Q&A - P5 Math

[savoury sweet]

MathIzzzFun:

savoury sweet:

Hi, can anyone help me with this question? Thks


Lily would like to cut out as many isosceles triangles of the same shape and size from a rectangular piece of paper shown length 29cm and breath 14cm. Each isosceles triangle should have a base of 6cm and a height of 4 cm. What is the maximum number of isosceles triangles she can cut ?

My apologies, I could not draw the intended rectangle and isosceles triangle.

Hi

May I know the source of this question ? What is the given answer ?
Personally, I think this question is beyond the scope of P5/P6. It is more likely a MO question.

My answer is 28

cheers.

Hi MathIzzzfun,

That was my gal's SA1 maths question. The ans is 24. The workout given as 4 x 3 x 2 = 24. I don't get the \" x 2\" part ??

[tianzhu]

savoury sweet:

Hi, can anyone help me with this question? Thks


Lily would like to cut out as many isosceles triangles of the same shape and size from a rectangular piece of paper shown length 29cm and breath 14cm. Each isosceles triangle should have a base of 6cm and a height of 4 cm. What is the maximum number of isosceles triangles she can cut ?

My apologies, I could not draw the intended rectangle and isosceles triangle.

Hi

Hope this helps.

Best wishes

http://farm8.staticflickr.com/7237/7201423944_6d5baf659b_z.jpg\">

[MathIzzzFun]

savoury sweet:

MathIzzzFun:

[quote=\"savoury sweet\"]Hi, can anyone help me with this question? Thks


Lily would like to cut out as many isosceles triangles of the same shape and size from a rectangular piece of paper shown length 29cm and breath 14cm. Each isosceles triangle should have a base of 6cm and a height of 4 cm. What is the maximum number of isosceles triangles she can cut ?

My apologies, I could not draw the intended rectangle and isosceles triangle.

Hi

May I know the source of this question ? What is the given answer ?
Personally, I think this question is beyond the scope of P5/P6. It is more likely a MO question.

My answer is 28

cheers.

Hi MathIzzzfun,

That was my gal's SA1 maths question. The ans is 24. The workout given as 4 x 3 x 2 = 24. I don't get the \" x 2\" part ??[/quote]Hi

I have attached the solution to obtain 28 triangles. To get this, one needs to know pythagorus theorem and similar triangles.

http://i49.tinypic.com/2dccy2c.png\">

cheers.

[Nebbermind]

MathIzzzFun:

I have attached the solution to obtain 28 triangles. To get this, one needs to know pythagorus theorem and similar triangles.

http://i49.tinypic.com/2dccy2c.png\">

cheers.

:udaman:

[savoury sweet]

Hi


May I know the source of this question ? What is the given answer ?
Personally, I think this question is beyond the scope of P5/P6. It is more likely a MO question.

My answer is 28

cheers.[/quote]


Hi MathIzzzfun,

That was my gal's SA1 maths question. The ans is 24. The workout given as 4 x 3 x 2 = 24. I don't get the \" x 2\" part ??[/quote]

Hi

I have attached the solution to obtain 28 triangles. To get this, one needs to know pythagorus theorem and similar triangles.

http://i49.tinypic.com/2dccy2c.png\">

cheers.[/quote]


Thank you so much MathIzzzfun

[MathIzzzFun]

savoury sweet:

Hi


May I know the source of this question ? What is the given answer ?
Personally, I think this question is beyond the scope of P5/P6. It is more likely a MO question.

My answer is 28

cheers.


Hi MathIzzzfun,

That was my gal's SA1 maths question. The ans is 24. The workout given as 4 x 3 x 2 = 24. I don't get the \" x 2\" part ??

Hi

I have attached the solution to obtain 28 triangles. To get this, one needs to know pythagorus theorem and similar triangles.

http://i49.tinypic.com/2dccy2c.png\">

cheers.


Thank you so much MathIzzzfun

u r welcome. The question was not set properly, and certainly 24 triangles cannot be the answer.

I just realized that using the configuration of triangle 9,10,11 above, I could fit in one more ie total 29.

Here's the 29 triangles configuration:

http://postimage.org/image/fo9sglp17/



cheers.

[TulipisPink]

Hi parents

Could you help to solve this maths question? Thanks.

Pupil B, J and A shared some money. The ratio of B’s money to the total of J’s and A’s money is 4:9. A’s share was 6 times J’s. B had $95 more than J. How much money had A?

[TulipisPink]

Q: A farmer had a square field with an area of 57600 sq meter. He planted a tree at the four corners and some along the sides of the field. Each tree was planted 20 m from the next. How many trees were planted on one side of the field?

[TulipisPink]

Q: In a swimming test there were 109 participants. The ratio of the no. of boys who passed the test to the no. of boys who failed the test was 4:9. 4/7 of the girls passed the test. A total of 52 pupils passed the test. How many girls failed the test?

[TulipisPink]

Q: Ben bought 2 sacks of flour, sack A and sack B. They had a total mass of 440 kg. Ben then poured 1/3 of the flour from sack A to sack B. Then he poured 1/3 of flour from sack B to sack A. As a result both sacks had the same amount of flour. How much flour was there in sack A at first.