Q&A - P3 Math

[mother777]

jieheng:

tracywham:

Thank you for your answer. I du\\on't quite understand. Where does the 2u and 12u comes from Siti?

Method 1

Siti had 6 times as many apples as David at first

If we assume D --> 1u , then S --> 6u , total (D+S) --> 7u

In the end , they had an equal number of apples

D --> 3.5u and S --> 3.5u after S gave 2.5u to D

2.5u --> 450
1u --> 180

For this method , you will have the decimal points , 3.5u and 2.5u .

Method 2

Siti had 6 times as many apples as David at first

I assume D --> 2u , then S --> 12u , total (D+S) --> 14u

In the end , they had an equal number of apples

D --> 7u and S --> 7u after S gave 5u to D

5u --> 450
1u --> 90

2u --> 2*90 = 180

For this method , you will have the whole numbers , 7u and 5u

Hi,
my DD is in P3 this year and I wonder if kids will be taught in which situation we need to assume 1u or 2u in such questions?

If you have any idea pls help to advise because I am not sure Kids will be taught to handle division with decimal numbers in P3.

[jieheng]

mother777:

jieheng:

[quote=\"tracywham\"]Thank you for your answer. I du\\on't quite understand. Where does the 2u and 12u comes from Siti?

Method 1

Siti had 6 times as many apples as David at first

If we assume D --> 1u , then S --> 6u , total (D+S) --> 7u

In the end , they had an equal number of apples

D --> 3.5u and S --> 3.5u after S gave 2.5u to D

2.5u --> 450
1u --> 180

For this method , you will have the decimal points , 3.5u and 2.5u .

Method 2

Siti had 6 times as many apples as David at first

I assume D --> 2u , then S --> 12u , total (D+S) --> 14u

In the end , they had an equal number of apples

D --> 7u and S --> 7u after S gave 5u to D

5u --> 450
1u --> 90

2u --> 2*90 = 180

For this method , you will have the whole numbers , 7u and 5u

Hi,
my DD is in P3 this year and I wonder if kids will be taught in which situation we need to assume 1u or 2u in such questions?

If you have any idea pls help to advise because I am not sure Kids will be taught to handle division with decimal numbers in P3.[/quote]Hi ,

If the question is
A had 6 times as many apples as B at first ................In the end , they had an equal number of apples.

It is better to make assumptions for A and B that their total no to be multiples of 2 .

First , assume B as 1u , then A --> 6u but their total no will be 7u which is not the multiples of 2.

Next , assume B as 2u , then A --> 12u and their total no will be 14u which is the multiples of 2.

[mother777]

Hi JieHeng,

Ok I understand the concept now.
thanks for the clear explanation

[angel]

Hi, I need help in solving this problem sum.


Elson has less than 40 sweets in a box.
When he ties the sweets in packets of 6, he has 2 sweets left.
When he ties them in packets of 8, he is short of 2 sweets.
How many sweets does he have in the box?

Thank you.

[mother777]

Multiples of 6: 6,12,18,24,36

Add 2. : 8,14,20,26,38

Multiples of 8: 8,16,24,32,40
Minus 2. : 6,14,22,30,38

Is it answer could be 14 or 38?

[angel]

mother777:

Multiples of 6: 6,12,18,24,36

Add 2. : 8,14,20,26,38

Multiples of 8: 8,16,24,32,40
Minus 2. : 6,14,22,30,38

Is it answer could be 14 or 38?

Thank you mother 777.

[Steadyberry]

Hi


Pls kindly help. I just do not get it why the number of muffins that jennifer has is 49 (answer is $21).

Grace baked 99 muffins. If Grace gives Jennifer 25 muffins, they will both have the same number of muffins. Jennifer then sold her muffins at 7 for $3. How much did Jennifer collect from the sale of her muffins?

Pls draw model if possible. Thank you.

[mother777]

G [ U][25][25]

J [ U][25]
Grace at first = 99
Grace gives Jennifer 25 and they become equal right? so draw something like drawn above.

so the from the model we can infer that,
Jennifer at first –>99-25-25
= 49

this is how you get 49 for Jennifer…

sorry workign from office, no time to upload drawing…

[qms]

mother777:

G [ U][25][25]

J [ U][25]
Grace at first = 99
Grace gives Jennifer 25 and they become equal right? so draw something like drawn above.

so the from the model we can infer that,
Jennifer at first -->99-25-25
= 49

this is how you get 49 for Jennifer..

sorry workign from office, no time to upload drawing..

Yes, Jennifer initially had 49. But, the question says that Grace gave Jennifer 25 muffins. Jennifer then sold the muffins at 7 for $3, meaning Jennifer should also sell the 25 muffins given by Grace. So, if I am not wrong, Steadyberry's question is that why weren't the 25 muffins included in the sale?

[Steadyberry]

qms:

mother777:

G [ U][25][25]

J [ U][25]
Grace at first = 99
Grace gives Jennifer 25 and they become equal right? so draw something like drawn above.

so the from the model we can infer that,
Jennifer at first -->99-25-25
= 49

this is how you get 49 for Jennifer..

sorry workign from office, no time to upload drawing..

Yes, Jennifer initially had 49. But, the question says that Grace gave
Jennifer 25 muffins. Jennifer then sold the muffins at 7 for $3, meaning Jennifer should also sell the 25 muffins given by Grace. So, if I am not wrong, Steadyberry's question is that why weren't the 25 muffins included in the sale?

Hi mother777, qms

Thks for replying. Qms is right. My question is why the 25 muffins were not included? I am :?

This question was taken from P3 Distinction in Maths by just Ed revision 1 section C no 45.