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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T
      tianzhu
      last edited by

      lousymum:
      Help pls.

      (1) Michael jogged while Karen walked from the same place but in opposite directions along a straight road. After 5h, they were 30 km apart. Michael's average speed was 1.2 km/h faster than Karen's average speed. What was Karen's average walking speed?
      Hi

      There’s a few ways to solve it.

      For questions on Speed, it’s useful to start with a simple diagram.

      If Karen’s distance travelled in 5h is showed by 1 unit or 1 box, then Michael’s distance travelled in 5h would be 1 unit or 1 box + (5*1.2)

      Hence we have 2 boxes or units + 6 ------- 30

      This gives 1 unit/box ------- 12

      Therefore, Karen’s speed -------- 12/5 ------- 2.4

      Best wishes

      1 Reply Last reply
      Reply Quote 0
      • T
        tianzhu
        last edited by

        lousymum:

        (2) Ben and Macus received some moey from their mother. Marcus would have $64 more than Ben if Ben gave 2/5 of his share to Marcus. Marcus would have $144 more than Ben if Ben gave 2/3 of his share to Marcus. How much money did Ben receive from his mother?
        Hi

        There are two scenarios in this question.

        Marcus would have $64 more than Ben if Ben gave 2/5 of his share to Marcus.

        A common multiple of 3 and 5 is 15

        Marcus -------9 units + 64
        Ben -------- 9 units

        Marcus would have $144 more than Ben if Ben gave 2/3 of his share to Marcus

        Marcus -------5 units + 144
        Ben -------- 5 units

        The total amount of money in both scenarios stays the same.

        18 units + 64 ------- 10 units + 144
        8 units -------- 80
        1 unit ------- 10

        Ben ------- 15 units -------- 150

        Best wishes

        1 Reply Last reply
        Reply Quote 0
        • L
          lousymum
          last edited by

          Hi tianzhu,


          hmm... yr answers are so much easiler to digest, :thankyou:

          1 Reply Last reply
          Reply Quote 0
          • K
            koguma
            last edited by

            tianzhu:
            lousymum:

            Help pls.

            (1) Michael jogged while Karen walked from the same place but in opposite directions along a straight road. After 5h, they were 30 km apart. Michael's average speed was 1.2 km/h faster than Karen's average speed. What was Karen's average walking speed?

            Hi

            There’s a few ways to solve it.

            For questions on Speed, it’s useful to start with a simple diagram.

            If Karen’s distance travelled in 5h is showed by 1 unit or 1 box, then Michael’s distance travelled in 5h would be 1 unit or 1 box + (5*1.2)

            Hence we have 2 boxes or units + 6 ------- 30

            This gives 1 unit/box ------- 12

            Therefore, Karen’s speed -------- 12/5 ------- 2.4

            Best wishes

            Hi Tianzhu, I tried to following your steps for the following qns but I get stuck. Appreciate if you can advise on this qns. Thanks.

            A cargo train leaves city X for city Y, 1500km apart at 8am. At the same time, express train leaves city Y for city X. Express train travels at a speed 100km/h faster than cargo train.
            The 2 trains pass each other and they are 300km apart at 8pm. What is the speed of express train?

            1 Reply Last reply
            Reply Quote 0
            • T
              tianzhu
              last edited by

              Hi koguma


              Please refer to MathIzzzFun’s solution.

              Best wishes

              1 Reply Last reply
              Reply Quote 0
              • MathIzzzFunM
                MathIzzzFun
                last edited by

                koguma:

                A cargo train leaves city X for city Y, 1500km apart at 8am. At the same time, express train leaves city Y for city X. Express train travels at a speed 100km/h faster than cargo train.
                The 2 trains pass each other and they are 300km apart at 8pm. What is the speed of express train?
                Hi

                Draw a diagram for the journey..
                1st part of the journey -- cargo train and express train meet --> total distance travelled (by both) = 1500 km
                2nd part of journey -- cargo train and express train \"separate\" and go opposite way --> additional distance covered = 300 km in total.
                Total distance covered in 1st part & 2nd part of journey --> 1800 km --(A)

                Since express train travels 100 km/h faster, after 12 hours (8am to 8pm), the express train will cover 100 km x 12 h = 1200 km more than the cargo train.

                So, distance covered by express train --> (1800 + 1200) / 2 = 1500 km
                Express train's speed --> 125 km/h
                Cargo train's speed --> 25 km/h

                or ..from (A) and total time from 8am - 8pm = 12h,
                total speed (cargo + express) = 1800 km/ 12h = 150 km/h
                since express train's speed is 100 km/h more than cargo train,
                express train's speed --> (150 + 100) /2 = 125 km/h

                cheers.

                1 Reply Last reply
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                • C
                  Chan09
                  last edited by

                  Why would you divide by 2?

                  distance covered by express train –> (1800 + 1200) / 2 = 1500 km

                  1 Reply Last reply
                  Reply Quote 0
                  • MathIzzzFunM
                    MathIzzzFun
                    last edited by

                    Chan09:
                    Why would you divide by 2?

                    distance covered by express train --> (1800 + 1200) / 2 = 1500 km
                    Hi

                    Draw a simple model,
                    Bigger block--> expres train
                    Smaller block --> cargo train
                    Sum = 1800
                    Difference = 1200

                    cheers.

                    1 Reply Last reply
                    Reply Quote 0
                    • N
                      Neat
                      last edited by

                      Hi


                      Tap A can fill a tank completely in 6 minutes. Tap B can fill the same tank completely in 3 minutes. At the beginning, Tap A was turned on to fill the tank. After 1 minute, Tap B was then turned on to fill the tank. How long would it take to fill the tank completely?

                      Thanks for the time.

                      1 Reply Last reply
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                      • E
                        Edureach
                        last edited by

                        Neat:
                        Hi


                        Tap A can fill a tank completely in 6 minutes. Tap B can fill the same tank completely in 3 minutes. At the beginning, Tap A was turned on to fill the tank. After 1 minute, Tap B was then turned on to fill the tank. How long would it take to fill the tank completely?

                        Thanks for the time.

                        Let the volume of the tank be in 6 units.

                        Speed of tap A to fill 1 unit = 1min/6mins for 6 units.
                        Speed of tap B to fill 1 unit = 30 secs/3mins for 6 units.

                        Tap A was turned on during 1st min = 1 unit filled.
                        Tap A & B were turned on during next min = 1+2 units filled.
                        Time taken to filled 4 units = 2 mins Ans(A).
                        Balance 2 units to be filled by tap A and B.

                        It took 60 secs to fill 3 units.
                        For 2 units time taken = 60 x 2/3 = 40 secs Ans (B).

                        Total time taken to fill completely = Ans A +B = 2 mins 40 secs.

                        1 Reply Last reply
                        Reply Quote 0

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