Q&A - P4 Math

[rocklee]

Hi MathsIzzzfun


Thanks for your solution.

[MathIzzzFun]

rocklee:

Hi MathsIzzzfun


Thanks for your solution.

u r welcome

cheers.

[usaik]

Hello,

I need help on the working as to how to solve the following question. The answer provided is 117 cm2. Thank you so much!

http://i52.tinypic.com/slsa2s.jpg\">

[MathIzzzFun]

usaik:

Hello,

I need help on the working as to how to solve the following question. The answer provided is 117 cm2. Thank you so much!

http://i52.tinypic.com/slsa2s.jpg\">

Hi

Find the common factors for 102 and 54...

54 = 1 x 2 x 3 x 3 x 3 = 6 x 9
102 = 1 x 2 x 3 x 17 = 6 x 17

Since each side of W is a whole number, each side = 6 cm, area = 36 cm2
So, area of V = 17 x 9 = 153 cm2
V-W= 153 - 36 = 117 cm2

cheers.

[chokos]

@ Tianzhu

Thank you very much.

[usaik]

MathIzzzFun:

Hi

Find the common factors for 102 and 54...

54 = 1 x 2 x 3 x 3 x 3 = 6 x 9
102 = 1 x 2 x 3 x 17 = 6 x 17

Since each side of W is a whole number, each side = 6 cm, area = 36 cm2
So, area of V = 17 x 9 = 153 cm2
V-W= 153 - 36 = 117 cm2

cheers.

Hi MathIzzzFun,
Thank you for the working!
Regards.

[MathIzzzFun]

usaik:

MathIzzzFun:

Hi

Find the common factors for 102 and 54...

54 = 1 x 2 x 3 x 3 x 3 = 6 x 9
102 = 1 x 2 x 3 x 17 = 6 x 17

Since each side of W is a whole number, each side = 6 cm, area = 36 cm2
So, area of V = 17 x 9 = 153 cm2
V-W= 153 - 36 = 117 cm2

cheers.

Hi MathIzzzFun,
Thank you for the working!
Regards.

u r welcome

cheers.

[pineapple tarts]

hello, can someone help with this pls


Ali has 3 times as many stickers as Mohan. If Ali gives 165 stickers to Mohan, he will have ½ as many stickers as Mohan. How many stickers do they have altogether?

Many thanks in advance.

[PiggyLalala]

One possible approach: Using units and parts:

A: M = 3u : 1u = 9u: 3u
A: M = 1p : 2p = 4p: 8p
Total remains the same:
Therefore 12u = 12p, that is u = p
Therefore (before) A:M = 9u:3u
(after) A: M = 4u:8u
Therefore 5u = 165
u= 33
Total = 12u = 396 stickers

[usaik]

Another possible approach would be using model as below :

http://i54.tinypic.com/rbjxh3.jpg\">