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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • 2 Offline
      2DMommy
      last edited by

      Please help me with these questions :


      1) Benita and Mildred shared a box of laminating sheets. If Benita were to give 25% of her share to Mildred, Benita would have half of Mildred's final share. If Benita were to give 16 laminating sheets to Mildred, Benita would have 54 fewer laminating sheets than Mildred. If they were to pack all their laminating sheets into boxes of 25 each, what is the least number of boxes required to pack all of them ?

      2)Jan and Kay had equal number of sweets and equal number of chocolates. Jan ate 12 sweets and Kay ate 18 chocolates and then the ratio of Jan's sweets to chocolates became 1 : 7 and the ratio of Kay's sweets to chocolates became 1 : 4. How many sweets did Jan have at first?

      3)The tickets for a show are priced at $10 and $5. The number of ten-dollar tickets available is 1 half times the number of five-dollar tickets. 5 out of 6 ten-dollar tickets and all the five-dollar tickets were sold. The amount of money collected from the sale of the tickets were $5600. How much more would have been collected if all the tickets were sold ?

      :thankyou:

      1 Reply Last reply Reply Quote 0
      • B Offline
        Bunny27
        last edited by

        I’m not sure about tis question…

        Colin and Karin save $2378.1/6 of Colin’s savings is $41 more than 1/7 of Karin’s savings. Find the ratio of Colins savings to Karin’s savings. Express your answer in the simplest form.

        TIA

        1 Reply Last reply Reply Quote 0
        • W Offline
          Winx5015
          last edited by

          Hi tianzhu,


          Thanks for your solution.

          Have a nice weekends 🙂

          1 Reply Last reply Reply Quote 0
          • J Offline
            jewelbox
            last edited by

            Hi tianzhu

            Thank you so much for the solutions and teaching how to use units and parts.:)

            1 Reply Last reply Reply Quote 0
            • T Offline
              tianzhu
              last edited by

              Winx5015:
              Hi tianzhu,


              Thanks for your solution.

              Have a nice weekends 🙂
              Hi

              You're welcome.

              Have a good weekend too.

              Best wishes

              1 Reply Last reply Reply Quote 0
              • T Offline
                tianzhu
                last edited by

                jewelbox:
                Hi tianzhu

                Thank you so much for the solutions and teaching how to use units and parts.:)
                Hi

                You're welcome.

                Your username reminds me that my jewelbox is very empty, so sad.

                While MD may be used to solve your question, I think UP is more efficient.

                Have a good weekend.

                Best wishes

                1 Reply Last reply Reply Quote 0
                • H Offline
                  happyheart
                  last edited by

                  Hi Tianzhu,


                  Thank you for helping many of us here in solving questions. I would like to seek your advice on any good approach to tackling Maths as a subject. My DS has super good memory when it comes to geography, history, current affairs, events etc. But when it comes to remembering Mathematics concept, strategy and rules, he is like a goldfish with 3 seconds memory! He forgets them so easily! This make learning progress very slow as we have to back track almost every topic that he has been taught.

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                  • J Offline
                    jtparent
                    last edited by

                    Hi,


                    Pse assist on the following q:

                    q1 : The ratio of the num of xavier’s stickers to the num of Yvonne’s stickers to the num of Zack’s stickers was 4:6:7 at first. When Xavier bought another 35 stickers & Yvonne lost 27 stickers, Xavier & Yvonne had the same num of stickers. How many more stickers would Zack have to buy in order to have twice as many stickers as Yvonne?

                    q2: On Mr Chan’s farm, 70% of his fowls were chickens & the rest were ducks. When he bought another 108 more ducks, the num of ducks on his farm increased by 40%. Afer selling some chickens, he had an equal num of chickens & ducks left. How many chickens did Mr Chan sell?

                    q3: At first, Chenxu had 2/3 as many stickers as Weiwei. After Chenxu bought another 3 stickers and Weiwei lost 9 stickers, Chenxu had 5/6 as many stickers as Weiwei. Find the num of stickers Chenxu had at first?

                    TIA

                    1 Reply Last reply Reply Quote 0
                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      jtparent:
                      Hi,


                      Pse assist on the following q:

                      q1 : The ratio of the num of xavier's stickers to the num of Yvonne's stickers to the num of Zack's stickers was 4:6:7 at first. When Xavier bought another 35 stickers & Yvonne lost 27 stickers, Xavier & Yvonne had the same num of stickers. How many more stickers would Zack have to buy in order to have twice as many stickers as Yvonne?

                      q2: On Mr Chan's farm, 70% of his fowls were chickens & the rest were ducks. When he bought another 108 more ducks, the num of ducks on his farm increased by 40%. Afer selling some chickens, he had an equal num of chickens & ducks left. How many chickens did Mr Chan sell?

                      q3: At first, Chenxu had 2/3 as many stickers as Weiwei. After Chenxu bought another 3 stickers and Weiwei lost 9 stickers, Chenxu had 5/6 as many stickers as Weiwei. Find the num of stickers Chenxu had at first?

                      TIA
                      Hi
                      Q1.
                      X : Y : Z --> 4u : 6u : 7u

                      4u + 35 = 6u - 27
                      2u --> 62
                      1u --> 31

                      Z --> 7 x 31 = 217
                      Y --> 6u - 27 = 159
                      Number of Z needs to buy = 159 x 2 - 217 = 101

                      Q2.
                      Chickens : Ducks --> 70u : 30u
                      Ducks increased by 40% --> 40% x 30u = 12u
                      12u --> 108, 1u --> 9
                      Ducks --> 42 x 9 = 378
                      Number of chickens sold = 70 x 9 - 378 = 252

                      Q3.
                      C : W --> 2u : 3u
                      2u+3 : 3u-9 = 5 : 6
                      cross multiply or equalize :
                      12u + 18 = 15u - 45
                      3u = 63, 1u = 21
                      At first C had 21 x 2 = 42 stickers

                      cheers.

                      1 Reply Last reply Reply Quote 0
                      • J Offline
                        jtparent
                        last edited by

                        MathIzzzFun:
                        jtparent:

                        Hi,


                        Pse assist on the following q:

                        q1 : The ratio of the num of xavier's stickers to the num of Yvonne's stickers to the num of Zack's stickers was 4:6:7 at first. When Xavier bought another 35 stickers & Yvonne lost 27 stickers, Xavier & Yvonne had the same num of stickers. How many more stickers would Zack have to buy in order to have twice as many stickers as Yvonne?

                        q2: On Mr Chan's farm, 70% of his fowls were chickens & the rest were ducks. When he bought another 108 more ducks, the num of ducks on his farm increased by 40%. Afer selling some chickens, he had an equal num of chickens & ducks left. How many chickens did Mr Chan sell?

                        q3: At first, Chenxu had 2/3 as many stickers as Weiwei. After Chenxu bought another 3 stickers and Weiwei lost 9 stickers, Chenxu had 5/6 as many stickers as Weiwei. Find the num of stickers Chenxu had at first?

                        TIA

                        Hi
                        Q1.
                        X : Y : Z --> 4u : 6u : 7u

                        4u + 35 = 6u - 27
                        2u --> 62
                        1u --> 31

                        Z --> 7 x 31 = 217
                        Y --> 6u - 27 = 159
                        Number of Z needs to buy = 159 x 2 - 217 = 101

                        Q2.
                        Chickens : Ducks --> 70u : 30u
                        Ducks increased by 40% --> 40% x 30u = 12u
                        12u --> 108, 1u --> 9
                        Ducks --> 42 x 9 = 378
                        Number of chickens sold = 70 x 9 - 378 = 252

                        Q3.
                        C : W --> 2u : 3u
                        2u+3 : 3u-9 = 5 : 6
                        cross multiply or equalize :
                        12u + 18 = 15u - 45
                        3u = 63, 1u = 21
                        At first C had 21 x 2 = 42 stickers

                        cheers.

                        Tks Mathizzfun.

                        u re great! solution is easily understood except q3 when say cross multiply or equalize..may i know hw to do tat? sorry to bother u again

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