Q&A - P5 Math

[mama_10]

:thankyou:

[mama_10]

Hi Dazzlego, thank you very much.

I worked out the solution too but not sure if its correct

R S T
?
3 : 2 Total 492

-50% -50% ? Total 326
<74
-------------------------------------------
166

x x+74 166

x+(x+74) = 166
2x=92
x=46
Ryan @ beginning = 46x2=92.

[dazzlego]

mama_10:

Need help on this question too.

Mrs Ho had 2 boxes of oranges.At first, there are 228 more oranges in Box A than in Box B. Mrs Ho then transfers 600 oranges from Box A toBox B. Now, Box B contained 5 times as many oranges as Box A. How many oranges are there ineach box at first?

Thank you.

Easier way to solve this question is to draw the model.
Here is my handdrawing model. Hope it still can be seen and understood

http://i48.tinypic.com/14age4y.jpg\">

4u -> 372 + 600 = 972
1u -> 243
At first,
A: 243 + 600 = 843
B: 243 + 372 = 615



Another way is to assume
At first,
A: 1u + 228
B: 1u

So in the end,
A: 1u - 372
B: 1u + 600

5 x (1u - 372) = 1u + 600
5u - 1860 = 1u + 600
4u = 2460
1u = 615

B: 615
A: 615 + 228 = 843

[dazzlego]

mama_10:

Hi Dazzlego, thank you very much.

I worked out the solution too but not sure if its correct

R S T
?
3 : 2 Total 492

-50% -50% ? Total 326
<74
-------------------------------------------
166

x x+74 166

x+(x+74) = 166
2x=92
x=46
Ryan @ beginning = 46x2=92.

I am not too sure how u get the 166
Btw can P5 use algebra to solve the question?

[MathIzzzFun]

mama_10:

Hi,


Need help on below question :-
Ryan, Sean and Tristan collected a total of 492 bookmarks. Ryan had the least number of bookmarks. At first, the ratio of the number of bookmarks Sean had to the ratio of bookmarks Tristan had was 3:2. After Ryan and Sean each gave away 50% of their bookmarks, Sean had 74 bookmarks more than Ryan. If the three boys had 326 bookmarks left, howmany bookmarks did Ryan have in the beginning?

Thank you.

Sean had 74 bookmarks than Ryan after Ryan and Sean each gave away 50% of their bookmarks
--> Sean had 74 x 2 = 148 more bookmarks than Ryan at first

Number of bookmarks given away by Ryan and Sean
= 492 - 326 = 166 --> 1/2 the total number of bookmarks of Ryan and Sean at first.

At first, Ryan and Sean had a total of 166 x 2 = 332 bookmarks

Ryan's bookmarks --> (332-148)/2 =92

cheers.

[mama_10]

dazzlego:

mama_10:

Hi Dazzlego, thank you very much.

I worked out the solution too but not sure if its correct

R S T
?
3 : 2 Total 492

-50% -50% ? Total 326
<74
-------------------------------------------
166

x x+74 166

x+(x+74) = 166
2x=92
x=46
Ryan @ beginning = 46x2=92.

I am not too sure how u get the 166
Btw can P5 use algebra to solve the question?

492-326=166.

[verykiasumummy]

sorry ya, p5 cannot use algebra… even p6 cannot use algebra to solve problem sums… not recognise…

[chloecube]

wau lau, P5 math is so difficult


DS just completed his P4 math exam ytd and i am looking thru this P5 thread to better prepare him and myself. but reading it makes me sweat...:(

[verykiasumummy]

chloecube:

wau lau, P5 math is so difficult


DS just completed his P4 math exam ytd and i am looking thru this P5 thread to better prepare him and myself. but reading it makes me sweat...:(

dun get so stressed out... relax first before fighting again..

[trytry]

mama_10:

Hi,


Need help on below question :-
Ryan, Sean and Tristan collected a total of 492 bookmarks. Ryan had the least number of bookmarks. At first, the ratio of the number of bookmarks Sean had to the ratio of bookmarks Tristan had was 3:2. After Ryan and Sean each gave away 50% of their bookmarks, Sean had 74 bookmarks more than Ryan. If the three boys had 326 bookmarks left, howmany bookmarks did Ryan have in the beginning?

Thank you.

Model
Before
R[.|.]
S[..|..][..|..][..|..]--->6u
T[..|..][..|..]--->4u

After
R[.|<-74->
S[..|..][..|--->3u
T[..|..][..|..]--->4u

326+74=400----->10u(making R 3u)
1u-->400/10=40

3u=40x3=120
After R--->120-74=46
Before R--->46x2=92