Q&A - P4 Math
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Thank you for your help, we solved all the (this type) questions.
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Hi,
I need help for the following question.
Michelle has more than 50 hairpins.
If she puts them in packets of 7, she has 5 hairpins left.
If she puts them in packets of 9, she has 6 hairpins left.
How many hairpins does Michelle have?
Thanks! -
The answer is 96.
Why? Because
>50
so
if packed in 7 with a remainder 5:
49+5 ; 56+5 ; 63+5 ; 70+5 ; 77+5 ; 84+5 ; 91+5
54 ; 61 ; 68 ; 75 ; 82 ; 89 ; 96
if packed in 9 with a total of the above, which no. I can get remainder 6?
6 r 0 ; 6 r 7 ; 7 r 5 ; 8 r 2 ; 9 r 1 ; 9 r 8 ; 10 r 6
So 96 is the answer. -
Thank you Mychildren and WCW for the explanations!

WCW, the table u created helps greatly , thanks! -
Its my pleasure, sokk! I love to crack my head if not will be rusty. Who knows? Someday you might be the one who is solving my queries here! :?:
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need help on this following question.
there are 3 different types of tiles.
Tile A- 0.54 kg
Tile B - 0.76kg
Tile C-0.63kg
Kim has a stack of 21 different types of tiles which are made of a combination of Tiles A, B and C. 9 of them are Tiles C and the total mass of 21 tiles is 13.69kg. How many tiles A and B are there respectively? -
ozora:
this is a guess and check question.need help on this following question.
there are 3 different types of tiles.
Tile A- 0.54 kg
Tile B - 0.76kg
Tile C-0.63kg
Kim has a stack of 21 different types of tiles which are made of a combination of Tiles A, B and C. 9 of them are Tiles C and the total mass of 21 tiles is 13.69kg. How many tiles A and B are there respectively?
Wt of 9 tiles C = 9 x 0.63 = 5.67kg
Wt of tiles A & B = 13/69 - 5.67 = 8.02kg
# of tiles A & B = 21 - 9 = 12
Guess and check
6A & 6B = (6x0.54) + (6x0.76) = 7.8kg
5A & 7B = (5x0.54) + (7x0.76) = 8.02
5 tile A and 7 tile B -
zeemimi:
this question is similar to the money question...and the number of legs question (in P3)... no need to use guess and check also can (want to use also can :D)
this is a guess and check question.ozora:
need help on this following question.
there are 3 different types of tiles.
Tile A- 0.54 kg
Tile B - 0.76kg
Tile C-0.63kg
Kim has a stack of 21 different types of tiles which are made of a combination of Tiles A, B and C. 9 of them are Tiles C and the total mass of 21 tiles is 13.69kg. How many tiles A and B are there respectively?
Wt of 9 tiles C = 9 x 0.63 = 5.67kg
Wt of tiles A & B = 13/69 - 5.67 = 8.02kg
# of tiles A & B = 21 - 9 = 12
Guess and check
6A & 6B = (6x0.54) + (6x0.76) = 7.8kg
5A & 7B = (5x0.54) + (7x0.76) = 8.02
5 tile A and 7 tile B
Tile A- 0.54 kg
Tile B - 0.76kg
Tile C-0.63kg
Kim has a stack of 21 different types of tiles which are made of a combination of Tiles A, B and C. 9 of them are Tiles C and the total mass of 21 tiles is 13.69kg. How many tiles A and B are there respectively?
---------------------------
9 Tile C --> 9x0.63=5.67
(21-9=)12 Tiles (A & B mix) --> 13.69-5.67=8.02
assume all 12 tiles are Tile A\t
--> 12x0.54=6.48\t
Difference --> 8.02-6.48=1.54
difference between Tile A & Tile B
1Tile --> 0.76-0.54=0.22
1.54 divide 0.22 = 7\t
\t
therefore 7\tTile B
and (12-7=) 5Tile A
hope it is clear...
(veterans....pls help double check
TQ).
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Need help.
How many whole numbers are there between 1000 and 10000?
Do we need to include nos ā1000ā n ā10000ā? -
The table shows the weights of some marbles.What is the weight of the heaviest marble?
a+b+c=240
b+c+d=230
c+d+a=250
a+b+d=210
can someone please help me on this question.
thank you in advanced.
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