Q&A - P5 Math

[happyheart]

tianzhu:

happyheart:

Thank you Tianzhu for answering this question. Sorry, I am trying to understand but just cannot get it. In the 2nd round, how do we establish the number of cards Muthu has? Could you explain further?

Hi

For the second transfer
2 units (2/3) -------- 660
3 units (3/3) -------- 990

Next, the first transfer
3 units (3/4) -------- 174
4 units (4/4) -------- 232

Best wishes

Tianzhu, I learnt your method and managed to solve another similar question! Thank you!

[cimman]

happyheart:

Hi, I need help on this...please help with illustration. I am confused with multiple variables and the 3 equations. Thank you!


The cost of 6 identical chairs , 5 identical lamps and 1 table is $380.
The cost of 2 such chairs and 1 table is $188, while 1 chair and 1 lamp cost $44.
a) What is the cost of 1 chair and 1 table?
b) What is the total cost of 1 table, 1 lamp and 1 chair?

if you use a table, it will be easier to see the relationships:
first put all the equations into a table (I should put l for lamps, but l looks like a 1 or I, so I use p to represent unit cost for lamps) :
http://i47.tinypic.com/35ba3ys.png\">

next fill up the blank boxes with zeros and determine which variable you want or don't want by putting a tick and cross in the right places:
http://i50.tinypic.com/2vm94iv.png\">

substitute p and solve for c + t
http://i48.tinypic.com/24o8xg5.png\">

put in the new equation (c + t) into the table:
http://i50.tinypic.com/289lrgw.png\">

this is a possible way:
http://i47.tinypic.com/14p9o9.png\">

there are other ways, you can use equation 2 - equation 3, here I'm using equation 2 - equation 4, which I think is easier to \"see\":
http://i46.tinypic.com/2q15hlh.png\">

c = 28. Once you have the value of c, you can find t and p.

[chloecube]

i hope its not to confusing for u,


6C + 5L + 1T = 380 —Equation 1
2C + 1T = 188 —Equation 2
1C + 1L = 44 —Equation 3

Equation 1 - Equation 3
5C + 4L + 1T = 336—Equation 4

Equation 2 + Equation 3
3C + 1L + 1T = 232—Equation 5

Equation 4 - Equation 5
2C + 3L = 104

Equation 3 (x2)
2C + 2L = 88

from above, u can find out that 1L = 16
1C = 44-16=28
6C + 5L + 1T = 380
168 + 80 + 1T = 380
1T = 132

[YumYum]

Hi, can someone pls help with this qn:


Tony and Sam each have some money. If Tony spends $80 per day and Sam spreads $40 per day, Tony will have $500 left when Sam has spent all his money. If Tony spent $40 each day and Sam spent $80 each day, Tony will have $1100 left when Sam has spent all his money. Find the amount of money Sam has.

Thanks

[tianzhu]

YumYum:

Hi, can someone pls help with this qn:


Tony and Sam each have some money. If Tony spends $80 per day and Sam spreads $40 per day, Tony will have $500 left when Sam has spent all his money. If Tony spent $40 each day and Sam spent $80 each day, Tony will have $1100 left when Sam has spent all his money. Find the amount of money Sam has.

Thanks

Hi

Please refer to this similar type of question.

You may apply the same strategy to your question.

Best wishes

http://farm6.static.flickr.com/5142/5614468685_555807d62e_z.jpg\">

[YumYum]

tianzhu:

YumYum:

Hi, can someone pls help with this qn:


Tony and Sam each have some money. If Tony spends $80 per day and Sam spreads $40 per day, Tony will have $500 left when Sam has spent all his money. If Tony spent $40 each day and Sam spent $80 each day, Tony will have $1100 left when Sam has spent all his money. Find the amount of money Sam has.

Thanks

Hi

Please refer to this similar type of question.

You may apply the same strategy to your question.



Hi Tianzhu,

Thank you for yr usual help.

Best wishes

http://farm6.static.flickr.com/5142/5614468685_555807d62e_z.jpg\">

[the shadowed snake]

Hi how to do this


In a bus, there were 40% as many children as adults. After 22 adults alighted from the bus the percentage of the children increased to 60%. How many children were there in the bus?

[php]

the shadowed snake:

Hi how to do this


In a bus, there were 40% as many children as adults. After 22 adults alighted from the bus the percentage of the children increased to 60%. How many children were there in the bus?

Before : C --> 7u x 3 = 21u A --> 5u x 3 = 15u
After : C --> 3p x 7 = 21u A --> 2p x 7 = 14u

1u = 22
21u = 22x21 = 462

[happyheart]

cimman:

happyheart:

Hi, I need help on this...please help with illustration. I am confused with multiple variables and the 3 equations. Thank you!


The cost of 6 identical chairs , 5 identical lamps and 1 table is $380.
The cost of 2 such chairs and 1 table is $188, while 1 chair and 1 lamp cost $44.
a) What is the cost of 1 chair and 1 table?
b) What is the total cost of 1 table, 1 lamp and 1 chair?

if you use a table, it will be easier to see the relationships:
first put all the equations into a table (I should put l for lamps, but l looks like a 1 or I, so I use p to represent unit cost for lamps) :
http://i47.tinypic.com/35ba3ys.png\">

next fill up the blank boxes with zeros and determine which variable you want or don't want by putting a tick and cross in the right places:
http://i50.tinypic.com/2vm94iv.png\">

substitute p and solve for c + t
http://i48.tinypic.com/24o8xg5.png\">

put in the new equation (c + t) into the table:
http://i50.tinypic.com/289lrgw.png\">

this is a possible way:
http://i47.tinypic.com/14p9o9.png\">

there are other ways, you can use equation 2 - equation 3, here I'm using equation 2 - equation 4, which I think is easier to \"see\":
http://i46.tinypic.com/2q15hlh.png\">

c = 28. Once you have the value of c, you can find t and p.

Thank you Cimman, that is one way to look at it. Much appreciated!

[happyheart]

chloecube:

i hope its not to confusing for u,


6C + 5L + 1T = 380 ---Equation 1
2C + 1T = 188 ---Equation 2
1C + 1L = 44 ---Equation 3

Equation 1 - Equation 3
5C + 4L + 1T = 336---Equation 4

Equation 2 + Equation 3
3C + 1L + 1T = 232---Equation 5

Equation 4 - Equation 5
2C + 3L = 104

Equation 3 (x2)
2C + 2L = 88

from above, u can find out that 1L = 16
1C = 44-16=28
6C + 5L + 1T = 380
168 + 80 + 1T = 380
1T = 132

Yes, I can understand this one. The challenge I faced earlier was to first break down the various equations. Thank you.