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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • H Offline
      happyheart
      last edited by

      tianzhu:
      happyheart:


      Thanks Tianzhu! I understand now 🙂

      one question, Would you think this is a typical p5 question? I checked through DS worksheet and cannot find similar question to work on.

      Hi

      Where did you get this question from?

      From my experience during my kid's PSLE, questions involving \"Working Backwards\" are popular.

      Best wishes

      Tianzhu, The question is from DS school, June holiday worksheet.

      1 Reply Last reply Reply Quote 0
      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        beanbear:
        I have such a struggle with the following type of problem sums. Is there a particular approach to such sums? What is the critical thing to understand about such problems?


        (1) Mr Lim bought 4 pears & 5 lemons. Mr Tan bought 5 pears and 4 lemons. Mr Tan paid 20cents more than Mr Lim. If Mr Lim paid $4.40, how much did 4 pears cost?

        (2) 5 similar files cost $3 more than 3 similar pens. Mrs Lee purchased 3 files and 6 pens for $17.40. What was the cost of each file?
        Hi

        For both questions, one needs to find out the difference in price in the two items.

        You can use MD, or picture models, units to find the difference first.

        Q1.
        Lim --> 4P + 5L = (4P + 4L) + 1L
        Tan --> 5P + 4L = (4P + 4L) + 1P
        Tan paid 20 cents more --> 1P is 20 cents more than 1L
        1L --> 1 unit
        1P --> 1 unit + 0.20
        Lim --> 4 units + 0.80 + 5 units = 9 units + 0.80 --> $ 4.40
        1 unit --> $ 0.40
        1P --> $0.40 + $ 0.20 = $ 0.60
        4P --> $ 2.40
        4 pears cost $ 2.40

        cheers.

        1 Reply Last reply Reply Quote 0
        • MathIzzzFunM Offline
          MathIzzzFun
          last edited by

          beanbear:
          I have such a struggle with the following type of problem sums. Is there a particular approach to such sums? What is the critical thing to understand about such problems?


          (1) Mr Lim bought 4 pears & 5 lemons. Mr Tan bought 5 pears and 4 lemons. Mr Tan paid 20cents more than Mr Lim. If Mr Lim paid $4.40, how much did 4 pears cost?

          (2) 5 similar files cost $3 more than 3 similar pens. Mrs Lee purchased 3 files and 6 pens for $17.40. What was the cost of each file?
          Hi

          Q2.
          lowest common multiple of 5 & 3 --> 15

          3 pens --> 15 units, 1 pen --> 5 units
          5 files --> 15 units + $3.00, 1 file --> 3 units + $ 0.60
          3 files + 6 pens --> (9 units + $1.80) + 30 units = 39 units + $ 1.80 --> $ 17.40
          1 unit --> $0.40

          1 pen --> $ 2.00
          1 file --> $ 1.20 + $ 0.60 = $1.80

          cheers.

          1 Reply Last reply Reply Quote 0
          • T Offline
            the shadowed snake
            last edited by

            thanks tianzhu

            1 Reply Last reply Reply Quote 0
            • B Offline
              beanbear
              last edited by

              MathIzzzFun:
              beanbear:

              I have such a struggle with the following type of problem sums. Is there a particular approach to such sums? What is the critical thing to understand about such problems?


              (1) Mr Lim bought 4 pears & 5 lemons. Mr Tan bought 5 pears and 4 lemons. Mr Tan paid 20cents more than Mr Lim. If Mr Lim paid $4.40, how much did 4 pears cost?

              (2) 5 similar files cost $3 more than 3 similar pens. Mrs Lee purchased 3 files and 6 pens for $17.40. What was the cost of each file?

              Hi

              Q2.
              lowest common multiple of 5 & 3 --> 15

              3 pens --> 15 units, 1 pen --> 5 units
              5 files --> 15 units + $3.00, 1 file --> 3 units + $ 0.60
              3 files + 6 pens --> (9 units + $1.80) + 30 units = 39 units + $ 1.80 --> $ 17.40
              1 unit --> $0.40

              1 pen --> $ 2.00
              1 file --> $ 1.20 + $ 0.60 = $1.80

              cheers.

              Thanks so much for your clear explanation!! I see the light!

              1 Reply Last reply Reply Quote 0
              • C Offline
                cimman
                last edited by

                beanbear:
                I have such a struggle with the following type of problem sums. Is there a particular approach to such sums? What is the critical thing to understand about such problems?


                (1) Mr Lim bought 4 pears & 5 lemons. Mr Tan bought 5 pears and 4 lemons. Mr Tan paid 20cents more than Mr Lim. If Mr Lim paid $4.40, how much did 4 pears cost?

                (2) 5 similar files cost $3 more than 3 similar pens. Mrs Lee purchased 3 files and 6 pens for $17.40. What was the cost of each file?
                Hi Beanbear
                if you are open to using algebra and simultaneous equations, there is a consistent way to solve such problems. It does not rely on heursitcs, just equation generation and solving the equations.

                I categorise such problems as Unit Value problems, because they all require the same basic formula: Quantity x Unit Cost = Total Cost

                Mr Lim bought 4 pears & 5 lemons. Mr Tan bought 5 pears and 4 lemons. Mr Tan paid 20cents more than Mr Lim. If Mr Lim paid $4.40, how much did 4 pears cost?

                the first step is to fill up the table with the values from the problem sum. Here, the fonts in black represents the values from the problem sum. Next, put in the unknown variables, in this case, u and p for the respective unit values. The fonts in red represents the calculated or derived values.

                http://i50.tinypic.com/2hwk77q.png\">

                5 similar files cost $3 more than 3 similar pens. Mrs Lee purchased 3 files and 6 pens for $17.40. What was the cost of each file?

                in the next question, the same Unit Value table is used. The process is the same, fill up the table with values from the problem sum, then put in the unknown variables, then circle the relevant equations.
                http://i49.tinypic.com/rgwg44.png\">

                the filling up of the table with the values from the problem sum is very straight forward, so the child will not be confused. The table itself guides you on the relationships between the different values.

                if you do not use simultaneous equations concepts, then you'll have to use heuristics to remove one unknown from a 2 unknown problem.
                In the above example, 5u - 3p = 3. You'll find that if you use Lowest Common Multiple of 5 and 3, you'll remove one unknown from the equation, the u and p will have the same units. This is a techniqe in solving simultaneous equations.

                The advantage of using simultaneous equations is that the child do not have to contend with learning multiple heuristics and uses just one technique to solve a wide range of problems. The downside of simultaneous equations is that schools don't teach it, so parents or tutors will have to teach this concept.

                Each category of problem type have a different table, because the table enforces the formula required to solve that particular problem type. If you're interested in such technique, I conduct a workshop for parents, you can get the infomation from here: http://www.kiasuparents.com/kiasu/forum/viewtopic.php?f=43&t=32278&start=110
                the next workshop would be around end June to early July.

                1 Reply Last reply Reply Quote 0
                • U Offline
                  Udon
                  last edited by

                  Please help…THANK U…

                  Appreciate with illustration, thankz for your time.

                  Q1. Container A has a mass of 1 000g when it is 3/5 filled with oil. Its mass is 40g more when it is 5/8 filled with oil. What is the mass of the empty container?


                  Q2. Roland had $160 less than Jim. After Jim spent $200 on a shirt and tie, Roland had twice as much money as Jim. Find the amount of money Jim had at first.

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    tianzhu
                    last edited by

                    Udon:

                    Q2. Roland had $160 less than Jim. After Jim spent $200 on a shirt and tie, Roland had twice as much money as Jim. Find the amount of money Jim had at first.
                    Hi

                    Hope this helps.

                    Best wishes

                    http://farm8.staticflickr.com/7077/7179026399_d7b10983b0_z.jpg\">

                    1 Reply Last reply Reply Quote 0
                    • H Offline
                      happyheart
                      last edited by

                      Hi, I need help on this…please help with illustration. I am confused with multiple variables and the 3 equations. Thank you!


                      The cost of 6 identical chairs , 5 identical lamps and 1 table is $380.
                      The cost of 2 such chairs and 1 table is $188, while 1 chair and 1 lamp cost $44.
                      a) What is the cost of 1 chair and 1 table?
                      b) What is the total cost of 1 table, 1 lamp and 1 chair?

                      1 Reply Last reply Reply Quote 0
                      • C Offline
                        chloecube
                        last edited by

                        happyheart:
                        Hi, I need help on this...please help with illustration. I am confused with multiple variables and the 3 equations. Thank you!


                        The cost of 6 identical chairs , 5 identical lamps and 1 table is $380.
                        The cost of 2 such chairs and 1 table is $188, while 1 chair and 1 lamp cost $44.
                        a) What is the cost of 1 chair and 1 table?
                        b) What is the total cost of 1 table, 1 lamp and 1 chair?
                        a) 1 chair = $28
                        1 table = $132
                        1 lamp = $16
                        28+ 132 =160

                        b) 160 + 16 = $176

                        1 Reply Last reply Reply Quote 0

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