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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • B Offline
      Brenda10
      last edited by

      YLH88:
      Hi Brenda10,


      I understand how you get 4 for the shaded part. But for the unshaded part, why use only 30 ? how about A and B ?

      Sorry still a bit confused .. :?
      Hi YLH88

      May be explain this way, figure means outline.

      Although there were 3 circles, A, B & C. However the two small circles are insided the big circle C. the figure refers to the outline of the shape.

      Thank you and hope you can understand.

      1 Reply Last reply Reply Quote 0
      • V Offline
        Vanilla Cake
        last edited by

        YLH88:
        2) Nan Hua SA1 2009 P1 Qn 15

        In the figure, not drawn to scale, the ratio of the area of Circle A to Circle B to Circle C is 3 : 4 : 10. If 1/3 of B is shaded, what is the ratio of the shaded part to the unshaded part of the figure ?

        a) 1:17
        b) 2:13
        c) 3: 17
        d) 4:13

        http://www.postimage.org/image.php?v=Tshduyr
        Ratio of area
        A : B : C
        3 : 4 : 10

        Since 1/3 of B is shaded, look for the LCM of 3 and 4 which is 12
        So, multiply for B ->4x3 = 12.Do the same for A and C.

        A : B : C
        9 : 12 : 30

        1/3 of B is shaded = shaded part of the figure ie 1/3x12 = 4
        See the picture to visualize. Got it so far?

        Whole figure is C itself ie 30.
        Remaining part of the figure (after deducting the shaded portion)= Unshaded part of the figure
        -> 30-4 = 26

        Finally, ratio of the shaded part to the unshaded part of the figure = 4 :26
        = 2: 13

        Answer option is (b)

        1 Reply Last reply Reply Quote 0
        • Y Offline
          YLH88
          last edited by

          Hi Brenda10,


          Thank you so much!! Now I understand liao ..

          Hi VC,

          Thank you so much for the solution!! You are right, the options given in the questions are in 1, 2, 3, 4 😎 Just that I wrote in (a, b, c, d) to easy differentiate between the question and options 😎 You are so well-informed of where the answers to all the related questions are !!
          [quote]I believe the answer options given in the actual Maths exam script is in numerical option (1,2,3,4) and not alphabetical option (a,b,c,d). Pls clarify.[/quote]

          1 Reply Last reply Reply Quote 0
          • H Offline
            Herbie
            last edited by

            Hi, I have one qn which needs help?




            Paya Lebar MGS, Paper 2, Q15


            5x5 = 25
            5x5x5=125
            5x5x5x5=625
            5x5x5x5x5=3125

            (a) What is the sum of the last three digits in 5 to the power of 15?
            (b) What is the sum of the last four digits in 5 to the power of 210?

            Can someone provide us with the solution?

            Many thanks!

            1 Reply Last reply Reply Quote 0
            • M Offline
              Maths Monster
              last edited by

              delete

              1 Reply Last reply Reply Quote 0
              • CoffeeCatC Offline
                CoffeeCat
                last edited by

                Herbie:
                Hi, I have one qn which needs help?




                Paya Lebar MGS, Paper 2, Q15


                5x5 = 25
                5x5x5=125
                5x5x5x5=625
                5x5x5x5x5=3125

                (a) What is the sum of the last three digits in 5 to the power of 15?
                (b) What is the sum of the last four digits in 5 to the power of 210?

                Notice that the last 3 digits of 3125 is 125, which corresponds to the 125 from two lines before. The cycle will repeat itself 125, 625, 125,625...
                As for the pattern of the last 4 digits more calculations is needed
                just remember to work with the last 4 digits and discard the rest and u will find the pattern.

                1 Reply Last reply Reply Quote 0
                • corneyAmberC Offline
                  corneyAmber
                  last edited by

                  Herbie:
                  Hi, I have one qn which needs help?

                  Paya Lebar MGS, Paper 2, Q15
                  5x5 = 25
                  5x5x5=125
                  5x5x5x5=625
                  5x5x5x5x5=3125

                  (a) What is the sum of the last three digits in 5 to the power of 15?
                  (b) What is the sum of the last four digits in 5 to the power of 210?

                  Can someone provide us with the solution?

                  Many thanks!
                  (a) odd number power => it ends with 125
                  so power of 15 is odd number => it will end with 125,
                  Hence sum of last 3 digits = 1+2+5 = 8

                  I need to mull over how to present (b).

                  1 Reply Last reply Reply Quote 0
                  • M Offline
                    Muffins
                    last edited by

                    Brenda10:
                    Muffins:

                    Hi Brenda10, your daughter just managed to summarise my workings into a few steps! :shock: How old is your DD??? πŸ™‚



                    Thank you Muffins.

                    She is 11 years old.

                    :shock: :shock: Very young and VERY BRIGHT!!! πŸ™‚

                    1 Reply Last reply Reply Quote 0
                    • R Offline
                      ruyu
                      last edited by

                      Vanilla Cake:
                      YLH88:

                      6) Mark can climb uphill at an average speed of 2km/h and go downhill at an average speed of 6km/h. Going first uphill and then downhill, without stopping and using the same route, what will his average speed be for the entire trip ?


                      Assume the distance of the route be unit.
                      Total time taken = unit/2 + unit/6 = 4units/6 = 2units/3
                      Distance = unit
                      Average speed = unitΓ·2 units/3 = unitx3/2units = 3/2 = 1.5 km/h

                      This is similar to NMOS 2009 Prelim round Q3. Where is this question taken from?

                      dont understand :? care to explain?

                      1 Reply Last reply Reply Quote 0
                      • B Offline
                        Brenda10
                        last edited by

                        Muffins:
                        Brenda10:

                        [quote=\"Muffins\"]Hi Brenda10, your daughter just managed to summarise my workings into a few steps! :shock: How old is your DD??? πŸ™‚



                        Thank you Muffins.

                        She is 11 years old.

                        :shock: :shock: Very young and VERY BRIGHT!!! :)[/quote]Hi Muffins,

                        Thank you for thinking highly upon her. :oops:


                        In fact, DD is just average. She has done more than 50 ratio/percentage questions during the school holiday and may be the numerous practices really help. The questions in this forum really provide her the good opportunity on trial and error. The more important thing is that she could also learn from all of you as well.

                        1 Reply Last reply Reply Quote 0

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