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Vanilla Cake:

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Hi


Pls help with this question.Thanks

Gibson had 50-dollar, 20-dollar and 10-dollar tickets for a school funfair in the ratio 1:5:4.
The total value of the funfair tickets was $3420.
a) Find the no. of each type of tickets he had.
b) After selling 1/4 of the 10-dollar tickets and a few 20-dollar tickets, he found that 2/11 of the remaining tickets were 50-dollar tickets.
How many 20-dollar tickets did he sell?

TIA

This question was first posted by firebird on 28 Mar 2010 02:46 and had been answered by http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&postdays=0&postorder=asc&start=700 on Wed Mar 31, 2010 3:16 pm and http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=6373&postdays=0&postorder=asc&start=660 on 28 Mar 2010 08:31 .

Hi VC

Thanks for your help

[Herbie]

Thanks VC, Dharma and David59

[Maths Monster]

delete

[ruyu]

how to solve this question? Please refer to the picture

http://www.postimage.org/image.php?v=gx8yjDi

[Vanilla Cake]

ruyu:

how to solve this question? Please refer to the picture

http://www.postimage.org/image.php?v=gx8yjDi

T starts at point C
W starts at point F

T : W
1.5 : 1
3 : 2

Think of each side of the hexagon track as 1 unit.
Example:
1st Time
T: Point F
W: Point B

2nd Time
T: Point C
W: Point D

3rd time
T: Point F
W: Point F

(a) They will meet at point F.

Wilson ran for (6x0.5) km = 3 km
20 min for 3 km
60 min for 9 km
1.5x9 = 13.5 km/h

(b) Tommy's speed is 13.5 km/h.

[ruyu]

Vanilla Cake:

ruyu:

how to solve this question? Please refer to the picture

http://www.postimage.org/image.php?v=gx8yjDi

T starts at point C
W starts at point F

T : W
1.5 : 1
3 : 2

Think of each side of the hexagon track as 1 unit.
Example:
1st Time






2nd Time
T: Point C
W: Point D

3rd time
T: Point F
W: Point F

(a) They will meet at point F.

Wilson ran for (6x0.5) km = 3 km
20 min for 3 km
60 min for 9 km
1.5x9 = 13.5 km/h

(b) Tommy's speed is 13.5 km/h.

thanks at first i thought for every 3 sides T ran W ran 1 soo stupid of me btw thank you very much!
T: Point F
W: Point B

[CoffeeCat]

ruyu:

how to solve this question? Please refer to the picture

http://www.postimage.org/image.php?v=gx8yjDi

the key insight to solve such questions is that the extra speed (translates to extra distance covered per unit time) is used to catch up with another moving object ahead. Wilson is 3 hexagon sides ahead of Tommy. If Tommy's speed is 1.5 times that of Wilson, it means for every 1 hexagon side Wilson covers, Tommy will cover 1.5 hexagon sides, thus being 0.5 hexagon side nearer Wilson whenever wilson covers a hexagon side.
So therefore to meet, Tommy must cover 3 extra hexagon sides, meaning wilson will have covered 6 hexagon sides. Therefore they will meet at pt f.

I believe you should be able to do part b from here.

[ruyu]

A car and a van were travelling in opposite directions at speeds of 80km/h and 60km/h respectively. The car was travelling from Town A to Town B while the Van was travelling form Town B to Town A. At what time would the pass each other?

[Lynn1967]

This is 2008 RGS SA1 qn. Anyone has the answers as I have misplaced it.


Many thanks.

At 9am, a van left Town P for Town Q. After some time, a car left Town Q for Town P. The 2 vehicles met at 11.30am. The ratio of the speed of the van to the speed of the car is 3:5.

a) What time did the car leave Town Q?
b) If the distance between Town P and Town Q is 150km, calculate the average speed of the van.

[Dharma]

Lynn1967:

This is 2008 RGS SA1 qn. Anyone has the answers as I have misplaced it.


Many thanks.

At 9am, a van left Town P for Town Q. After some time, a car left Town Q for Town P. The 2 vehicles met at 11.30am. The ratio of the speed of the van to the speed of the car is 3:5.

a) What time did the car leave Town Q?
b) If the distance between Town P and Town Q is 150km, calculate the average speed of the van.

Hi Lynn1967,

There is a missing word as highlighted in bold in qn below.


At 9am, a van left Town P for Town Q. After some time, a car left Town Q for Town P. The 2 vehicles met midway at 11.30am. The ratio of the speed of the van to the speed of the car is 3:5.

a) What time did the car leave Town Q?
b) If the distance between Town P and Town Q is 150km, calculate the average speed of the van.

Speed ratio of van to car = 3 : 5
Time ratio of van to car 5 : 3

a)
5u = 2.5hrs
1u = 0.5hrs
Car will take 3u = 3 x 0.5 hrs = 1.5 hrs
Car left Town Q at 1.5 hrs before 11.30am ( i.e. 10.00am)

b)
Average speed of van = 75km/2.5hrs = 30km/hr