verykiasumummy:

using another magnet to chk if it repels is not required to confirm if they have become temperary magnets, (only when u need to confirm an object is a magnet, as in permanent magnet) because temporary magnets are just for short term, so the repulsion may not be guaranteed.

:thankyou: :lovesite:

verykiasumummy:

Tiramisu Coco:

Hi, need help for part (b) of this qtn. Thk u.


http://www.flickr.com/photos/82618212@N07/8005317651

hi Tiramisu Coco,

a temporary magnet will be able to attract paper clips once they have been magnetised but will soon lose its magnetism after some time. if the steel rods were able to attract paper clips after they have been stroked many times, they have become temperory magnet..

hope this helps..

Thks for the reply verykiasumummy. The qtn ask how to confirm if the two steel rods hv become temporary magnets. My query is, do we use a magnet to check or can we use the same poles of the two steel rods to chk if they repel each other? Very confused, hope someone can clarify. Thk u.

Hi, need help for part (b) of this qtn. Thk u.


http://www.flickr.com/photos/82618212@N07/8005317651

MathIzzzFun:

Tiramisu Coco:

Hi tianzhu, here's the link to the qtn. TIA


http://m.flickr.com/#/photos/82618212@N07/7837766706/

http://i47.tinypic.com/rucz06.png\">

cheers.

:thankyou: MathIzzzFun

Hi tianzhu, here's the link to the qtn. TIA


http://m.flickr.com/#/photos/82618212@N07/7837766706/

tianzhu:

Tiramisu Coco:

Hi Tianzhu, thks for your reply.

This qtn has not been discussed before, think u refer to the wrong qtn on the photostream. It's the last item abt ABCD is a square of 20cm. E & F are the mid-points of AB & AD. Find area of shaded region.
Would appreciate your help for this qtn. TIA

Hi

When I clicked on your link, all I could see was a circle inscribed in a triangle.

Based on your description, perhaps this question may help.

Q15 of this paper, please go to page 35 of this link.

http://www.orlesson.org/orp/10Ma/2010-P6-Math-SA2-Rosyth.pdf


Best wishes.

http://farm5.staticflickr.com/4103/5037820252_8aa41e056c_z.jpg\">

Gd morning, tianzhu! Thks for the reply. I used similar approach to solve my qtn but still not able to get the ans given: 266 2/3 cm2. Can guide me the steps to solve? Thk u.

tianzhu:

Tiramisu Coco:

Hi, pls help with this qtn. Thks!


http://m.flickr.com/photos/82618212@N07/7837766706/lightbox/

Hi

A similar question has been discussed in one of the earlier posts, but I can't locate it now.

There are a few ways to solve it.

One possible way.

Radius of circle -------( a+b-c)/2 -------(18+24-30)/2 ------ 6 cm

Best wishes

Hi Tianzhu, thks for your reply.
This qtn has not been discussed before, think u refer to the wrong qtn on the photostream. It's the last item abt ABCD is a square of 20cm. E & F are the mid-points of AB & AD. Find area of shaded region.
Would appreciate your help for this qtn. TIA

Hi, pls help with this qtn. Thks!


http://m.flickr.com/photos/82618212@N07/7837766706/lightbox/

tianzhu:

Hi


Another way to look at your question.

Please refer to MathIzzzFun ‘s diagram.

From the centre of the circle o, draw three lines to touch A,B and C of the triangle.

This will give you 3 smaller triangles of height equal to radius r.

Area of triangle ABC ------ ½*18*24 ------- 216

Area of triangle AOC ------ ½*18*r ------ 9r

Area of triangle AOB ------ ½*24*r ------ 12r

Area of triangle BOC ------ ½*30*r ------ 15r

9r+12r+15r ------- 36r

36r ------ 216

r ------- 6

Best wishes

Hi,
Thks MathIzzzFun for explaining the equation (24-r)+(18-r)=30 with a diagram to illustrate. Thk u tianzhu for the effort to come out with the 2nd solution (dividing the original triangle into 3 different triangles with height =r). Really thankful to both of you for your time and effort. I'm now able to accept this as a P6 maths qtn.

:thankyou:

MathIzzzFun:

Tiramisu Coco:

[quote=\"tianzhu\"]Hi, need help for this qtn.

Thank u.

http://www.flickr.com/photos/82618212@N07/7568230484

Hi

Good Morning.

Where is this question from?

It should be a breeze for secondary school students who have knowledge about tangential properties.

For primary schools, it might pose some challenges.

I think one way is show is to use a pair of compasses, draw two arcs from the centre of the circle to touch the longest side of the triangle (30 cm), say at a point X.

(24 – r ) + (18 – r) ------- 30

r + r ------- 42 – 30

r ------- 12/2 ------- 6

Try it out.

Hope this helps.

Best wishes

Hi Tianzhu,
Thks for your solution.
Pls enlighten why is
(24-r)+(18-r) --- 30?

Thks!

Hi

This is not a standard P6/PSLE question - more likely a competition question, because this requires student to know properties of tangent, congruent triangles.

http://i46.tinypic.com/219bfx2.png\">

BY=BZ (by congruent triangles: OY=OZ, OB=OB, angle OZB=angle OYB=90 deg)
CX=CZ (by congruent triangles)
BY+CX = BZ + CZ
24-R + 18-R = 30, R --> radius of circle

cheers.[/quote]Hi tianzhu & MathIzzzfun,
Thks for your help.
A friend shared this qtn that she got from a pri maths tuition ctr's FB pg, which stated that to solve the qtn, students need to draw lines, use ratio & unit transfer method(2 variables concepts). Wonder if it's relevant for p6 to know how to solve this type of qtns.