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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • T Offline
      tianzhu
      last edited by

      Spongy:

      3.If Bernerd sells a computer at a discount of 20% of the usual selling price, he will earn $45. If he sells the computer at a discount of 35% of the usual selling price he will lose $30.
      (a) Find the usual selling price of the computer
      (b) Find the cost price of the computer
      Hi

      Please take a look at this similar question.It'll help to answer your question.

      Best wishes

      http://farm6.staticflickr.com/5064/5816591015_a98e4eb5a1_z.jpg\">

      1 Reply Last reply Reply Quote 0
      • S Offline
        Shimmer
        last edited by

        tianzhu:
        Shimmer:


        2) A school is staging a play to raise funds for an orphanage. The tickets for this fundraising charity play are priced at $10 and $5. The number of ten dollar ticket available is 1 1/2 times the number of five dollar tickets. 5/6 of the ten dollar tickets and 3/4 of the five dollar tickets were sold. The tickets sales amt to $ 5850. How much more funds will the school be able to raise if all tickets sold ?

        Hi

        Hope this helps.

        Best wishes

        http://farm9.staticflickr.com/8027/7504879614_e9c51e4e99_z.jpg\">

        Hi Tianzhu

        May I know according to the model it's show the ten dollar x 2 which is 8 units but I thought its should be 1.5 times ? Thanks to advise. Greatly appreciate.

        1 Reply Last reply Reply Quote 0
        • M Offline
          Michaelia0816
          last edited by

          small:
          tianzhu:

          This question is pretty interesting, but I have reasons to believe that there are some figures which are not in order. I think if you change 456 to 462, you should be able to arrive at a solution.


          A fruit seller had some oranges, pears and durians. After selling some of them, there were 6 pears for every 5 oranges left and 7 oranges for every 3 durians left. He sold 168 oranges. He had 456 pears and oranges left. The number of pears sold was the same as the number of durians sold. a) How many oranges had he at first? (2m) b) If the number of pears was twice the number of durians at first, what was the total number of pears and durians sold? (3m)


          Hi Tianzhu,
          Agreed with you. If it was 462 then my answers will be:

          a) 378 oranges
          b) 144 of pears and durian sold

          πŸ˜‰

          Hi Tianzhu, this question is found in my HW, of course, it 462 not 456.
          I not sure how to get 144 as my answer? Pls tell how, help me with the (b) part,can?

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            Spongy:

            2. Marvin and Nick had some twenty-cent coins each. If Marvin gave 1/3 of his share to Nick, Nick would have 210 coins more than Marvin. If Marvin gave 1/4 of his share to Nick, the ratio of number of Marvin's coins to the number of Nick's coins would become 3:7. What is the difference between the sum of money that each of them had?
            Hi

            Case 1

            In the end

            Marvin ------ 8 units
            Nick ------ 8 units + 210

            At first

            Marvin ------ 12 units
            Nick ------ 4 units + 210

            Case 2

            In the end

            Marvin ------ 9 units
            Nick ------ 7 units + 210

            9 units : 7 units + 210 ------- 3:7

            Cross multiply

            63 units ------- 21 units + 630

            42 units ------ 630

            1 unit ------ 15

            Marvin ------ 12 unit ------ 180

            Nick ------ 4 units + 210 ------ 270

            Difference ------- 90

            Best wishes

            1 Reply Last reply Reply Quote 0
            • T Offline
              tianzhu
              last edited by

              Shimmer:

              May I know according to the model it's show the ten dollar x 2 which is 8 units but I thought its should be 1.5 times ? Thanks to advise. Greatly appreciate.
              Hi

              The first set of MD shows number while the second set of MD shows value.

              Best wishes

              1 Reply Last reply Reply Quote 0
              • J Offline
                jarenchuatw
                last edited by

                Thanks BB for explaining that time is inversely proportional to speed, given that distance is common. I have definitely learnt something new.


                Got another similar question to one that I have asked previously still can’t figure out how to do it - due to my lack of imagination. Will need help again for the following question.

                A block of wood 28cm by 66cm by 9 cm was cut into smaller pieces which were 4cm by 7cm by 3cm each. What was the maximum number of pieces that it could be cut into?

                Thanks

                1 Reply Last reply Reply Quote 0
                • T Offline
                  tianzhu
                  last edited by

                  Spongy:

                  1. 1/4 of the marbles in a box are red and the rest are either blue or green. If there are 36 more blue than twice the number of green ones, how many more red marbles than green marbles a there?
                  Hi

                  Green ------ 1 unit

                  Blue ------ 2 units + 36

                  3 units + 36 ------ 3 parts (3/4)

                  1 unit + 12 ------ 1 part (1/4)

                  Red ------ 1 unit + 12

                  Hence there are 12 more red marbles than green marbles.

                  Best wishes

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    Shimmer
                    last edited by

                    tianzhu:
                    Shimmer:

                    Hi all


                    One more question.

                    Ravi put some eggs into 3 boxes box A, box B and box C. 1/2 of the eggs in box A is equal to 3/10 of the eggs in box B . The numbers of egg in box C is 16 more than 1/2 of the total numbers of eggs in box A and box B, if 25% of the eggs in box C were broken and removed, there were 804 more eggs in box B than in box C. Ravi sold each egg at 8 cents. How much did he earn ?

                    Hi

                    Box A ----- 6 units

                    Box B ------ 10 units

                    Box C ----- 8 units + 16

                    25% of the eggs in box C were broken and removed.

                    Box C (removed) ----- 2 units + 4

                    Box C (left) ----- 6 units + 12

                    There were 804 more eggs in box B than in box C.

                    10 units – (6 units + 12) ------ 804

                    1 unit ----- 204

                    Number of eggs sold ------ 22 units + 12 ------ 4500

                    Ravi sold each egg at 8 cents

                    4500*8 ------ $360.

                    Best wishes

                    Hi Tianzhu

                    How do you get 1 unit 204 ?

                    Don't understand this part :

                    10 units – (6 units + 12) ------ 804

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      tianzhu
                      last edited by

                      Shimmer:

                      Hi Tianzhu

                      How do you get 1 unit 204 ?

                      Don't understand this part :

                      10 units – (6 units + 12) ------ 804
                      Hi

                      4 units – 12 ------- 804

                      4 units ------ 804 + 12 ------ 816

                      1 unit ------ 816/4 ------- 204

                      Best wishes

                      1 Reply Last reply Reply Quote 0
                      • MathIzzzFunM Offline
                        MathIzzzFun
                        last edited by

                        jarenchuatw:
                        Thanks BB for explaining that time is inversely proportional to speed, given that distance is common. I have definitely learnt something new.


                        Got another similar question to one that I have asked previously still can't figure out how to do it - due to my lack of imagination. Will need help again for the following question.

                        A block of wood 28cm by 66cm by 9 cm was cut into smaller pieces which were 4cm by 7cm by 3cm each. What was the maximum number of pieces that it could be cut into?

                        Thanks
                        hi

                        A block of wood 28cm by 66cm by 9 cm was cut into smaller pieces which were 4cm by 7cm by 3cm each. What was the maximum number of pieces that it could be cut into?

                        28/7 x 9/3 x 66/4 (52) -- cut the 66 cm side into 4 cm each up to 52 cm
                        = 4 x 3 x 13 blocks = 156 blocks,
                        leaving a block of 28 cm x 9 cm x 14 cm (66 cm - 52 cm = 14 cm)

                        The remaining block can be further cut into 28/4 x 9/3 x 14/7 = 7 x 3 x 2= 42 blocks.

                        total 156 + 42 = 198 blocks

                        cheers.

                        1 Reply Last reply Reply Quote 0

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