Q&A - P5 Math

[blueymum]

Dear all,


Would need some help for the following questions:

1. Mary had a box of beads and buttons. 4/7 were beads. Mary gave away 57 buttons. Of the beads, 5/12 of them were red, 3/5 of the remainder were blue and the rest were yellow. If there were 84 blue beads, how many buttons were left?


2. Susan had a total of 402 mangoes and pineapples. She sold 28 pineapples and 1/9 of the mangoes. The number of pineapples left became 1/4 of the number of mangoes left. how many mangoes did Susan have at first?

Thanks so much!!

[tianzhu]

blueymum:

1. Mary had a box of beads and buttons. 4/7 were beads. Mary gave away 57 buttons. Of the beads, 5/12 of them were red, 3/5 of the remainder were blue and the rest were yellow. If there were 84 blue beads, how many buttons were left?

Hi

Good Morning.

This question on remainder concept may be solved using MD or Branch Method (BM).

Please refer to an earlier solution as an example.

I did a quick check and the answer is 123 buttons.

Best wishes

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[tianzhu]

blueymum:

2. Susan had a total of 402 mangoes and pineapples. She sold 28 pineapples and 1/9 of the mangoes. The number of pineapples left became 1/4 of the number of mangoes left. how many mangoes did Susan have at first?

Hi

You may use MD to solve this question.

I’ll give you some pointers.

Draw 9 boxes to show the number of mangoes. Colour 1 box to show the number of mangoes sold (1/9).Hence, you’ll have 8 boxes of mangoes remaining.

Draw 2 boxes to show the number of pineapples remaining (1/4 of the number of mangoes left). Add 28 pineapples sold.

11 units + 28 ------ 402
11 units ------ 374
1 unit ----- 34

Number of mangoes at first ------- 34*9 -------306

Best wishes

[YumYum]

Dear Tianzhu,


Thanks for working out the solutions for all the Qns late last nite.

I will need to go back to OnSponge for the basic concepts n run thru’ with my dd.

Enjoy the rest of the w-end.

[MathAche]

Can anybody provide the model for this problem?


John has 3 times as many stamps as Peter. When John loses 420 stamps and Peter loses 40 stamps, Peter has twice as many stamps as John. How many stamps does each of them have at first?

[Herbie]

MathAche:

Can anybody provide the model for this problem?


John has 3 times as many stamps as Peter. When John loses 420 stamps and Peter loses 40 stamps, Peter has twice as many stamps as John. How many stamps does each of them have at first?

err, i dun know how to use model by i just provide you with the alternative solution.

John : Peter
3u :1u
-420 : -40
_________
p : 2p

hence
3u-420 = p --(1) x 2 (so as to make becomes 2p)
1u-40=2p ---(2)

6u-840 = 2p ----(3)

Hence
1u-40=6u-840
u=160

Based on 1u-40 =2p
p= 60

John has 3u= 160 x 3=480
Peter has 1u=160

[szepinge]

Answer

Peter 88
John 264

[alan000]

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MathAche:

Can anybody provide the model for this problem?


John has 3 times as many stamps as Peter. When John loses 420 stamps and Peter loses 40 stamps, Peter has twice as many stamps as John. How many stamps does each of them have at first?

Dear MathAche,

Hope this helps.

[Easy-going]

Anybody can help me solve this problem sum?


If X gives Y 1/3 of his money, Y willhave $70 more than X. If X gives Y 1/5 of his money, Y will have $10 more than X. How much does each of them have at first?

[MathIzzzFun]

Easy-going:

Anybody can help me solve this problem sum?


If X gives Y 1/3 of his money, Y willhave $70 more than X. If X gives Y 1/5 of his money, Y will have $10 more than X. How much does each of them have at first?

Hi

X --> 15 units
After X gives 1/3 to Y, X --> 10 units, Y ---> 10 units + 70

So, money each has :
X --> 15 units
Y --> 5 units + 70

If X gives 1/5 to Y,
X --> 12 units, Y --> 8 units + 70
8 units + 70 = 12 units + 10 --> 4 units = 60, 1 unit = 15

X --> 15 x $ 15 = $ 225
Y --> 5 x $ 15 + & 70 = $ 145

cheers.