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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • T
      tianzhu
      last edited by

      savoury sweet:
      Hi, can anyone help me with this question? Thks


      Lily would like to cut out as many isosceles triangles of the same shape and size from a rectangular piece of paper shown length 29cm and breath 14cm. Each isosceles triangle should have a base of 6cm and a height of 4 cm. What is the maximum number of isosceles triangles she can cut ?

      My apologies, I could not draw the intended rectangle and isosceles triangle.
      Hi

      Hope this helps.

      Best wishes

      http://farm8.staticflickr.com/7237/7201423944_6d5baf659b_z.jpg\">

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      • MathIzzzFunM
        MathIzzzFun
        last edited by

        savoury sweet:
        MathIzzzFun:

        [quote=\"savoury sweet\"]Hi, can anyone help me with this question? Thks


        Lily would like to cut out as many isosceles triangles of the same shape and size from a rectangular piece of paper shown length 29cm and breath 14cm. Each isosceles triangle should have a base of 6cm and a height of 4 cm. What is the maximum number of isosceles triangles she can cut ?

        My apologies, I could not draw the intended rectangle and isosceles triangle.

        Hi

        May I know the source of this question ? What is the given answer ?
        Personally, I think this question is beyond the scope of P5/P6. It is more likely a MO question.

        My answer is 28

        cheers.


        Hi MathIzzzfun,

        That was my gal's SA1 maths question. The ans is 24. The workout given as 4 x 3 x 2 = 24. I don't get the \" x 2\" part ??[/quote]Hi

        I have attached the solution to obtain 28 triangles. To get this, one needs to know pythagorus theorem and similar triangles.

        http://i49.tinypic.com/2dccy2c.png\">

        cheers.

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        • NebbermindN
          Nebbermind
          last edited by

          MathIzzzFun:


          I have attached the solution to obtain 28 triangles. To get this, one needs to know pythagorus theorem and similar triangles.

          http://i49.tinypic.com/2dccy2c.png\">

          cheers.
          :udaman:

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          • S
            savoury sweet
            last edited by

            Hi


            May I know the source of this question ? What is the given answer ?
            Personally, I think this question is beyond the scope of P5/P6. It is more likely a MO question.

            My answer is 28

            cheers.[/quote]


            Hi MathIzzzfun,

            That was my gal's SA1 maths question. The ans is 24. The workout given as 4 x 3 x 2 = 24. I don't get the \" x 2\" part ??[/quote]

            Hi

            I have attached the solution to obtain 28 triangles. To get this, one needs to know pythagorus theorem and similar triangles.

            http://i49.tinypic.com/2dccy2c.png\">

            cheers.[/quote]


            Thank you so much MathIzzzfun 😄

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            • MathIzzzFunM
              MathIzzzFun
              last edited by

              savoury sweet:
              Hi


              May I know the source of this question ? What is the given answer ?
              Personally, I think this question is beyond the scope of P5/P6. It is more likely a MO question.

              My answer is 28

              cheers.


              Hi MathIzzzfun,

              That was my gal's SA1 maths question. The ans is 24. The workout given as 4 x 3 x 2 = 24. I don't get the \" x 2\" part ??

              Hi

              I have attached the solution to obtain 28 triangles. To get this, one needs to know pythagorus theorem and similar triangles.

              http://i49.tinypic.com/2dccy2c.png\">

              cheers.


              Thank you so much MathIzzzfun 😄
              u r welcome. The question was not set properly, and certainly 24 triangles cannot be the answer.

              I just realized that using the configuration of triangle 9,10,11 above, I could fit in one more ie total 29.

              Here's the 29 triangles configuration:

              http://postimage.org/image/fo9sglp17/



              cheers.

              1 Reply Last reply
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              • T
                TulipisPink
                last edited by

                Hi parents

                Could you help to solve this maths question? Thanks.

                Pupil B, J and A shared some money. The ratio of B’s money to the total of J’s and A’s money is 4:9. A’s share was 6 times J’s. B had $95 more than J. How much money had A?

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                • T
                  TulipisPink
                  last edited by

                  Q: A farmer had a square field with an area of 57600 sq meter. He planted a tree at the four corners and some along the sides of the field. Each tree was planted 20 m from the next. How many trees were planted on one side of the field?

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                  • T
                    TulipisPink
                    last edited by

                    Q: In a swimming test there were 109 participants. The ratio of the no. of boys who passed the test to the no. of boys who failed the test was 4:9. 4/7 of the girls passed the test. A total of 52 pupils passed the test. How many girls failed the test?

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                    • T
                      TulipisPink
                      last edited by

                      Q: Ben bought 2 sacks of flour, sack A and sack B. They had a total mass of 440 kg. Ben then poured 1/3 of the flour from sack A to sack B. Then he poured 1/3 of flour from sack B to sack A. As a result both sacks had the same amount of flour. How much flour was there in sack A at first.

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                      • T
                        tianzhu
                        last edited by

                        TulipisPink:
                        Hi parents

                        Could you help to solve this maths question? Thanks.

                        Pupil B, J and A shared some money. The ratio of B's money to the total of J's and A's money is 4:9. A's share was 6 times J's. B had $95 more than J. How much money had A?
                        Hi

                        You may use MD or work using units.

                        B:(J+A) -------- 4:9 -------- 28:63

                        A:J -------- 6:1 (7) -------- 54:9 (63)

                        Make the total units for (J+A) the same.

                        28 – 9 ------- 19

                        19 units ------- 95

                        1 unit ------- 5

                        A -------- 54*5 ------- 270

                        Best wishes

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