Q&A - PSLE Math
-
Winx5015:
HiHi tianzhu,
Thanks for your solution.
Have a nice weekends
You're welcome.
Have a good weekend too.
Best wishes -
jewelbox:
HiHi tianzhu
Thank you so much for the solutions and teaching how to use units and parts.:)
You're welcome.
Your username reminds me that my jewelbox is very empty, so sad.
While MD may be used to solve your question, I think UP is more efficient.
Have a good weekend.
Best wishes -
Hi Tianzhu,
Thank you for helping many of us here in solving questions. I would like to seek your advice on any good approach to tackling Maths as a subject. My DS has super good memory when it comes to geography, history, current affairs, events etc. But when it comes to remembering Mathematics concept, strategy and rules, he is like a goldfish with 3 seconds memory! He forgets them so easily! This make learning progress very slow as we have to back track almost every topic that he has been taught. -
Hi,
Pse assist on the following q:
q1 : The ratio of the num of xavier’s stickers to the num of Yvonne’s stickers to the num of Zack’s stickers was 4:6:7 at first. When Xavier bought another 35 stickers & Yvonne lost 27 stickers, Xavier & Yvonne had the same num of stickers. How many more stickers would Zack have to buy in order to have twice as many stickers as Yvonne?
q2: On Mr Chan’s farm, 70% of his fowls were chickens & the rest were ducks. When he bought another 108 more ducks, the num of ducks on his farm increased by 40%. Afer selling some chickens, he had an equal num of chickens & ducks left. How many chickens did Mr Chan sell?
q3: At first, Chenxu had 2/3 as many stickers as Weiwei. After Chenxu bought another 3 stickers and Weiwei lost 9 stickers, Chenxu had 5/6 as many stickers as Weiwei. Find the num of stickers Chenxu had at first?
TIA -
jtparent:
HiHi,
Pse assist on the following q:
q1 : The ratio of the num of xavier's stickers to the num of Yvonne's stickers to the num of Zack's stickers was 4:6:7 at first. When Xavier bought another 35 stickers & Yvonne lost 27 stickers, Xavier & Yvonne had the same num of stickers. How many more stickers would Zack have to buy in order to have twice as many stickers as Yvonne?
q2: On Mr Chan's farm, 70% of his fowls were chickens & the rest were ducks. When he bought another 108 more ducks, the num of ducks on his farm increased by 40%. Afer selling some chickens, he had an equal num of chickens & ducks left. How many chickens did Mr Chan sell?
q3: At first, Chenxu had 2/3 as many stickers as Weiwei. After Chenxu bought another 3 stickers and Weiwei lost 9 stickers, Chenxu had 5/6 as many stickers as Weiwei. Find the num of stickers Chenxu had at first?
TIA
Q1.
X : Y : Z --> 4u : 6u : 7u
4u + 35 = 6u - 27
2u --> 62
1u --> 31
Z --> 7 x 31 = 217
Y --> 6u - 27 = 159
Number of Z needs to buy = 159 x 2 - 217 = 101
Q2.
Chickens : Ducks --> 70u : 30u
Ducks increased by 40% --> 40% x 30u = 12u
12u --> 108, 1u --> 9
Ducks --> 42 x 9 = 378
Number of chickens sold = 70 x 9 - 378 = 252
Q3.
C : W --> 2u : 3u
2u+3 : 3u-9 = 5 : 6
cross multiply or equalize :
12u + 18 = 15u - 45
3u = 63, 1u = 21
At first C had 21 x 2 = 42 stickers
cheers. -
MathIzzzFun:
Tks Mathizzfun.
Hijtparent:
Hi,
Pse assist on the following q:
q1 : The ratio of the num of xavier's stickers to the num of Yvonne's stickers to the num of Zack's stickers was 4:6:7 at first. When Xavier bought another 35 stickers & Yvonne lost 27 stickers, Xavier & Yvonne had the same num of stickers. How many more stickers would Zack have to buy in order to have twice as many stickers as Yvonne?
q2: On Mr Chan's farm, 70% of his fowls were chickens & the rest were ducks. When he bought another 108 more ducks, the num of ducks on his farm increased by 40%. Afer selling some chickens, he had an equal num of chickens & ducks left. How many chickens did Mr Chan sell?
q3: At first, Chenxu had 2/3 as many stickers as Weiwei. After Chenxu bought another 3 stickers and Weiwei lost 9 stickers, Chenxu had 5/6 as many stickers as Weiwei. Find the num of stickers Chenxu had at first?
TIA
Q1.
X : Y : Z --> 4u : 6u : 7u
4u + 35 = 6u - 27
2u --> 62
1u --> 31
Z --> 7 x 31 = 217
Y --> 6u - 27 = 159
Number of Z needs to buy = 159 x 2 - 217 = 101
Q2.
Chickens : Ducks --> 70u : 30u
Ducks increased by 40% --> 40% x 30u = 12u
12u --> 108, 1u --> 9
Ducks --> 42 x 9 = 378
Number of chickens sold = 70 x 9 - 378 = 252
Q3.
C : W --> 2u : 3u
2u+3 : 3u-9 = 5 : 6
cross multiply or equalize :
12u + 18 = 15u - 45
3u = 63, 1u = 21
At first C had 21 x 2 = 42 stickers
cheers.
u re great! solution is easily understood except q3 when say cross multiply or equalize..may i know hw to do tat? sorry to bother u again -
jtparent:
Tks Mathizzfun.
HiMathIzzzFun:
[quote=\"jtparent\"]Hi,
Pse assist on the following q:
q1 : The ratio of the num of xavier's stickers to the num of Yvonne's stickers to the num of Zack's stickers was 4:6:7 at first. When Xavier bought another 35 stickers & Yvonne lost 27 stickers, Xavier & Yvonne had the same num of stickers. How many more stickers would Zack have to buy in order to have twice as many stickers as Yvonne?
q2: On Mr Chan's farm, 70% of his fowls were chickens & the rest were ducks. When he bought another 108 more ducks, the num of ducks on his farm increased by 40%. Afer selling some chickens, he had an equal num of chickens & ducks left. How many chickens did Mr Chan sell?
q3: At first, Chenxu had 2/3 as many stickers as Weiwei. After Chenxu bought another 3 stickers and Weiwei lost 9 stickers, Chenxu had 5/6 as many stickers as Weiwei. Find the num of stickers Chenxu had at first?
TIA
Q1.
X : Y : Z --> 4u : 6u : 7u
4u + 35 = 6u - 27
2u --> 62
1u --> 31
Z --> 7 x 31 = 217
Y --> 6u - 27 = 159
Number of Z needs to buy = 159 x 2 - 217 = 101
Q2.
Chickens : Ducks --> 70u : 30u
Ducks increased by 40% --> 40% x 30u = 12u
12u --> 108, 1u --> 9
Ducks --> 42 x 9 = 378
Number of chickens sold = 70 x 9 - 378 = 252
Q3.
C : W --> 2u : 3u
2u+3 : 3u-9 = 5 : 6
cross multiply or equalize :
12u + 18 = 15u - 45
3u = 63, 1u = 21
At first C had 21 x 2 = 42 stickers
cheers.
u re great! solution is easily understood except q3 when say cross multiply or equalize..may i know hw to do tat? sorry to bother u again[/quote]Hi
Q3.
C : W --> 2u : 3u
2u+3 : 3u-9
= 5parts : 6parts
equalize parts --> 6 x (2u+3) = 5x(3u-9)
cheers. -
Hi,
Can anyone please help in the following question:
In a school hall, chairs were arranged in rows such that there were exactly 9 chairs in each row.
For a concert, Mr Ong brought 6 more chairs into the school hall and rearranged all the chairs. There are now exactly 7 chairs in each row and 2 more rows than before. How many chairs are there in the school hall for the concert ?
Thank you in advance ! -
fightingmom:
HiHi,
Can anyone please help in the following question:
In a school hall, chairs were arranged in rows such that there were exactly 9 chairs in each row.
For a concert, Mr Ong brought 6 more chairs into the school hall and rearranged all the chairs. There are now exactly 7 chairs in each row and 2 more rows than before. How many chairs are there in the school hall for the concert ?
Thank you in advance !
2 new rows of 7 chairs --> 14 chairs
number of chairs removed from original number of rows = 14 - 6 = 8
2 chairs removed from each row, so number of rows at first = 8 / 2 = 4
total number of chairs = 4 x 9 + 6 = 6 x 7 = 42
cheers. -
Thank you, MathIzzzFun !
Hello! It looks like you're interested in this conversation, but you don't have an account yet.
Getting fed up of having to scroll through the same posts each visit? When you register for an account, you'll always come back to exactly where you were before, and choose to be notified of new replies (either via email, or push notification). You'll also be able to save bookmarks and upvote posts to show your appreciation to other community members.
With your input, this post could be even better 💗
Register Login