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    Q&A - P3 Math

    Scheduled Pinned Locked Moved Primary 3
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    • cathychoC
      cathycho
      last edited by

      just888,


      Thanks for the solution. It’s so easy to understand with the model which I m not good at.

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      • Y
        youngtay
        last edited by

        Hi, need help for the following q.


        which one of the following numbers, when added to 3178 will allow regrouping of the ones and hundreds?
        A) 6732 B)6597 C)5914 D) 5832

        TIA

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        • M
          Muffins
          last edited by

          @WCW your answer is wrong. It should be 5832. The TENS and HUNDREDS do not have to be changed, it is the ONES and hundreds 😛 😛 😛 😛 😛 😛 😛 😛

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          • H
            HAPPYH
            last edited by

            Hi all,


            I need help with the following question.

            How many 4-digit numbers can be formed with the digits 4, 6, 0 and 5? If there is no 0 given, then it will be 4 x 3 x 2 x 1 = 24 numbers. If there is 0, is it just 3 x 2 x 1? Thank you in advance.

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            • P
              peapot
              last edited by

              I agree with WCW’s answer.



              I also have a question that I find difficult to teach and make her understand. Can anyone help?

              Henry has some apples. When he puts them equally into boxes of 3, he will have 5 more boxes than if he puts them into boxes of 4. How many apples does he have?

              I usually reserve "guess and check" method as the last resort. Any alternate ideas?

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              • T
                tianzhu
                last edited by

                peapot:
                I agree with WCW's answer.


                I also have a question that I find difficult to teach and make her understand. Can anyone help?

                Henry has some apples. When he puts them equally into boxes of 3, he will have 5 more boxes than if he puts them into boxes of 4. How many apples does he have?

                I usually reserve \"guess and check\" method as the last resort. Any alternate ideas?
                Hi

                Good Morning.

                This question was discussed in our of our earlier posts.

                Best wishes

                http://farm6.staticflickr.com/5126/5369093465_154cea1c91_z.jpg\">

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                • T
                  tianzhu
                  last edited by

                  HAPPYH:
                  Hi all,


                  I need help with the following question.

                  How many 4-digit numbers can be formed with the digits 4, 6, 0 and 5? If there is no 0 given, then it will be 4 x 3 x 2 x 1 = 24 numbers. If there is 0, is it just 3 x 2 x 1? Thank you in advance.
                  Hi

                  If such questions were to appear in P3 level, usually students would use “Systematic Listing” to solve it.It’s quite tedious.

                  Assuming no repetitions of number and 0 cannot be the first number.
                  \t
                  The first number can be chosen in 3 ways.

                  We can choose the second number in 3 ways.

                  The third number in 2 ways and we are left with one choice for the last number.

                  3*3*2*1 ----- 18 ways

                  Best wishes

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                  • H
                    HAPPYH
                    last edited by

                    tianzhu:
                    HAPPYH:

                    Hi all,


                    I need help with the following question.

                    How many 4-digit numbers can be formed with the digits 4, 6, 0 and 5? If there is no 0 given, then it will be 4 x 3 x 2 x 1 = 24 numbers. If there is 0, is it just 3 x 2 x 1? Thank you in advance.

                    Hi

                    If such questions were to appear in P3 level, usually students would use “Systematic Listing” to solve it.It’s quite tedious.

                    Assuming no repetitions of number and 0 cannot be the first number.
                    \t
                    The first number can be chosen in 3 ways.

                    We can choose the second number in 3 ways.

                    The third number in 2 ways and we are left with one choice for the last number.

                    3*3*2*1 ----- 18 ways

                    Best wishes

                    :thankyou:

                    1 Reply Last reply
                    Reply Quote 0
                    • O
                      optimistforum
                      last edited by

                      Help. Frantic advice for DS1 and DS2 needed.


                      Am I doing the right things with DS1. He has completed the first term of his P3, and struggles with Challenging Maths P3 by Sataya Sundar (EPH). Is it conceding defeat for me to take him back to the P2 book (which we did not complete), and for him to complete that before progressing to P3 again.

                      I will turn to DS2 in the P1 section.

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                      • H
                        HAPPYH
                        last edited by

                        😄

                        optimistforum:
                        Help. Frantic advice for DS1 and DS2 needed.


                        Am I doing the right things with DS1. He has completed the first term of his P3, and struggles with Challenging Maths P3 by Sataya Sundar (EPH). Is it conceding defeat for me to take him back to the P2 book (which we did not complete), and for him to complete that before progressing to P3 again.

                        I will turn to DS2 in the P1 section.

                        I also have the same feeling. No matter what/how I taught my DD, she still does mistakes with some questions. Sometimes, careless and sometimes she really does not know. We should not take it as a failure. WE should let them keep practising. If the Challenging Maths is a struggle, you sit with him and go thro' some problems. Over the time, he should be fine with it. It reminds me that my challenging maths is sleeping in the bookshelf. Must pass it to my DD to see her reaction as well as to see her level of understanding 😄

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