6 x 9
        102 = 1 x 2 x 3 x 17 = 6 x 17

        Since each side of W is a whole number, each side = 6 cm, area = 36 cm2
        So, area of V = 17 x 9 = 153 cm2
        V-W= 153 - 36 = 117 cm2

        cheers.
        Hi MathIzzzFun,
        Thank you for the working!
        Regards.

        1 Reply Last reply Reply Quote 0
        • MathIzzzFunM Offline
          MathIzzzFun
          last edited by

          usaik:
          MathIzzzFun:


          Hi

          Find the common factors for 102 and 54...

          54 = 1 x 2 x 3 x 3 x 3 = 6 x 9
          102 = 1 x 2 x 3 x 17 = 6 x 17

          Since each side of W is a whole number, each side = 6 cm, area = 36 cm2
          So, area of V = 17 x 9 = 153 cm2
          V-W= 153 - 36 = 117 cm2

          cheers.

          Hi MathIzzzFun,
          Thank you for the working!
          Regards.

          u r welcome šŸ˜„

          cheers.

          1 Reply Last reply Reply Quote 0
          • P Offline
            pineapple tarts
            last edited by

            hello, can someone help with this pls šŸ˜„


            Ali has 3 times as many stickers as Mohan. If Ali gives 165 stickers to Mohan, he will have ½ as many stickers as Mohan. How many stickers do they have altogether?

            Many thanks in advance.

            1 Reply Last reply Reply Quote 0
            • PiggyLalalaP Offline
              PiggyLalala
              last edited by

              One possible approach: Using units and parts:

              A: M = 3u : 1u = 9u: 3u
              A: M = 1p : 2p = 4p: 8p
              Total remains the same:
              Therefore 12u = 12p, that is u = p
              Therefore (before) A:M = 9u:3u
              (after) A: M = 4u:8u
              Therefore 5u = 165
              u= 33
              Total = 12u = 396 stickers

              1 Reply Last reply Reply Quote 0
              • U Offline
                usaik
                last edited by

                Another possible approach would be using model as below :

                http://i54.tinypic.com/rbjxh3.jpg\">

                1 Reply Last reply Reply Quote 0
                • J Offline
                  Jenlimtz
                  last edited by

                  Hi


                  Need help:

                  1) Farmer Lim sold 1/2 as many eggs on Saturday than on Friday. He sold 78 less eggs on Sunday than on Friday. If he sold a total of 172 eggs on the three days, how many eggs did he sell on Sunday?

                  2) Tin A contains some 20-cents coins and Tin B contains some 50-cents coins. There are 9 more coins in Tin A than in Tin B. The amount of money in Tin A is $2.70 less than that in Tin B.
                  How many 50-cents coins are there in Tin B?

                  TIA

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                  • P Offline
                    pineapple tarts
                    last edited by

                    many thanks to piggylalala and usaik. I need some time to digest the solution. I am seeing stars . . .

                    1 Reply Last reply Reply Quote 0
                    • P Offline
                      pineapple tarts
                      last edited by

                      I cannot figure out why 165 is 5 units. let me think let me think . . .

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tianzhu
                        last edited by

                        Jenlimtz:

                        1) Farmer Lim sold 1/2 as many eggs on Saturday than on Friday. He sold 78 less eggs on Sunday than on Friday. If he sold a total of 172 eggs on the three days, how many eggs did he sell on Sunday?

                        2) Tin A contains some 20-cents coins and Tin B contains some 50-cents coins. There are 9 more coins in Tin A than in Tin B. The amount of money in Tin A is $2.70 less than that in Tin B.
                        How many 50-cents coins are there in Tin B?
                        Hi

                        Q1) You may use MD.

                        Fri ------ 2 units
                        Sat ----- 1 unit
                        Sun ------ 2 units – 78

                        2 units + 1unit + (2units – 78) ------172

                        5 units ------ 250
                        1 unit ------50

                        Number of eggs sold on Sun ----- (2*50) – 78 ------22.



                        Q2) Suppose or pretend that you remove 9 20 cents coins from Tin A.

                        9*20 ---- 180

                        Now Tin A has (270+180) or 450 cents less than Tin B

                        Difference in value between a 50 cents coin and 20 cents coin ------ 30 cents.

                        450/30 ------ 15

                        There are 15 50 cents coins in Tin B.

                        Best wishes

                        1 Reply Last reply Reply Quote 0

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