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    PSLE - New Format for Maths

    Scheduled Pinned Locked Moved Primary 6 & PSLE
    399 Posts 105 Posters 89.0k Views 1 Watching
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    • M Offline
      Mandy-Alex
      last edited by

      Guan Hui:
      John inherited $25,000 and invested part of it in a money market account, part in municipal bonds, and part in a mutual fund. After one year, he received a total of $1,620 in simple interest from the three investments. The money market paid 6% annually, the bonds paid 7% annually, and the mutually fund paid 8% annually. There was $6,000 more invested in the bonds than the mutual funds. Find the amount John invested in each category


      Money invest model
      MM [ ] |
      MB [1u ][6000] }$25000
      MF [ 1u] |

      25000-6000=$19000
      MM= 19000-2u

      Interest received for the $6000 invested in municipal bonds
      7% x 6000=7/100 x 6000
      =7 x 60
      =$420

      $1620- $420= $1200

      interest receive from 19000-2u of MM
      6% x (19000-2u)=19000x 6% -2u x 6%
      =(114000-12u)/100
      interest receive from 1 u of MB
      7% x 1u= 7u/100
      interest receive from 1 u of MF
      8% x 1u= 8u/100

      $1200=120000/100

      since all is divided by 100 we can ignore them(multiply all by 100)

      114000-12u+7u+8u=120000
      3u +114000=120000
      3u=6000
      1u=$2000

      money invested in MM
      19000-2u=19000-2x2000
      =19000- 4000
      =$15000
      money invested in MB
      1u+6000=2000+6000
      =$8000
      money invested in MF
      1u=$2000

      double check
      15000 X 6%= $900
      8000 X 7%= $560
      2000X 8%= $160
      900+560+160=$1620(correct)

      hope this helps=D But still seems algebra to me :stupid:


      Hi Guan Hui,

      I think algebra method will look more like that!
      Three equations and that's all!


      F+6000=B (1) --->> F=B-6000
      6M+7B+8F=162000 (2)
      M+B+F=25000 (3) --->>M+B+(B-6000)=25000 -->>M=31000-2B


      If we put for F=B-6000 and for M=31000-2B in the second equation and after few calculation we will get that B=$8000,

      Than F=B-6000=8000-6000 F=$2000,

      For M=31000-2B=31000-16000 M=$15000



      The last will be 7%x $8000=$560

      8%x $2000=$160

      9%x $15000=$900

      It seems easier than any model.




      Regards :lol:

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      • G Offline
        Guan Hui
        last edited by

        I can solve it in with 1 equation straight. Just trying to make the model make sense... but the space are canceled so the model looks wierd...=((

        trying my answer more understandable thats all šŸ˜› šŸ˜›
        Think next time I'll just use photoshop to make a jpeg and paste it here :lol:
        I know algebra is surely more easy.. but enoawng say:Can anyone help me to solve this below using the model method? thats y the model method

        1 Reply Last reply Reply Quote 0
        • M Offline
          Mandy-Alex
          last edited by

          Guan Hui:
          I can solve it in with 1 equation straight. Just trying to make the model make sense... but the space are canceled so the model looks wierd...=((

          trying my answer more understandable thats all šŸ˜› šŸ˜›
          Think next time I'll just use photoshop to make a jpeg and paste it here :lol:
          I know algebra is surely more easy.. but enoawng say:Can anyone help me to solve this below using the model method? thats y the model method

          OK! I just sow his/her request! Previously I did not go up to the beginning!

          1 Reply Last reply Reply Quote 0
          • G Offline
            Guan Hui
            last edited by

            Hehe=) np :lol:

            Glad that the PSLE is officially finally over. Parents of P6 students and P6 students you all deserve A GOOD REST!! Enjoy the rest of the year^^ CHEERS!

            1 Reply Last reply Reply Quote 0
            • L Offline
              lambchop1976
              last edited by

              Dear Parents of current P6 and those who posted their views,


              I salute all of you for your various contributions and I really read with much interest. Well I am not a parent who kids are any near to P6. They aint even in p1 yet. H/w as ex-tchr, I really very interested in what going on at primary sch lvl.

              As i read all the posts with interest esp those that states the PSLE Maths qns. I must say they are tough. And pls say to your little ones :\" Aunt here salute them too for being courageous to even sit thro the pp. Mayb if i m to sit fr the pp, i may cry 😢 so tough!!

              It does not matter whether current P6 or p5 or p4 ...parents to prepare your kids for tough sums/PSLE .. do tons of assessmt bks, ttn ctrs etc...
              But hv u all wonder is it necessary for the questions to be so tough in the first place? Wat r the examiners trying to prove? That they are clever and the stdnts are stupid??

              Whn i was a tchr (ws tchg in TOP sec school wher stdnts are top 5%), i always wonder why some of these TOP stdnts aint so TOP whn they r in sec. They seems to show a sharp decline in their ability may it be maths or science. I rmb my ex-colleague who commented a Sec2 gal(T-score 269) did a chinese compo test n her std ws at most p4 ...why?

              I mean lets be honest how many of us can really do those many tough qns in that ltd time and under the envt and conditions. Pressure cooker u know. :stupid: Whn i saw those qns i feel so stupid.

              Heard some excuses MOE gave was that the stdnts hv calculators to aid them. Oh pls...qns like the sweets Jim or Joe or watevr have and Ken with sweets (ratio qns) if u cant grasp the concept/understd, the calculator is just a white elephant.

              No wonder Maths kills some many brain cells and thus kids these days hate it! :?:

              1 Reply Last reply Reply Quote 0
              • M Offline
                mum42
                last edited by

                Hi i am a new mum joining this forum. Can someone help me solve this PSLE Question? Do not know the actual question but is something like : 6 pupils rented 4 computers for 2.5hrs each how long can each of them play equally? Son ans is 100mins but friend's daughter got 50mins and insisted is the correct ans. :?:

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                • M Offline
                  Mandy-Alex
                  last edited by

                  mum42:
                  Hi i am a new mum joining this forum. Can someone help me solve this PSLE Question? Do not know the actual question but is something like : 6 pupils rented 4 computers for 2.5hrs each how long can each of them play equally? Son ans is 100mins but friend's daughter got 50mins and insisted is the correct ans. :?:


                  Hi Mum42,
                  Welcome!
                  For this Q, my solving is a bit different from that I saw here, in the forum. Anyway I think it's correct and my ans is 100.


                  The solving:

                  6 pupils ---> 4 computers --->2h 30 min (150 min),

                  Let say the pupils are 4, than

                  4 pupils ---> 4 computers ---> 150 min, here is clear. Every pupil will use a computer for 150 min, but the pupils are 6.

                  Than 150 min x 4 computers = 600 min

                  600 min:6 pupils=100 min for every one of the pupils.


                  Your son ans is correct!
                  :lol:
                  But I can't say the same for my daughter's ans 😢

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                  • E Offline
                    enoawng
                    last edited by

                    Guan Hui:
                    I can solve it in with 1 equation straight. Just trying to make the model make sense... but the space are canceled so the model looks wierd...=((

                    trying my answer more understandable thats all šŸ˜› šŸ˜›
                    Think next time I'll just use photoshop to make a jpeg and paste it here :lol:
                    I know algebra is surely more easy.. but enoawng say:Can anyone help me to solve this below using the model method? thats y the model method
                    Thanks everyone. My view is that algebra is more suited for complex problems and in particular its ability to frame complex problems so that we can understand it and solve it step by step.

                    I am bewildered and annoyed why forumers insist that combination of models/heuristic & partial algebra is the more powerful method to solve complex problems.

                    However I do acknowledge that using simple models teaches our kids think differently when approaching a problem.

                    Nevertheless I can only speculate that those who insists on model being the best method for complex problems have self interest in mind to further the intake of students for maths tuition.

                    Like to hear the views of others.

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                    • A Offline
                      atutor2001
                      last edited by

                      enoawng:
                      atutor2001:



                      Fully agreed. However, please don't condemn \"model\" completely to the dungeon. It is a very powerful tool for solving question with minimum information.

                      Models are useful to solve problems up to a point of complexity.

                      Beyond that point, models are useless because the human mind can only handle a limited amount of complexity at the same time.

                      Einstein, Newton didn't use models or did they?

                      I used to share your view until encountering question with minimum information given. Then it dawn on me that using algebra for such problem requires the use of a few unknowns, which will cancelled off at the end. It takes great confidence for a P6 to use so many unknowns and the steps is quite laborious. Below is a sample of the type of question, previous posted in this forum, where the use of model simplified the process to the solution :

                      Tim walks to school from his home. One day, as he was walking pass a junction, he remembered that he left his wallet at home and he ran back to take his wallet and ran from home to school. He reached school at the same time as he usually did. The ratio of his running speed to his walking speed is 5:2. Given that the distance from the junction to his school is 1km, what is the distance between his home and school?

                      1 Reply Last reply Reply Quote 0
                      • E Offline
                        enoawng
                        last edited by

                        [quote]
                        I used to share your view until encountering question with minimum information given. Then it dawn on me that using algebra for such problem requires the use of a few unknowns, which will cancelled off at the end. It takes great confidence for a P6 to use so many unknowns and the steps is quite laborious. Below is a sample of the type of question, previous posted in this forum, where the use of model simplified the process to the solution :

                        Tim walks to school from his home. One day, as he was walking pass a junction, he remembered that he left his wallet at home and he ran back to take his wallet and ran from home to school. He reached school at the same time as he usually did. The ratio of his running speed to his walking speed is 5:2. Given that the distance from the junction to his school is 1km, what is the distance between his home and school?[/quote]D/W=(D-1)/W+2(D-1+D)/2(R)
                        Substitute 2R=5W
                        D/W=(D-1)/W+(4D-2)/5W
                        eliminate W
                        D=D-1+(4D-2)/5
                        D=7/4 ............
                        (I'm not sure where is the issue)

                        My view is that these minimum information problems are specifically designed to promote the use of models meaning if you change the information slightly the model method breaks down, whereas the algebric method is agnostic to the design of the question

                        Tim walks to school from his home. One day, as he was walking pass a junction, he remembered that he left his wallet at home and he ran back to take his wallet and ran from home to school. He reached school at the same time as he usually did. Tim's running speed is 2km/hr more than his walking speed. Given that the distance from the junction to his school is 1km, express the distance to school in terms of his walking speed?

                        1 Reply Last reply Reply Quote 0

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