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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      ozora:
      Need guide on these questions.

      Ahmad spent $12.80 more than Ryan and 4 times as much money as Vincent. The 3 boys spent $118.60 altogether. How much money did Vincent spend?
      My answer
      12.80 x 1/4 =3.20
      118.6-3.2-12.8= 102.6
      102.6/ 9 =11.4
      11.4 + 3.2= $14.60. Is it correct?

      2. the number of apples at a store was 80% more than the number of oranges. After 60% of the oranges were sold, there were 42 more apples than oranges. Findthe total number of apples and oranges at first.
      Hi

      Q1 - yes.. you may want to add $12.80 to the total ie 12.80 +118.60 = 131.40 and this will be equal to 9u, 1u = $14.60 = Vincent's money.

      Q2. Apples : Oranges = 180 : 100 = 9u : 5u, total 14u
      after 60% oranges sold, oranges left = 0.4 x 5u = 2u
      so 9u-2u = 42, 7u=42, 1u =6

      Total number of fruits at first : 14u = 84, 54 apples & 30 oranges.

      cheers.

      1 Reply Last reply Reply Quote 0
      • ozoraO Offline
        ozora
        last edited by

        MathIzzzFun:
        ozora:

        Need guide on these questions.

        Ahmad spent $12.80 more than Ryan and 4 times as much money as Vincent. The 3 boys spent $118.60 altogether. How much money did Vincent spend?
        My answer
        12.80 x 1/4 =3.20
        118.6-3.2-12.8= 102.6
        102.6/ 9 =11.4
        11.4 + 3.2= $14.60. Is it correct?

        2. the number of apples at a store was 80% more than the number of oranges. After 60% of the oranges were sold, there were 42 more apples than oranges. Findthe total number of apples and oranges at first.

        Hi

        Q1 - yes.. you may want to add $12.80 to the total ie 12.80 +118.60 = 131.40 and this will be equal to 9u, 1u = $14.60 = Vincent's money.

        Q2. Apples : Oranges = 180 : 100 = 9u : 5u, total 14u
        after 60% oranges sold, oranges left = 0.4 x 5u = 2u
        so 9u-2u = 42, 7u=42, 1u =6

        Total number of fruits at first : 14u = 84, 54 apples & 30 oranges.

        cheers.

        oic. thanks

        1 Reply Last reply Reply Quote 0
        • C Offline
          Chenonceau
          last edited by

          Could someone help with this question? http://i53.tinypic.com/2dhwhtt.jpg\">

          1 Reply Last reply Reply Quote 0
          • K Offline
            kittybank
            last edited by

            This question appeared in a revision paper: Answer is 2.4km but no solutions given. Could the gurus here help? :thankyou:


            Andy, Benjamin and Charles travel from Town X to Town Y. They leave Town X at the same time. Andy drives at 56km/h, Benjamin walks at 8km/h and Charles walks at 7km/h. Andy gave Benjamin a lift at the start of journey to travel a part of the journey and then comes back to pick up Charles. They arrived at Town Y at the same time. If Benjamin walks 2.8km, how far does Charles walk?

            1 Reply Last reply Reply Quote 0
            • E Offline
              elkniwt
              last edited by

              Hi Chenonceau,


              Let me try ..

              Based on the figure,
              YC = YA, i.e. Angle YCA = (180 - 118)/2 = 31 (base angles of isos triangle)
              Angle ACB = Angle YCA + Angle YCB = 31 + 47 = 78
              Since ABCF is a rhombus, then AB = BC, Angle CAB = Angle ACB
              Angle ABC = 180 - 78x2 = 24 (sum angles in a triangle)
              Angle EDC = 180 -24 = 156 ( interior angles, AB // FC // ED)

              Hope there's no calculation error. šŸ™‚

              Regards.

              Chenonceau:
              Could someone help with this question? http://i53.tinypic.com/2dhwhtt.jpg\">

              1 Reply Last reply Reply Quote 0
              • C Offline
                Chenonceau
                last edited by

                elkniwt:
                Hi Chenonceau,


                Let me try ..

                Based on the figure,
                YC = YA, i.e. Angle YCA = (180 - 118)/2 = 31 (base angles of isos triangle)
                Angle ACB = Angle YCA + Angle YCB = 31 + 47 = 78
                Since ABCF is a rhombus, then AB = BC, Angle CAB = Angle ACB
                Angle ABC = 180 - 78x2 = 24 (sum angles in a triangle)
                Angle EDC = 180 -24 = 156 ( interior angles, AB // FC // ED)

                Hope there's no calculation error. šŸ™‚

                Regards.
                Chenonceau:

                Could someone help with this question? http://i53.tinypic.com/2dhwhtt.jpg\">

                Thank you!! šŸ’‹

                1 Reply Last reply Reply Quote 0
                • MathIzzzFunM Offline
                  MathIzzzFun
                  last edited by

                  wormy:
                  This question appeared in a revision paper: Answer is 2.4km but no solutions given. Could the gurus here help? :thankyou:


                  Andy, Benjamin and Charles travel from Town X to Town Y. They leave Town X at the same time. Andy drives at 56km/h, Benjamin walks at 8km/h and Charles walks at 7km/h. Andy gave Benjamin a lift at the start of journey to travel a part of the journey and then comes back to pick up Charles. They arrived at Town Y at the same time. If Benjamin walks 2.8km, how far does Charles walk?
                  Hi

                  http://i51.tinypic.com/2qi4miv.jpg\">

                  cheers.

                  1 Reply Last reply Reply Quote 0
                  • W Offline
                    Winx5015
                    last edited by

                    Hi, I need help for the following questions.


                    1) At first, Ahmad has 3 times as many stickers as Tricia. Then, each of them bought an equal number of stickers. In the end, Tricia had 72 stickers and Ahmad had twice as many stickers as Tricia. Find the number of stickers Ahmad had at first.

                    2) Mother has similar bags of three different colours: red, blue and green. 1 red bag and 2 blue bags weigh 13kg.
                    2 green bags and 2 blue bags weigh 22kg.
                    3 red bags and 2 green bags weigh 21kg.
                    (a) Find the total mass of 1 red bag, 1 blue bag and 1 green bag.
                    (b) Find the average mass of 1 red bag, 1 blue bag and 1 green bag.
                    Express your answer in kilograms.

                    3) Danny had $156 more than Esther. After Danny had spent 1/6 of his money and Esther spent 1/2 of her money, Danny had $245 more than Esther. How much money did Danny have at first?

                    Thanks!

                    1 Reply Last reply Reply Quote 0
                    • K Offline
                      kittybank
                      last edited by

                      Dear MathIzzzFun


                      Thank u so much!

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        wormy:
                        Dear MathIzzzFun


                        Thank u so much!
                        Hi

                        u r welcome šŸ˜„

                        cheers.

                        1 Reply Last reply Reply Quote 0

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