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    Q&A - PSLE Math

    Scheduled Pinned Locked Moved Primary 6 & PSLE
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    • A Offline
      atutor2001
      last edited by

      Vanilla Cake:
      tianzhu:

      [quote]Well,ratio problems are supposed to be solved by ratio.I love using ratio but i'm always stuck at challenging questions that involve ratio.One quick(inaccurate) example is this: The marbles that A and B has is in the ratio 6:7. Then,124 marbles were added to the total and the ratio became 2:3.How many marbles were there at first? These kind of questions are common and its almost impossible to solve using model. If your dd knows how to use ratio to solve such challenging problems,then your dd should be alright if she wants to use model now as she still have the \"skills\" to apply the ratio method if she needs it.However,if she cannot solve using ratio,then she may face difficulty with the challenging questions.


      Hi

      I picked up this quote from the thread, Tips for improving in PSLE. It was from a member called livewith_vanilla.

      I think the question she posed is a pretty interesting one, it involves two changed quantities, but the number(124) involved in the transaction is lumped into one lot instead of two different portions.

      The marbles that A and B has is in the ratio 6:7. Then,124 marbles were added to the total and the ratio became 2:3.How many marbles were there at first?

      Have fun.
      Best wishes

      Hi Uncle Tianzhu,
      There seems to be more than one possible correct answer for this question. I have posted a reply to \"livewith_vanilla\" to seek her clarification for this \"One quick(inaccurate) example is this:.....\"[/quote]I remember seeing this question in Andrew Er's assessment book.

      It is true mathematically that if we have only 1 equation with 2 unknowns, then the number of answers can be infinite. However, this particular question will have only one answer because of the following reasons:
      (a) the number of marbles must be \"whole number\"
      (b) the numbers in the questions are all prime numbers : 13; 5 and 124=2x2x31

      This question was intended to test a student's understanding that if a certain amount is divided into 13 U and it becomes 6 W after adding 124 to 13U, we can convert the 6 W to U by cutting each W into 3 parts. There is no other way of cutting such that 124 can be divided without remainder.

      1 Reply Last reply Reply Quote 0
      • T Offline
        tianzhu
        last edited by

        Brenda10:

        Thank you for providing us all these sample.
        Hi Brenda10
        You're welcome.

        You’re swift and accurate.
        If you are a P6 student, you can certainly look forward to an illuminating performance in PSLE 2010.

        Best wishes

        1 Reply Last reply Reply Quote 0
        • B Offline
          Brenda10
          last edited by

          tianzhu:
          Brenda10:


          Thank you for providing us all these sample.

          Hi Brenda10
          You're welcome.

          You’re swift and accurate.
          If you are a P6 student, you can certainly look forward to an illuminating performance in PSLE 2010.

          Best wishes

          Hi tianzhu

          Thank you.

          In fact I am actually very blur on all these ratio questions. :? However I feel is important for my dd (P5) to get the fundamental right and we have spent a few days try to learn/understand the different approach on ratio questions. Hopefully by more practice, dd can gradually handle better when the questions getting more complicating.

          1 Reply Last reply Reply Quote 0
          • T Offline
            tianzhu
            last edited by

            Hi Brenda10


            A P5 girl, that’s even more impressive considering the fact that she has just started to learn ratios.

            Wishing you and your daughter success in your journey towards A* for PSLE Maths in 2011.

            Best wishes

            1 Reply Last reply Reply Quote 0
            • CoffeeCatC Offline
              CoffeeCat
              last edited by

              atutor2001:
              Vanilla Cake:

              [quote=\"tianzhu\"]
              Hi

              I picked up this quote from the thread, Tips for improving in PSLE. It was from a member called livewith_vanilla.

              I think the question she posed is a pretty interesting one, it involves two changed quantities, but the number(124) involved in the transaction is lumped into one lot instead of two different portions.

              The marbles that A and B has is in the ratio 6:7. Then,124 marbles were added to the total and the ratio became 2:3.How many marbles were there at first?

              Have fun.
              Best wishes

              Hi Uncle Tianzhu,
              There seems to be more than one possible correct answer for this question. I have posted a reply to \"livewith_vanilla\" to seek her clarification for this \"One quick(inaccurate) example is this:.....\"

              I remember seeing this question in Andrew Er's assessment book.

              It is true mathematically that if we have only 1 equation with 2 unknowns, then the number of answers can be infinite. However, this particular question will have only one answer because of the following reasons:
              (a) the number of marbles must be \"whole number\"
              (b) the numbers in the questions are all prime numbers : 13; 5 and 124=2x2x31

              This question was intended to test a student's understanding that if a certain amount is divided into 13 U and it becomes 6 W after adding 124 to 13U, we can convert the 6 W to U by cutting each W into 3 parts. There is no other way of cutting such that 124 can be divided without remainder.[/quote]To assure those who got multiple answers that they are not seeing stars...
              I used the old fashioned algebra way ,
              i let the marbles at first be 6x and 7x.
              and the marbles added to A and B be y and 124-y respectively
              using the last ratio, i form the equation
              3 (6x+y) = 2( 7x+ 124-y)
              i get this diophantine equation 4x + 5y = 248
              the smallest solution is form when x=2, and y =48. (26 marbles at first)
              the next solution is when x= 2+5 = 7 and y = 48-4 = 44 (91 marbles at first).
              I stopped here but i suspect additional solutions can be obtained by adding 5 to x, and subtracting 4 from y.
              It's quite late so i will digest what you said tmr morning, so it's possible i might be reading something wrongly.

              1 Reply Last reply Reply Quote 0
              • V Offline
                Vanilla Cake
                last edited by

                CoffeeCat:
                atutor2001:

                [quote=\"Vanilla Cake\"]
                Hi Uncle Tianzhu,
                There seems to be more than one possible correct answer for this question. I have posted a reply to \"livewith_vanilla\" to seek her clarification for this \"One quick(inaccurate) example is this:.....\"

                I remember seeing this question in Andrew Er's assessment book.

                It is true mathematically that if we have only 1 equation with 2 unknowns, then the number of answers can be infinite. However, this particular question will have only one answer because of the following reasons:
                (a) the number of marbles must be \"whole number\"
                (b) the numbers in the questions are all prime numbers : 13; 5 and 124=2x2x31


                This question was intended to test a student's understanding that if a certain amount is divided into 13 U and it becomes 6 W after adding 124 to 13U, we can convert the 6 W to U by cutting each W into 3 parts. There is no other way of cutting such that 124 can be divided without remainder.

                To assure those who got multiple answers that they are not seeing stars...
                I used the old fashioned algebra way ,
                i let the marbles at first be 6x and 7x.
                and the marbles added to A and B be y and 124-y respectively
                using the last ratio, i form the equation
                3 (6x+y) = 2( 7x+ 124-y)
                i get this diophantine equation 4x + 5y = 248
                the smallest solution is form when x=2, and y =48. (26 marbles at first)
                the next solution is when x= 2+5 = 7 and y = 48-4 = 44 (91 marbles at first).
                I stopped here but i suspect additional solutions can be obtained by adding 5 to x, and subtracting 4 from y.
                It's quite late so i will digest what you said tmr morning, so it's possible i might be reading something wrongly.[/quote]Hi All,
                I am VC's mum and this is the http://www.kiasuparents.com/kiasu/forum/viewtopic.php?t=11112&start=20 from thread starter - livewith_vanilla:

                Ermmm...sorry but that's not the question i have actually.I actually just thought of some random one.It is not actually a question.Its just an example,something that i just thought of randomly without any thought.Yes,the answers will be vague.I will take an example from my school paper tmr and post it here as an accurate question with only one answer.Sorry!

                Hi atutor2001,
                I believe that this question is invalid and will not likely to appear in any upcoming PSLE Maths exams. If such example does appear in Andrew Er's assessment books, pls let us know which assessment book? Pls elaborate more on your 2 reasons that this particular question has only one answer instead of multiple answers.
                Thanks.

                1 Reply Last reply Reply Quote 0
                • B Offline
                  Brenda10
                  last edited by

                  Hi tianzhu


                  Thank you for your encouragement.

                  There is still a long way to go and hopefully we can keep up our stamina.

                  We do hope that the effort will be pay off.

                  Have a nice day.

                  1 Reply Last reply Reply Quote 0
                  • T Offline
                    trytry
                    last edited by

                    2008

                    http://www.jamesangtutors.com/forum/viewtopic.php?p=5520&sid=dd197883788c1e3bdaea959288b33365

                    7. Mrs Smith bought some mangoes and mangosteens for $16.50. She bought 5 fewer mangoes than mangosteens. Each mango cost $1.80 more than the mangosteen. How many mangosteens did she buy?

                    Anyone has solution to the above question?
                    Crack my head can't solve.

                    1 Reply Last reply Reply Quote 0
                    • B Offline
                      Brenda10
                      last edited by

                      trytry:
                      2008

                      http://www.jamesangtutors.com/forum/viewtopic.php?p=5520&sid=dd197883788c1e3bdaea959288b33365

                      7. Mrs Smith bought some mangoes and mangosteens for $16.50. She bought 5 fewer mangoes than mangosteens. Each mango cost $1.80 more than the mangosteen. How many mangosteens did she buy?

                      Anyone has solution to the above question?
                      Crack my head can't solve.
                      HI,

                      I would like to give a try:

                      Mangoesteen 6 7 8 9 10

                      Mango 1 2 3 4 5

                      Additional $1.80 $3.6 $5.4 $7.2 $9


                      $16.5-$9= $7.5
                      $7.5/15 = $0.5
                      (10*$0.5) + (5*$2.3) = $16.50

                      Therefore total she bought 10 mangoesteen.

                      Hopefully the answer is correct.

                      Thanks

                      1 Reply Last reply Reply Quote 0
                      • A Offline
                        atutor2001
                        last edited by

                        CoffeeCat:

                        To assure those who got multiple answers that they are not seeing stars...
                        I used the old fashioned algebra way ,
                        i let the marbles at first be 6x and 7x.
                        and the marbles added to A and B be y and 124-y respectively
                        using the last ratio, i form the equation
                        3 (6x+y) = 2( 7x+ 124-y)
                        i get this diophantine equation 4x + 5y = 248
                        the smallest solution is form when x=2, and y =48. (26 marbles at first)
                        the next solution is when x= 2+5 = 7 and y = 48-4 = 44 (91 marbles at first).
                        I stopped here but i suspect additional solutions can be obtained by adding 5 to x, and subtracting 4 from y.
                        It's quite late so i will digest what you said tmr morning, so it's possible i might be reading something wrongly.
                        Hi Coffeecat

                        Thanks for bring out my mistake. It is correct that there are 2 possible answers because the additional marble given was 124 (equal to 2x2x31). However, if the additional marble is 62 (equal to 2x31) then there should be only 1 answer because 1 unit will become 31 and cannot be split into any other way as 31 is a prime number.

                        Hi Vanilla Cake

                        Sorry, I cannot remember which book but it was one of those on P5 challenging math question (it is 5 years ago when my youngest kid was taking PSLE). I remember this question because I strongly disagree with it then, thinking it will generate infinite answers - until a math expert explained to me the rationale behind it.

                        There will be more than one answer if we use a \"composite number\" (numbers with more than 2 factors) for the additional number of marbles added to the total. This is because the marbles can then be distributed between A and B in many different ways using the different combination of factors of that \"composite number\" For the given example, the additional marble is 124 and so 1 unit is 62 = 2 x 31 or 1 x 61 allowing 2 possible answers.

                        As for the fact that marbles cannot be added in fraction, this limit the answer to \"whole numbers\". If instead of using marbles but let say the weight of something in kg or volume in litres, then the answers can be in fractions and there will be infinite answers as any number can be broken up into the product of 2 fractions in infinite number of ways. Hope I am right.

                        1 Reply Last reply Reply Quote 0

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