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    Q&A - P3 Math

    Scheduled Pinned Locked Moved Primary 3
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    • K Offline
      Keroppi30
      last edited by

      Hi tianzhu


      using your method are we assuming the ratio of one-dollar coins and twenty-cents coins is 2:3

      Hi atutor2001

      The answer to the original question has to be whole numbers too cos P3 hasn’t touch on decimals yet.

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        Keroppi30:

        using your method are we assuming the ratio of one-dollar coins and twenty-cents coins is 2:3
        Hi

        There is no assumption; the solution is based on the information provided in the question.

        When dealing with primary Maths and Science, it’s important to see what they’ve studied in their syllabuses, do not try to go beyond that. See them through the eyes of our young ones.

        In this particular question, we are given that the mass of 2 one-dollar coins is as heavy as 3 twenty-cent coins. What does this mean? Imagine 2 one-dollar coins and as 3 twenty-cent coins put into a box (A group).So, you’ll have a total of 5 coins in a box.

        Next, we are told that there was 50 coins altogether. Therefore, you’ll have 10 such boxes to make up a total of 50 coins.

        The total mass of 50 coins is 600g; therefore the mass per box is 600/10 which is 60g.

        Hope this helps.

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        • A Offline
          atutor2001
          last edited by

          Keroppi30:

          Hi atutor2001

          The answer to the original question has to be whole numbers too cos P3 hasn't touch on decimals yet.
          I agree that the book implicitly expected the answer in whole number.

          However, it is important for the book to state clearly by including a statement, for example : \"The difference in the weight is a whole number\".

          Otherwise, many students develop the wrong impression that all answers must be in \"whole number\". This is a common problem many average students in upper Pr are facing. Whenever they get an answer in fraction (which is actually correct), they thought that it is wrong because they have been getting whole number answers in the past and nobody highlight to them that answers can also be in fraction. Some students even manipulated the working just to get a whole number and end up with a wrong answer.

          It is important for assessment books for lower Pr to state clearly if it only wants answer in \"whole number\" when there are other possible answers. By doing so, it will make the student realise that there are other possible answers that may not be in whole number. In later years, they will have confident to accept answers in \"fraction.\"

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          • K Offline
            Keroppi30
            last edited by

            :thankyou: tianzhu & atutor2001


            I really appreciate your help. I’m not trying to challenge your answers but I’m trying to address the questions raised by my dd. I’m not very good at explaining maths concepts to my dd in fact what I usually do when I encounter such problem sums is I’ll try to obtain the answers via simultaneous equations.

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            • A Offline
              atutor2001
              last edited by

              Keroppi30:
              :... I’m not trying to challenge your answers but I’m trying to address the questions raised by my dd. ....

              Hi Keroppi30

              Don't be too concerned, questioning our proposed answers. In fact, your query sets me thinking. Which is why I modified the question - hoping to find a solution to a more tricky type of math condition where only the whole number solution is allowed but is not explained explicitly in Pr Math. Lets just continue to question when there is ambiguity. It makes math more interesting and \"alive\".

              Regards

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              • F Offline
                fanren
                last edited by

                Hi

                for P3, can we use equation? for example let something be u, let something be w

                then come out with 2 equations and solve the two unknown alphabets…

                thought now school wants students to use reasoning, trial and error or those draw model type,

                please enlighten me! my son going P3 next year

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                • T Offline
                  tianzhu
                  last edited by

                  Keroppi30:

                  I’m not trying to challenge your answers but I’m trying to address the questions raised by my dd.
                  Hi

                  No worries, I’ve stayed long enough in Maths and Science threads to realise that a solution is only useful if it serves its purpose. The person asking the question must be able to understand it for it to be meaningful.

                  A vibrant forum where members offer differing views can only benefit us in the long run. So, we welcome your feedback as it helps to improve ourselves.

                  Best wishes

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                  • D Offline
                    Daddy
                    last edited by

                    HI,


                    A question need help.
                    \" Harry and Frank have 480 cards altogether. After Harry gve 90 cards to Frank, Frank has twice as many cards as Harry. How many cards do the two boys have at first.\"

                    Thanks 🙏

                    1 Reply Last reply Reply Quote 0
                    • M Offline
                      Muffins
                      last edited by

                      Daddy:
                      HI,


                      A question need help.
                      \"Harry and Frank have 480 cards altogether. After Harry gave 90 cards to Frank, Frank has twice as many cards as Harry. How many cards do the two boys have at first.\"

                      Thanks 🙏
                      Hi Daddy, the two boys ALWAYS have 480 cards altogether. THAT DOES NOT CHANGE. So, if Frank has twice as many cards as Harry in the end, there must be three units of cards (2 units of Frank + 1 unit of Harry). So, 3 units = 480. 1 unit = 480/3=160. If Frank had 2 units - 90 cards at first, he had (160 X 2) - 90 = 320 -90 = 230 cards at first. And if Frank had 230 cards at first, Harry had 480 - 230 = 250 cards at first.

                      Regards.

                      1 Reply Last reply Reply Quote 0
                      • T Offline
                        tutor_your_child
                        last edited by

                        Daddy:

                        \" Harry and Frank have 480 cards altogether. After Harry gve 90 cards to Frank, Frank has twice as many cards as Harry. How many cards do the two boys have at first.\"
                        Hi this is a question using 2-step method and model drawing.
                        Draw the \"after\" position first and you will be able to see it clearly.

                        http://www.postimage.org/

                        So each unit represents 160 (=480/3)
                        Harry has 160 after giving 90 to Frank, so Harry has 250 (=160+90) at first
                        Frank has 230 (=480-250) or (160*2=320; 320-90)

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