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    Q&A - P3 Math

    Scheduled Pinned Locked Moved Primary 3
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    • cathychoC Offline
      cathycho
      last edited by

      What is the fastest method to solve this type of question?


      Darren has some 10-cent coins, 20-cent coins and 50-cent coins in his pocket that add up to $2. He has exactly 9 coins. How many 20-cent coins does he have?

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        cathycho:
        What is the fastest method to solve this type of question?


        Darren has some 10-cent coins, 20-cent coins and 50-cent coins in his pocket that add up to $2. He has exactly 9 coins. How many 20-cent coins does he have?
        Hi

        First, is this a multiple choice question where four options are available for students to choose?

        The numbers are not too big, so it’ll not be tedious to arrive at an answer if choices are given.

        If not, use “Systematic Listing”, it’s also not too tedious as we are dealing with small numbers.

        The answer is 3 20-cent coins.

        Best wishes

        1 Reply Last reply Reply Quote 0
        • H Offline
          HAPPYH
          last edited by

          cathycho:
          What is the fastest method to solve this type of question?


          Darren has some 10-cent coins, 20-cent coins and 50-cent coins in his pocket that add up to $2. He has exactly 9 coins. How many 20-cent coins does he have?
          I really wonder why our children needs to know this. As long as they know the value of each coin and how to make certain amount, isn't fine? Sigh

          1 Reply Last reply Reply Quote 0
          • cathychoC Offline
            cathycho
            last edited by

            tianzhu:
            cathycho:

            What is the fastest method to solve this type of question?


            Darren has some 10-cent coins, 20-cent coins and 50-cent coins in his pocket that add up to $2. He has exactly 9 coins. How many 20-cent coins does he have?

            Hi

            First, is this a multiple choice question where four options are available for students to choose?

            The numbers are not too big, so it’ll not be tedious to arrive at an answer if choices are given.

            If not, use “Systematic Listing”, it’s also not too tedious as we are dealing with small numbers.

            The answer is 3 20-cent coins.

            Best wishes


            Yes, it's a multiple choice question. Thks.

            1 Reply Last reply Reply Quote 0
            • T Offline
              Taurus
              last edited by

              [Mod's note: threads merged]

              Hi,

              Anyone can help to explain how to get the answer:

              Qns : When A is divided by 5, it gives a remainder. Which is the most possible pair of quotient (Q) and remainder (R) when A is divided by 5?

              (1) Q = 5, R= 9
              (2) Q = 6, R = 6
              (3) Q = 5, R = 5
              (4) Q = 6, R = 4

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              • B Offline
                BigDevil
                last edited by

                Hi, instead of starting a new thread for your question, please go to the http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=66&t=149 thread and post a reply there.


                For this question, the answer is (4). In division, the remainder can never be equal or more than the divisor.

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                • E Offline
                  e.011054chua
                  last edited by

                  Pls help me on this question.


                  In a class of 42 pupils, each boy received 3 stickers and each girl received 4 stickers from their teacher. Altogether the teacher gave out 154 stickers. How many girls were there in this class?

                  The answer is :
                  42 x 4 = 168
                  168-42 = 126
                  154-126 = 28

                  But I do not understand why 168-42 ?

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                  • MathIzzzFunM Offline
                    MathIzzzFun
                    last edited by

                    e.chua:
                    Pls help me on this question.


                    In a class of 42 pupils, each boy received 3 stickers and each girl received 4 stickers from their teacher. Altogether the teacher gave out 154 stickers. How many girls were there in this class?

                    The answer is :
                    42 x 4 = 168
                    168-42 = 126
                    154-126 = 28

                    But I do not understand why 168-42 ?
                    Hi
                    I think the answer provided is based on assumptive method... with 1 extra step.
                    Assume all are girls --> 3 x 42 = 126 (which is = 168 - 42)

                    The assumptive method can also be represented in form of area model ..

                    http://i43.tinypic.com/35a7ivo.png\">

                    cheers.

                    1 Reply Last reply Reply Quote 0
                    • M Offline
                      Michaelia0816
                      last edited by

                      I also got a method, similar but more understanding!

                      Method: Assuming
                      Let us assume that all are boys
                      Time- 42x3=126
                      Minus- 154-126=28
                      Minus- 4-3=1
                      Divide- 28 divide 1=28
                      So the answer is 28.
                      remember TMMD method using assuming!

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                      • P Offline
                        peapot
                        last edited by

                        Oh! this method is abit like the 2 legs and 4 legs question.


                        I also have a question which I remember someone ask before. But I can’t understand why? Hope someone can explain.

                        Jeremy brought a sum of money to buy some pencils. If he buys 4 pencils, he would be left with $2. If he buys 5 pencils, he would need another $1.

                        How much is the cost of 1 pencil? and how much money did he have at first?

                        1 Reply Last reply Reply Quote 0

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