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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • A Offline
      AbiSuresh
      last edited by

      Hi Maths guru,

      There were some sweets in Boxes A, B and C. Box A contained 1/7 of the total number of sweets in Boxes B and C.
      The ratio of the number of sweets in Box B to the total number of sweets in Boxes A and C is 3:1.
      If there are 30 more sweets in Box B than Box A, find the total number of sweets in Boxes A, B and C.

      1 Reply Last reply Reply Quote 0
      • MathIzzzFunM Offline
        MathIzzzFun
        last edited by

        AbiSuresh:
        Hi Maths guru,

        There were some sweets in Boxes A, B and C. Box A contained 1/7 of the total number of sweets in Boxes B and C.
        The ratio of the number of sweets in Box B to the total number of sweets in Boxes A and C is 3:1.
        If there are 30 more sweets in Box B than Box A, find the total number of sweets in Boxes A, B and C.
        Box A --> 1/8 of total number of sweets -- (A --> 1 part, B&C --> 7 parts, total --> 8 parts)

        Box B --> 3/4 of total number of sweets -- (B --> 3 units, A&C --> 1 unit, total --> 4 units)

        1 - 1/8 - 3/4 = 1/8

        Box C --> 1/8 of total number of sweets

        There are 30 more sweets in B than in A,

        3/4 - /18 = 5/8

        5/8 of total number of sweets --> 30
        Total number of sweets --> 8/5 x 30 = 48 sweets.

        cheers.

        1 Reply Last reply Reply Quote 0
        • E Offline
          elishatan
          last edited by

          #1

          http://elishatan.com/wp-content/uploads/2013/05/Evernote-Camera-Roll-20130506-142936-e1367824091265.jpg\">

          #2
          http://elishatan.com/wp-content/uploads/2013/05/Evernote-Camera-Roll-20130506-142928-e1367824147306.jpg\">

          #3
          http://elishatan.com/wp-content/uploads/2013/05/Evernote-Camera-Roll-20130506-142852-e1367824206891.jpg\">

          #4
          http://elishatan.com/wp-content/uploads/2013/05/Everno1te-Camera-Roll-20130506-142844-e1367824273638.jpg\">

          1 Reply Last reply Reply Quote 0
          • A Offline
            AbiSuresh
            last edited by

            Thank you very much

            MathIzzzFun:
            AbiSuresh:

            Hi Maths guru,
            There were some sweets in Boxes A, B and C. Box A contained 1/7 of the total number of sweets in Boxes B and C.
            The ratio of the number of sweets in Box B to the total number of sweets in Boxes A and C is 3:1.
            If there are 30 more sweets in Box B than Box A, find the total number of sweets in Boxes A, B and C.

            Box A --> 1/8 of total number of sweets -- (A --> 1 part, B&C --> 7 parts, total --> 8 parts)

            Box B --> 3/4 of total number of sweets -- (B --> 3 units, A&C --> 1 unit, total --> 4 units)

            1 - 1/8 - 3/4 = 1/8

            Box C --> 1/8 of total number of sweets

            There are 30 more sweets in B than in A,

            3/4 - /18 = 5/8

            5/8 of total number of sweets --> 30
            Total number of sweets --> 8/5 x 30 = 48 sweets.

            cheers.

            1 Reply Last reply Reply Quote 0
            • H Offline
              hands on blessed mum
              last edited by

              Hi, need your help to solve this question;

              1 Reply Last reply Reply Quote 0
              • N Offline
                NYPSkiasuparent
                last edited by

                atutor2001:
                suiyuan:


                Hi
                Thank you for your offer.

                1)During a warehouse book sale, Sally spent 62.5% of her money on 24 books and 18 pens. She also spent 25% of her remaining money on 18 files. Each pen costs 8/9 as much as the price of one book. The file costs $7.80 less than a book. Find the total cost of one book and one pen.

                2)Mr Lim spent $1496 on some comics and dictionaries altogether. The number of comics bought to the number of dictionaries bought was in the ratio of 3 : 2. A dictionary cost $4 more than a comic. The total cost of the comics was 20% more than the total cost of the dictionaries. Find the cost of a dictionary.

                Hi suiyuan

                You are very \"naughty\". But the 2nd question is a bit easssy!

                Regards

                Why is she naughty?

                1 Reply Last reply Reply Quote 0
                • jkidsJ Offline
                  jkids
                  last edited by

                  hi maths guru

                  I need some advice, not on problem sums but rather can you recommend an enrichment centre for my child? he is weak in maths, others subjects lik eng and Chinese is ok. recently he failed his maths, got 27/70 😞

                  he seem to have prob understanding the math q, esp prob sums. what goes wrong, I really duno. we need to explain a few times, but sometime he still dun get it. he only has eng tuition but we intend to withdraw him fr eng class and enrol him for math class. can you recommend? I saw a few...cma , mind matter, mind stretcher...but dun really noe which is a better one...

                  thanks..

                  1 Reply Last reply Reply Quote 0
                  • M Offline
                    milo-cupcake
                    last edited by

                    Hi Maths guru,

                    This is my DD recently SA1 Maths question. My DD and her classmates answer was 180 but the answer given by the teacher was 120. Please can you tell whose answer is correct?
                    Thanks in advance!

                    http://i44.tinypic.com/30igcd2.jpg\">

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                    • MathIzzzFunM Offline
                      MathIzzzFun
                      last edited by

                      milo-cupcake:
                      Hi Maths guru,

                      This is my DD recently SA1 Maths question. My DD and her classmates answer was 180 but the answer given by the teacher was 120. Please can you tell whose answer is correct?
                      Thanks in advance!

                      http://i44.tinypic.com/30igcd2.jpg\">
                      in both cases, the fraction refers to the original number as whole, so the answer is 120

                      However, if the second sentence is:\"On the second day, he sold 1/3 of the remaining watermelons....\" then the answer will be 180

                      cheers.

                      1 Reply Last reply Reply Quote 0
                      • A Offline
                        Arrmanas
                        last edited by

                        450 - (2/5 x 450) - (1/3 x 450) = 120


                        The tricky part is "1/3 of his watermelons".

                        If the question says "1/3 of the balance watermelons" then the last calculation would be [1/3 x ((450 - (2/5 x 450)) = 90]. This gives 180 as the answer.

                        1 Reply Last reply Reply Quote 0

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