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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • T
      tianzhu
      last edited by

      blueymum:

      1. Mary had a box of beads and buttons. 4/7 were beads. Mary gave away 57 buttons. Of the beads, 5/12 of them were red, 3/5 of the remainder were blue and the rest were yellow. If there were 84 blue beads, how many buttons were left?
      Hi

      Good Morning.

      This question on remainder concept may be solved using MD or Branch Method (BM).

      Please refer to an earlier solution as an example.

      I did a quick check and the answer is 123 buttons.

      Best wishes

      http://farm8.staticflickr.com/7157/6580178853_c0e063bd36_z.jpg\">

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      • T
        tianzhu
        last edited by

        blueymum:

        2. Susan had a total of 402 mangoes and pineapples. She sold 28 pineapples and 1/9 of the mangoes. The number of pineapples left became 1/4 of the number of mangoes left. how many mangoes did Susan have at first?
        Hi

        You may use MD to solve this question.

        I’ll give you some pointers.

        Draw 9 boxes to show the number of mangoes. Colour 1 box to show the number of mangoes sold (1/9).Hence, you’ll have 8 boxes of mangoes remaining.

        Draw 2 boxes to show the number of pineapples remaining (1/4 of the number of mangoes left). Add 28 pineapples sold.

        11 units + 28 ------ 402
        11 units ------ 374
        1 unit ----- 34

        Number of mangoes at first ------- 34*9 -------306

        Best wishes

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        • Y
          YumYum
          last edited by

          Dear Tianzhu,


          Thanks for working out the solutions for all the Qns late last nite.

          I will need to go back to OnSponge for the basic concepts n run thru’ with my dd.

          Enjoy the rest of the w-end.

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          • M
            MathAche
            last edited by

            Can anybody provide the model for this problem?


            John has 3 times as many stamps as Peter. When John loses 420 stamps and Peter loses 40 stamps, Peter has twice as many stamps as John. How many stamps does each of them have at first?

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            • H
              Herbie
              last edited by

              MathAche:
              Can anybody provide the model for this problem?


              John has 3 times as many stamps as Peter. When John loses 420 stamps and Peter loses 40 stamps, Peter has twice as many stamps as John. How many stamps does each of them have at first?

              err, i dun know how to use model by i just provide you with the alternative solution.

              John : Peter
              3u :1u
              -420 : -40
              _________
              p : 2p

              hence
              3u-420 = p --(1) x 2 (so as to make becomes 2p)
              1u-40=2p ---(2)

              6u-840 = 2p ----(3)

              Hence
              1u-40=6u-840
              u=160

              Based on 1u-40 =2p
              p= 60

              John has 3u= 160 x 3=480
              Peter has 1u=160

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              • S
                szepinge
                last edited by

                Answer

                Peter 88
                John 264

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                • A
                  alan000
                  last edited by

                  http://i41.tinypic.com/242tyl5.jpg\">

                  MathAche:
                  Can anybody provide the model for this problem?


                  John has 3 times as many stamps as Peter. When John loses 420 stamps and Peter loses 40 stamps, Peter has twice as many stamps as John. How many stamps does each of them have at first?
                  Dear MathAche,

                  Hope this helps.

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                  • E
                    Easy-going
                    last edited by

                    Anybody can help me solve this problem sum?


                    If X gives Y 1/3 of his money, Y willhave $70 more than X. If X gives Y 1/5 of his money, Y will have $10 more than X. How much does each of them have at first?

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                    • MathIzzzFunM
                      MathIzzzFun
                      last edited by

                      Easy-going:
                      Anybody can help me solve this problem sum?


                      If X gives Y 1/3 of his money, Y willhave $70 more than X. If X gives Y 1/5 of his money, Y will have $10 more than X. How much does each of them have at first?
                      Hi

                      X --> 15 units
                      After X gives 1/3 to Y, X --> 10 units, Y ---> 10 units + 70

                      So, money each has :
                      X --> 15 units
                      Y --> 5 units + 70

                      If X gives 1/5 to Y,
                      X --> 12 units, Y --> 8 units + 70
                      8 units + 70 = 12 units + 10 --> 4 units = 60, 1 unit = 15

                      X --> 15 x $ 15 = $ 225
                      Y --> 5 x $ 15 + & 70 = $ 145

                      cheers.

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                      • B
                        blueymum
                        last edited by

                        Thanks Tianzhu for your help. Really appreciated it.



                        Just wondering if anyone knows how to solve this?

                        Sam earns 7/9 as much as Andy. Ken’s salary is 1/6 of the total salary of the three men. Ken earns $2560 less than the combined salary of Sam and Andy. What is Sam’s salary?

                        thanks all!!

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