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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • F
      fudgemum
      last edited by

      The question is


      Given that the value of the sum 1/a + 1/b + 1/c lies between 28/29 and 1, find the smallest possible value of a+b+c where a, b and c are whole numbers.

      The answer for this question is 12. This is SMOPS 2009 first round question.

      I tried using guess and check method starting with 1. 1 is not possible because the result will be more than 1. 2 and 3 are possible.
      1/2 + 1/3 = 0.8333.
      The other number cannot be 4 and 5. The sum will be more than 1. If it is 6, the sum will be exactly 1. So it should be 7.
      1/2 +1/3 + 1/7 is less than 1 and greater than 28/29.

      So the answer is 2+3+7 = 12.

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      • M
        mathsguru
        last edited by

        fudgemum:
        The question is


        Given that the value of the sum 1/a + 1/b + 1/c lies between 28/29 and 1, find the smallest possible value of a+b+c where a, b and c are whole numbers.

        The answer for this question is 12. This is SMOPS 2009 first round question.

        I tried using guess and check method starting with 1. 1 is not possible because the result will be more than 1. 2 and 3 are possible.
        1/2 + 1/3 = 0.8333.
        The other number cannot be 4 and 5. The sum will be more than 1. If it is 6, the sum will be exactly 1. So it should be 7.
        1/2 +1/3 + 1/7 is less than 1 and greater than 28/29.

        So the answer is 2+3+7 = 12.
        Hi Fudgemum,

        Thanks for clarifying!! No wonder no matter how I solve, I can't seem to get the answer \"12 based on Vikaesh's original question... πŸ˜“

        Hi Vikaesh >> Is Fudgemum's question correct? πŸ™‚

        Regards,
        MathsGuru

        1 Reply Last reply
        Reply Quote 0
        • D
          david59
          last edited by

          fudgemum:
          The question is


          Given that the value of the sum 1/a + 1/b + 1/c lies between 28/29 and 1, find the smallest possible value of a+b+c where a, b and c are whole numbers.

          The answer for this question is 12. This is SMOPS 2009 first round question.

          I tried using guess and check method starting with 1. 1 is not possible because the result will be more than 1. 2 and 3 are possible.
          1/2 + 1/3 = 0.8333.
          The other number cannot be 4 and 5. The sum will be more than 1. If it is 6, the sum will be exactly 1. So it should be 7.
          1/2 +1/3 + 1/7 is less than 1 and greater than 28/29.

          So the answer is 2+3+7 = 12.
          While I understand your rationale of 1/2 +1/3 + 1/7 is less than 1 and greater than 28/29, the total sum of the three is equal to 41/42 = 0.97619
          but the value of 57/58 is 0.98275.
          Since the question states that the value of the three is equal to 57/58, how then is the answer 2, 3 n 7 correct when they do not give the same equal value.
          Sorry, pardon my ignorance. I would like to learn. :?

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          • T
            tianzhu
            last edited by

            david59:
            fudgemum:

            The question is


            Given that the value of the sum 1/a + 1/b + 1/c lies between 28/29 and 1, find the smallest possible value of a+b+c where a, b and c are whole numbers.

            The answer for this question is 12. This is SMOPS 2009 first round question.

            Since the question states that the value of the three is equal to 57/58,

            Hi David

            According to fudgemum's question, it should be 28/29 not 57/58.

            Best wishes

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            • ChiefKiasuC
              ChiefKiasu
              last edited by

              mathsguru:
              Hi Fudgemum,


              Thanks for clarifying!! No wonder no matter how I solve, I can't seem to get the answer \"12 based on Vikaesh's original question... πŸ˜“

              Hi Vikaesh >> Is Fudgemum's question correct? πŸ™‚

              Regards,
              MathsGuru
              MathsGuru's logic is impeccable. There has to be a mistake either in the question or answer provided by Vikaesh. So before we all go bald :frustrated: for nothing, can Vikaesh kindly state the source of your question and answer?

              1 Reply Last reply
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              • D
                Dharma
                last edited by

                ChiefKiasu:
                mathsguru:

                Hi Fudgemum,


                Thanks for clarifying!! No wonder no matter how I solve, I can't seem to get the answer \"12 based on Vikaesh's original question... πŸ˜“

                Hi Vikaesh >> Is Fudgemum's question correct? πŸ™‚

                Regards,
                MathsGuru

                MathsGuru's logic is impeccable. There has to be a mistake either in the question or answer provided by Vikaesh. So before we all go bald :frustrated: for nothing, can Vikaesh kindly state the source of your question and answer?

                Hi Chief,

                The question can be found under SAPMOPS 2009 1st Round Q18. Check this http://www.hci.sg/aphelion/apmops/downloads.htm

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                • F
                  fudgemum
                  last edited by

                  I think the question was changed and this is only my guess.


                  Since the value of the sum 1/a + 1/b + 1/c lies between 28/29 and 1, he has assumed it as 28.5/29 which is 57/58. It is only inbetween and not the midpoint.

                  If anyone can provide the solution for Round 1 question numbers 7,21,23 and 30 from the above link provided by Dharma, it will be of great help.

                  Thanks.

                  1 Reply Last reply
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                  • D
                    Dharma
                    last edited by

                    fudgemum:
                    I think the question was changed and this is only my guess.


                    Since the value of the sum 1/a + 1/b + 1/c lies between 28/29 and 1, he has assumed it as 28.5/29 which is 57/58. It is only inbetween and not the midpoint.

                    If anyone can provide the solution for Round 1 question numbers 7,21,23 and 30 from the above link provided by Dharma, it will be of great help.

                    Thanks.
                    Qn 7 - For every 2 x 2 square grid, the top left square is the sum of the other 3 squares.

                    x = 89 - 35 - 35 = 19
                    Check 9 + 7 + 19 = 35 - ok
                    x = 19

                    Qn 21 - 7 squares

                    http://www.postimage.org/image.php?v=aV12mae0

                    Q23 - X = 7

                    http://www.postimage.org/image.php?v=Ts1UOXA

                    1 Reply Last reply
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                    • F
                      fudgemum
                      last edited by

                      Hi Dharma, Thank you very much for the solutions.

                      1 Reply Last reply
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                      • D
                        Dharma
                        last edited by

                        fudgemum:
                        Hi Dharma, Thank you very much for the solutions.

                        No pbm, fudgemum

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