Tutor MathsGuru: Ask me for your burning Maths questions!
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ruyu:
T starts at point Chow to solve this question? Please refer to the picture
http://www.postimage.org/image.php?v=gx8yjDi
W starts at point F
T : W
1.5 : 1
3 : 2
Think of each side of the hexagon track as 1 unit.
Example:
1st Time
T: Point F
W: Point B
2nd Time
T: Point C
W: Point D
3rd time
T: Point F
W: Point F
(a) They will meet at point F.
Wilson ran for (6x0.5) km = 3 km
20 min for 3 km
60 min for 9 km
1.5x9 = 13.5 km/h
(b) Tommy's speed is 13.5 km/h. -
Vanilla Cake:
T starts at point Cruyu:
how to solve this question? Please refer to the picture
http://www.postimage.org/image.php?v=gx8yjDi
W starts at point F
T : W
1.5 : 1
3 : 2
Think of each side of the hexagon track as 1 unit.
Example:
1st Time
2nd Time
T: Point C
W: Point D
3rd time
T: Point F
W: Point F
(a) They will meet at point F.
Wilson ran for (6x0.5) km = 3 km
20 min for 3 km
60 min for 9 km
1.5x9 = 13.5 km/h
(b) Tommy's speed is 13.5 km/h.
thanks at first i thought for every 3 sides T ran W ran 1 soo stupid of me btw thank you very much!
T: Point F
W: Point B -
ruyu:
the key insight to solve such questions is that the extra speed (translates to extra distance covered per unit time) is used to catch up with another moving object ahead. Wilson is 3 hexagon sides ahead of Tommy. If Tommy's speed is 1.5 times that of Wilson, it means for every 1 hexagon side Wilson covers, Tommy will cover 1.5 hexagon sides, thus being 0.5 hexagon side nearer Wilson whenever wilson covers a hexagon side.how to solve this question? Please refer to the picture
http://www.postimage.org/image.php?v=gx8yjDi
So therefore to meet, Tommy must cover 3 extra hexagon sides, meaning wilson will have covered 6 hexagon sides. Therefore they will meet at pt f.
I believe you should be able to do part b from here. -
A car and a van were travelling in opposite directions at speeds of 80km/h and 60km/h respectively. The car was travelling from Town A to Town B while the Van was travelling form Town B to Town A. At what time would the pass each other?
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This is 2008 RGS SA1 qn. Anyone has the answers as I have misplaced it.
Many thanks.
At 9am, a van left Town P for Town Q. After some time, a car left Town Q for Town P. The 2 vehicles met at 11.30am. The ratio of the speed of the van to the speed of the car is 3:5.
a) What time did the car leave Town Q?
b) If the distance between Town P and Town Q is 150km, calculate the average speed of the van. -
Lynn1967:
Hi Lynn1967,This is 2008 RGS SA1 qn. Anyone has the answers as I have misplaced it.
Many thanks.
At 9am, a van left Town P for Town Q. After some time, a car left Town Q for Town P. The 2 vehicles met at 11.30am. The ratio of the speed of the van to the speed of the car is 3:5.
a) What time did the car leave Town Q?
b) If the distance between Town P and Town Q is 150km, calculate the average speed of the van.
There is a missing word as highlighted in bold in qn below.
At 9am, a van left Town P for Town Q. After some time, a car left Town Q for Town P. The 2 vehicles met midway at 11.30am. The ratio of the speed of the van to the speed of the car is 3:5.
a) What time did the car leave Town Q?
b) If the distance between Town P and Town Q is 150km, calculate the average speed of the van.
Speed ratio of van to car = 3 : 5
Time ratio of van to car 5 : 3
a)
5u = 2.5hrs
1u = 0.5hrs
Car will take 3u = 3 x 0.5 hrs = 1.5 hrs
Car left Town Q at 1.5 hrs before 11.30am ( i.e. 10.00am)
b)
Average speed of van = 75km/2.5hrs = 30km/hr -
Thanks Dharma for your prompt reply.
I cracked my brains becos the copy I had was without the word midpoint.
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Suzy bought 12 stickers from Singapura Bookshop. The price of each sticker was the same. If the price of 1 sticker was cheaper by 5-cents, she could have bought4 more stickers at the cheaper price. How much did she spend on 12 stickers?
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ruyu:
Suzy bought 12 stickers from Singapura Bookshop. The price of each sticker was the same. If the price of 1 sticker was cheaper by 5-cents, she could have bought4 more stickers at the cheaper price. How much did she spend on 12 stickers?
Cost of 12 stickers = 12(1u)
12(1u) = 11(1u) + 5(1u - 5 cents)
4u = 25 cents
1u = 6.25 cents
12 stickers cost = 12 x 6.25 cents = 75 cents -
Dharma:
ruyu:
Suzy bought 12 stickers from Singapura Bookshop. The price of each sticker was the same. If the price of 1 sticker was cheaper by 5-cents, she could have bought4 more stickers at the cheaper price. How much did she spend on 12 stickers?
Cost of 12 stickers = 12(1u)
12(1u) = 11(1u) + 5(1u - 5 cents)
4u = 25 cents
1u = 6.25 cents
12 stickers cost = 12 x 6.25 cents = 75 cents
dont understand :?
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