Logo
    • Education
      • Pre-School
      • Primary Schools Directory
      • Primary Schools Articles
      • P1 Registration
      • DSA
      • PSLE
      • Secondary
      • Tertiary
      • Special Needs
    • Lifestyle
      • Well-being
    • Activities
      • Events
    • Enrichment & Services
      • Find A Service Provider
      • Enrichment Articles
      • Enrichment Services
      • Tuition Centre/Private Tutor
      • Infant Care/ Childcare / Student Care Centre
      • Kindergarten/Preschool
      • Private Institutions and International Schools
      • Special Needs
      • Indoor & Outdoor Playgrounds
      • Paediatrics
      • Neonatal Care
    • Forum
    • ASKQ
    • Register
    • Login

    O-Level Additional Math

    Scheduled Pinned Locked Moved Secondary Schools - Academic Support
    809 Posts 301 Posters 497.9k Views 1 Watching
    Loading More Posts
    • Oldest to Newest
    • Newest to Oldest
    • Most Votes
    Reply
    • Reply as topic
    Log in to reply
    This topic has been deleted. Only users with topic management privileges can see it.
    • Y Offline
      YLH88
      last edited by

      [quote]
      mrswongtuition wrote :
      My sis' Maths was terrible too. We got a HOD Maths from a Secondary school to coach her 1-to-1 for E & A Maths. She got A2 for E Maths and B3 for A Maths. Very good for my sister who used to fail A Maths and borderline pass E Maths.

      If you are willing to spend on a good tutor, it's not too late now. Still have 9+ months to prepare [/quote]Hi mrswongtuiton,

      I would like to have the contact for the Maths tutor. Have just pm you.

      Thank you.

      1 Reply Last reply Reply Quote 0
      • O Offline
        OK Lor
        last edited by

        Hi CoffeeCat,


        Thanks for Q1. Please help to comment on Q2:

        f(x) = 9/(1+cos2x) + 25/(1-cos2x) = 9/[2(cos x)^2] + 25/[2(sinx)^2]
        = [9(sec x)^2 + 25(cosec x)^2] / 2
        f'(x) = 9[(sec x)^2](tan x) - 25[(cosec x)^2](cot x) = 0
        9[(sec x)^2](tan x) = 25[(cosec x)^2](cot x)
        (tan x)^4 = 25 / 9
        tan x = (5/3)^(1/2); cos x = (3/8 )^(1/2), sin x = (5/8 )^(1/2).
        Least possible value of f(x) = [9(8/3) + 25(8/5)] / 2 = 32 ? 😐

        Thanks.

        1 Reply Last reply Reply Quote 0
        • M Offline
          Muffins
          last edited by

          Just a question to ask. For my exam, I had gotten a question like this:


          a) Express 756 in its index form

          b) Hence, find the value k where 756k is a perfect square.

          I had gotten part a) correct, but I had put 2⅓ for part b), but they marked me wrong, saying that the answer was 21. Could anyone explain why? Thanks.

          1 Reply Last reply Reply Quote 0
          • V Offline
            Vanilla Cake
            last edited by

            Muffins:
            Just a question to ask. For my exam, I had gotten a question like this:


            a) Express 756 in its index form

            b) Hence, find the value k where 756k is a perfect square.

            I had gotten part a) correct, but I had put 2⅓ for part b), but they marked me wrong, saying that the answer was 21. Could anyone explain why? Thanks.
            756=2²x3³x7
            (a) 756 in its index form = 2²x3³x7

            Perfect square =2²x3⁴x7²
            k = 3x7 = 21

            (b)Value of k where 756k is a perfect square = 21

            Pls do not :offtopic:

            1 Reply Last reply Reply Quote 0
            • A Offline
              atutor2001
              last edited by

              Muffins:
              Just a question to ask. For my exam, I had gotten a question like this:


              a) Express 756 in its index form

              b) Hence, find the value k where 756k is a perfect square.

              I had gotten part a) correct, but I had put 2⅓ for part b), but they marked me wrong, saying that the answer was 21. Could anyone explain why? Thanks.
              There is probably a requirement in the question that \"k is a whole number, find the smallest value of k\", which is why your answer is not acceptable

              1 Reply Last reply Reply Quote 0
              • CoffeeCatC Offline
                CoffeeCat
                last edited by

                OK Lor:
                Hi CoffeeCat,


                Thanks for Q1. Please help to comment on Q2:

                f(x) = 9/(1+cos2x) + 25/(1-cos2x) = 9/[2(cos x)^2] + 25/[2(sinx)^2]
                = [9(sec x)^2 + 25(cosec x)^2] / 2
                f'(x) = 9[(sec x)^2](tan x) - 25[(cosec x)^2](cot x) = 0
                9[(sec x)^2](tan x) = 25[(cosec x)^2](cot x)
                (tan x)^4 = 25 / 9
                tan x = (5/3)^(1/2); cos x = (3/8 )^(1/2), sin x = (5/8 )^(1/2).
                Least possible value of f(x) = [9(8/3) + 25(8/5)] / 2 = 32 ? 😐

                Thanks.
                sounds correct to me ...

                1 Reply Last reply Reply Quote 0
                • O Offline
                  OK Lor
                  last edited by

                  Hi 高人 CoffeCat,


                  Thanks. 😄

                  1 Reply Last reply Reply Quote 0
                  • M Offline
                    Muffins
                    last edited by

                    atutor2001:
                    Muffins:

                    Just a question to ask. For my exam, I had gotten a question like this:


                    a) Express 756 in its index form

                    b) Hence, find the value k where 756k is a perfect square.

                    I had gotten part a) correct, but I had put 2⅓ for part b), but they marked me wrong, saying that the answer was 21. Could anyone explain why? Thanks.

                    There is probably a requirement in the question that \"k is a whole number, find the smallest value of k\", which is why your answer is not acceptable

                    Hi atutor2001, this was actually the exact question itself,, nothing missed out.... :sad:

                    1 Reply Last reply Reply Quote 0
                    • M Offline
                      Muffins
                      last edited by

                      Vanilla Cake:
                      Muffins:

                      Just a question to ask. For my exam, I had gotten a question like this:


                      a) Express 756 in its index form

                      b) Hence, find the value k where 756k is a perfect square.

                      I had gotten part a) correct, but I had put 2⅓ for part b), but they marked me wrong, saying that the answer was 21. Could anyone explain why? Thanks.

                      756=2²x3³x7
                      (a) 756 in its index form = 2²x3³x7

                      Perfect square =2²x3⁴x7²
                      k = 3x7 = 21

                      (b)Value of k where 756k is a perfect square = 21

                      Pls do not :offtopic:

                      Hi VC, thanks for the answer, but I wanted to know the explanation as to why my answer was not allowed. It is, in fact, a smaller value than 21, which still makes 756 a perfect square.... TIA. 🙂

                      1 Reply Last reply Reply Quote 0
                      • V Offline
                        Vanilla Cake
                        last edited by

                        Hi Muffins,

                        Sorry, I don't know how to explain.Better go and ask your teacher when school reopens.
                        😢

                        BTW,my younger sister is taking part in http://www.acs.sch.edu.sg/acs_indep/announcements.php?id=93 for All Singapore Primary Schools 2010.Do you know whether ACSI sell the worked solutions for the past years' questions of Mathlympics?Do let us know your findings.
                        Thanks.
                        😉

                        1 Reply Last reply Reply Quote 0

                        Hello! It looks like you're interested in this conversation, but you don't have an account yet.

                        Getting fed up of having to scroll through the same posts each visit? When you register for an account, you'll always come back to exactly where you were before, and choose to be notified of new replies (either via email, or push notification). You'll also be able to save bookmarks and upvote posts to show your appreciation to other community members.

                        With your input, this post could be even better 💗

                        Register Login
                        • 1
                        • 2
                        • 12
                        • 13
                        • 14
                        • 15
                        • 16
                        • 80
                        • 81
                        • 14 / 81
                        • First post
                          Last post



                        Online Users

                        Statistics

                        2

                        Online

                        211.0k

                        Users

                        34.3k

                        Topics

                        1.8m

                        Posts
                        Popular Topics
                        New to the KiasuParents forum? Tips and Tricks!
                        Choosing and Evaluating Primary Schools
                        DSA 2026
                        PSLE Discussions and Strategies
                        How much do you spend on the kids' tuition/enrichments?
                        SkillsFuture + anything related to upskilling/learning something new!

                          About Us Contact Us forum Terms of Service Privacy Policy