Tutor MathsGuru: Ask me for your burning Maths questions!

[MathIzzzFun]

MathIzzzFun:

http://i46.tinypic.com/s15mkw.png\">


reposted

cheers.

[Herbie]

MathIzzzFun:

MathIzzzFun:

http://i46.tinypic.com/s15mkw.png\">


reposted

cheers.

Thanks! I have another maths qn but i am not able to upload the pic. =(

[VivianChan]

Hi I need help,


Linda could bake 5 cakes each day. Sally could bake 8 cakes each day. If Sally was sick for 3 days, how many days would she need to bake 12 more cakes than Linda?

Thanks!

[MathIzzzFun]

VivianChan:

Hi I need help,


Linda could bake 5 cakes each day. Sally could bake 8 cakes each day. If Sally was sick for 3 days, how many days would she need to bake 12 more cakes than Linda?

Thanks!

Assuming that both start on the same day and then Sally was sick for 3 days. If they started on different day, the solution will be different.

5 x 3 = 15 ---> Linda would bake 15 more cakes than Sally for the 3 days that Sally was sick.

8 - 5 = 3 --> Sally bake 3 more cakes than Linda every day.
To bake 12 cakes more than Linda, Sally will need to bake (12+15)= 27 more cakes --> 27/3 = 9 days

Sally need to bake for 9 days to have 12 more cakes than Linda
ie Sally bakes for 9 days, Linda bakes for 12 days.

cheers.

[petals73]

Hi pls help


1) the lengh of a rectangle table is 3 times its width. If the length was 2m shorter and the width 80cm wider, a sq table would be formed. What are the dimensions of the rectangular table.

2) mabel had 11m if cloth. She used 7/10m of it to make a dress and 4/5m to make a table cloth. How many meters of cloth was left .

Many thanks

[VivianChan]

MathIzzzFun:

Assuming that both start on the same day and then Sally was sick for 3 days. If they started on different day, the solution will be different.

5 x 3 = 15 ---> Linda would bake 15 more cakes than Sally for the 3 days that Sally was sick.

8 - 5 = 3 --> Sally bake 3 more cakes than Linda every day.
To bake 12 cakes more than Linda, Sally will need to bake (12+15)= 27 more cakes --> 27/3 = 9 days

Sally need to bake for 9 days to have 12 more cakes than Linda
ie Sally bakes for 9 days, Linda bakes for 12 days.

cheers.

Thanks so much! You save my day! Nowsaday poor children have to face these mind cracking problems.

[MathIzzzFun]

petals73:

Hi pls help


1) the lengh of a rectangle table is 3 times its width. If the length was 2m shorter and the width 80cm wider, a sq table would be formed. What are the dimensions of the rectangular table.

2) mabel had 11m if cloth. She used 7/10m of it to make a dress and 4/5m to make a table cloth. How many meters of cloth was left .

Many thanks

1.
If the length was 2m shorter and the width 80cm wider, a square table would be formed --> new length = new width.
So, length is 2m+80cm=280 cm more than the width.
Length --> 3u
Width --> 1u
2u --> 280cm, 1u --> 140cm
Length --> 420 cm, Breadth 140cm

2. subtraction of fractions --> 11 - 7/10 - 4/5

cheers.

[VivianChan]

Hi pls help


Ali left town A and travelled towards town B at speed of 90km/h.
45min later, Muthu left town B and travelled town A at speed of 120km/h.
Town X was halfway between town A and town B. Ali passed town X half an hour after Muthu had passed town X. Both speeds did not change throughout the journey. If Muthu reached town A at 2.45pm, at what time did Ali leave town A?

Thanks!

[MathIzzzFun]

VivianChan:

Hi pls help


Ali left town A and travelled towards town B at speed of 90km/h.
45min later, Muthu left town B and travelled town A at speed of 120km/h.
Town X was halfway between town A and town B. Ali passed town X half an hour after Muthu had passed town X. Both speeds did not change throughout the journey. If Muthu reached town A at 2.45pm, at what time did Ali leave town A?

Thanks!

Hi

points to note:
1-> Distance travelled by Ali fro A to X (midpoint of AB)
= Distance travelled by Muthu from B to X
2-> Muthu took less time to travel from B to X --> 45 min + 30 min = 75 min less.

Ali's speed : Muthu's speed = 90 : 120 --> 3 : 4
Time ratio (of time taken by both to travel AX and BX) of
Ali : Muthu --> 4u : 3u
1u --> 75 min
Time taken by Ali to travel from A to X = 4 x 75 min = 5h
Total time taken by Ali to travel fro A to X = 10h
10h before 2.45pm --> 4.45am
Ali left at 4.45am

cheers.

[VivianChan]

MathIzzzFun:

VivianChan:

Hi pls help


Ali left town A and travelled towards town B at speed of 90km/h.
45min later, Muthu left town B and travelled town A at speed of 120km/h.
Town X was halfway between town A and town B. Ali passed town X half an hour after Muthu had passed town X. Both speeds did not change throughout the journey. If Muthu reached town A at 2.45pm, at what time did Ali leave town A?

Thanks!

Hi

points to note:
1-> Distance travelled by Ali fro A to X (midpoint of AB)
= Distance travelled by Muthu from B to X
2-> Muthu took less time to travel from B to X --> 45 min + 30 min = 75 min less.

Ali's speed : Muthu's speed = 90 : 120 --> 3 : 4
Time ratio (of time taken by both to travel AX and BX) of
Ali : Muthu --> 4u : 3u
1u --> 75 min
Time taken by Ali to travel from A to X = 4 x 75 min = 5h
Total time taken by Ali to travel fro A to X = 10h
10h before 2.45pm --> 4.45am
Ali left at 4.45am

cheers.

Thanks so much! Appreciate it.