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    Q&A - P5 Math

    Scheduled Pinned Locked Moved Primary 5
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    • MathIzzzFunM Offline
      MathIzzzFun
      last edited by

      bookwormkids:
      Please help!


      Q2
      The average number of stickers of Paul, Quinn, Roy and Steve is 75. The ratio of the total number of stickers of Paul and Quinn to the ratio of the total number of stickers of Roy and Steve is 7 : 3. The number of Roy's stickers is 1/4 the number of Steve's stickers. What is the average number of stickers of Paul, Quinn and Roy?


      Thank you!
      Total number of stickers --> 75 x 4 = 300

      Paul & Quinn's stickers : Roy & Steve's stickers
      = 7 : 3
      = 210 : 90

      Roy' stickers : Steve's stickers = 1 : 4
      Roy's stickers --> 1/5 x 90 = 18

      Total number of stickers for Paul, Quinn & Roy = 210 + 18 = 228

      Average number of stickers of Paul, Quinn & Roy = 228/3 = 76

      cheers.

      1 Reply Last reply Reply Quote 0
      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        bookwormkids:
        Please help!


        Q1
        There were 920 seats in a concert. The last four rows were priced 70% of the rest of the seats. There were 55 seats each in the last four rows. The total amount collected when all the seats were sold was $25 620. How much was the cost of each seat in the back row?

        Thank you!
        Price of a seat, not in last 4 rows --> 1u
        Price of a seat in last 4 rows --> 0.7u

        Total number of seats in last 4 rows --> 55 x 4 = 220
        Total amount collected for seats in last 4 rows = 220 x 0.7u = 154u

        Total number of seats in other rows = 920-220=700
        total amount collected for seats in other rows = 700 x 1u = 700u

        Total amount collected for all seats = 700u + 154u = 854u

        854u --> $ 25620
        1u --> $30

        Cost of a seat in back row = 0.7 x $30 = $21

        cheers.

        1 Reply Last reply Reply Quote 0
        • B Offline
          bookwormkids
          last edited by

          Hi MathIzzzFun! Thank you so much! shall pass the solutions to my kid to digest them ! ๐Ÿ˜„

          1 Reply Last reply Reply Quote 0
          • L Offline
            lotto
            last edited by

            Xiao Hu:

            Hi Lotto,
            Looks like you are assuming the number of bags bought are multiples of 4. Can it not be multiples of 4? If say, number of bags bought is 6, then free pencil case is 2. So he may have bought 1 more pencil case, then ratio of pencil case to bag is 2/6 = 1/3, which is what the end ratio is. But the starting ratio is not 1/4 (1 free pencil case to 6 bags).

            I don't know how to solve it in any other way though.

            May be gurus like Tianzhu and MathIzzzzFun can help us here?

            Thanks,
            Xiaohu.
            Hi Xiao Hu,

            In Maths, our brain is automatically thinking that it must be a multiple of 4 when we read the question (especially for primary school).

            If you are looking into that type of answer, u might need to do 4 workings (for multiple of 4, multiple of 4 +1, multiple of 4 +2, multiple of 4 +3) and check one by one and end up with 4 solutions too.

            Take it easy! It is not as hard as u think.

            Cheers :celebrate:

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            • U Offline
              Udon
              last edited by

              MathIzzzFun:
              Udon:

              Need help...thanks


              Q2. Peter took 30 minutes to clean his father's car while his elder brother only took 15 minutes to clean it. How long would both of them take to clean the car together?

              It's Average calculation method right? I tried to add and divide but still could not find the answer....


              Two alternate approaches for such questions:

              1) Find LCM of 15 and 30 --> 30
              Suppose cleaning the car represents 30 units of work.

              Then,
              Peter's work rate --> 30 units/ 30 min = 1 unit/min
              Elder brother's work rate --> 30 units/ 15 min = 2 units/ min

              when both clean the car together,
              combined work rate --> 2 units/min + 1 unit/min = 3 units/min

              and time taken to clean the car together = 30 units รท 3 units/ min = 10 min

              2) In 30 min,
              Peter would clean 30/30 = 1 car
              Elder brother would clean 30/15 = 2 cars

              So, they would clean 3 cars together in 30 min
              To clean 1 car together, time taken = 30 min/3 = 10 min

              cheers



              Thank you so much....

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              • Y Offline
                YumYum
                last edited by

                Hi, can someone pls help with this Qn:


                Aaron and Ben shared a sum of $200. Aaron gave 3/5 of what he has to Ben. Ben later gave 1/5 of what he has back to Aaron. They ended up with equal amount of money. How much did Aaron have at first? Thanks.

                1 Reply Last reply Reply Quote 0
                • V Offline
                  verykiasumummy
                  last edited by

                  YumYum:
                  Hi, can someone pls help with this Qn:


                  Aaron and Ben shared a sum of $200. Aaron gave 3/5 of what he has to Ben. Ben later gave 1/5 of what he has back to Aaron. They ended up with equal amount of money. How much did Aaron have at first? Thanks.
                  hi, offering my help :

                  i would use working backwards method.. note that this is internal transfer and constant total.

                  They ended up with equal amount of money.
                  so $200 / 2 = $100

                  Ben later gave 1/5 of what he has back to Aaron.
                  means Ben would have 4/5 left and this 4/5 is $100.
                  4/5 --> $100
                  1/5 --> $25 (Ben gave back to Aaron)
                  5/5 --> $125 (Ben has $125 after Aaron gave him 3/5 of his money)

                  $200 - $125 = $75 (Since Ben has $125 after receiving money from Aaron, Aaron should have $75 left after giving his money to Ben.)

                  Aaron gave 3/5 of what he has to Ben.
                  so Aaron should have 2/5 of money left.
                  2/5 --> $75
                  1/5 --> $37.50
                  5/5 --> $187.50 (Aaron had at first)

                  $200 - $187.50 = $12.50 (Ben had at first)

                  1 Reply Last reply Reply Quote 0
                  • Y Offline
                    YumYum
                    last edited by

                    Verykiasummummy: thanks!

                    1 Reply Last reply Reply Quote 0
                    • V Offline
                      verykiasumummy
                      last edited by

                      YumYum:
                      Verykiasummummy: thanks!

                      welcome... ๐Ÿ˜ƒ

                      1 Reply Last reply Reply Quote 0
                      • Y Offline
                        YumYum
                        last edited by

                        Hi, can anyone pls helpt with this Qn? thanks! http://i48.tinypic.com/10yfg2p.jpg\">

                        1 Reply Last reply Reply Quote 0

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