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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • A Offline
      Almighty
      last edited by

      Hi all,


      Can anyone help to let me know whether my answer to the follwing question is right?

      Yao has 2 clocks in his house; a cuckoo clock and a pendulam clock. Unfortunately,\t\t
      neither is in good working condition.The cuckoo clock gains 5 seconds for every minute \t\t
      it runs (which means it gets faster and faster) whilst the pendulam clock loses 5 seconds\t\t
      every minute it runs (which means it gets slower and slower).Yao resets both at 6 O’clock\t\t
      in the morning. When the time shown on the pendulam clock is 7.am, what time is shown on the \t\t
      cuckoo clock?

      (My ans : 7.10.25 am (7-hr.10 - min and 25 secs in the morning. Am I correct?)

      1 Reply Last reply Reply Quote 0
      • B Offline
        biscuitqueen
        last edited by

        Mary and Ken travelled from Town A to Town B. Mary left Town A at 0915 and took 4h to reach Town B. Ken left Town A at 1000 and took 2h 45min to reach Town B. At what time did Ken pass Mary?

        1 Reply Last reply Reply Quote 0
        • T Offline
          trytry
          last edited by

          CoffeeCat:
          trytry:

          I need help with this problem.


          Alice is going up an escalator.
          When she takes 2 steps per second, she reaches the top in 24 steps.
          When she takes 1 step per second, she reaches the top in 16 steps.
          How long will she take to reach the top if she just stands on the escalator?

          TIA!

          May I know what's the source of this question?
          Questions similar to this have appeared twice in HCI's SMOPS so far.

          A math test taken by student for DSA selection

          1 Reply Last reply Reply Quote 0
          • C Offline
            Cheerfuldad
            last edited by

            Dear all,


            Please help!

            P5 Question:

            Q. Four girls, Alice, Bibi, Carol and Delia, each have some stickers. the number of stickers Alice has is 1/2 of the total number of the stickers Bibi, Carol and Delia have. The number of stickers Bibi has is 1/4 of the number of stickers Alice, Carol and Delia have. The number of stickers Carol has is 2/3 of the total number of stickers Alice, Bibi and Delia have. If Delia has 30 stickers, Find the total number of stickers Bibi and Carol have altogether. :?:

            TIA

            1 Reply Last reply Reply Quote 0
            • M Offline
              mujin
              last edited by

              Cheerfuldad:
              Dear all,


              Please help!

              P5 Question:

              Q. Four girls, Alice, Bibi, Carol and Delia, each have some stickers. the number of stickers Alice has is 1/2 of the total number of the stickers Bibi, Carol and Delia have. The number of stickers Bibi has is 1/4 of the number of stickers Alice, Carol and Delia have. The number of stickers Carol has is 2/3 of the total number of stickers Alice, Bibi and Delia have. If Delia has 30 stickers, Find the total number of stickers Bibi and Carol have altogether. :?:

              TIA
              Let me try..

              Alice = (1/2)/(1+1/2) = 1/3 of total
              Bibi = (1/4)/ (1+1/4) = 1/5 of total
              Carol = (2/3)/(1+2/3) = 2/5 of total
              Delia = 1-[(1/3)+(1/5)+(2/5)] = 1/15 of total = 30 stickers
              Total stickers = 30x15 = 450

              Ans
              Bibi has 450 x (1/5) = 90
              Carol has 450 x (2/5) = 180

              Bibi + Carol = 90+180 = 270 stickers

              1 Reply Last reply Reply Quote 0
              • D Offline
                Dharma
                last edited by

                trytry:
                I need help with this problem.


                Alice is going up an escalator.
                When she takes 2 steps per second, she reaches the top in 24 steps.
                When she takes 1 step per second, she reaches the top in 16 steps.
                How long will she take to reach the top if she just stands on the escalator?

                TIA!
                If Alice runs up 24 steps to reach the top; she takes 12 seconds (24/2)
                If Alice runs up 16 steps to reach the top; she takes 16 seconds (16/1)

                Each additional step takes (16 – 12)/(24 – 16) = 0.5 seconds

                Total no. of steps on the escalator = 24 + 12/0.5 = 48 steps

                If Alice stood on the escalator;

                Time taken = 48 steps x 0.5 seconds/steps = 24 seconds

                OR

                Let no. of steps on escalator be x

                Speed of escalator = (x – 24)/12 = (x – 16)/16

                16(x – 24) = 12(x – 16)
                16x – 384 = 12x – 192
                4x = 192
                X = 48

                Speed of escalator = (48 – 24)/ 12 = 2 step/ sec

                Time taken = 48 steps/ 2 step/sec = 24 sec

                1 Reply Last reply Reply Quote 0
                • M Offline
                  Muffins
                  last edited by

                  Got a question for you guys to answer. It's from a primary school test paper. I need the working in models, if you don't mind...


                  In a conference, there were some men and women. In the first day, there were 80 less women than men. In the second day, the number of men who came decreased by 10%, and the number of women who had arrived increased by 20%. The total number of people who had arrived for the second day was 1542.

                  How many men and women were there for the first and second day?

                  TIA. 🙂

                  1 Reply Last reply Reply Quote 0
                  • S Offline
                    singalion
                    last edited by

                    In a conference, there were some men and women. In the first day, there were 80 less women than men. In the second day, the number of men who came decreased by 10%, and the number of women who had arrived increased by 20%. The total number of people who had arrived for the second day was 1542.


                    How many men and women were there for the first and second day?


                    I can give you the answer without models - in ratio instead:

                    Hope this helps:


                    http://www.postimage.org/image.php?v=Pqg8tNr

                    1 Reply Last reply Reply Quote 0
                    • B Offline
                      biscuitqueen
                      last edited by

                      Hi there, please help me solve this Maths questn for my daughter.

                      I have no idea how to solve. Thanx!


                      Mary and Ken travelled from Town A to Town B. Mary left Town A at 0915 and took 4h to reach Town B. Ken left Town A at 1000 and took 2h 45min to reach Town B. At what time did Ken pass Mary?

                      1 Reply Last reply Reply Quote 0
                      • O Offline
                        optimistforum
                        last edited by

                        optimistforum:
                        Hi Maths Guru


                        Can you look at this Clock Question, please?

                        Please help on the answer to the question below.

                        John and Tom race around a circular track, divided like the face of a clock, into 12 sections. If John gives Tom four sections start and runs half as fast again as Tom, at what point on the track will he overtake Tom? (Assume on the clock face that John and Tom start at 12 and 4, respectively).

                        The answer is 12, however, if John gives Tom four sections starts and is half as fast, surely does not half as fast mean that John is running at half the speed of Tom. And if he is 4 sections behind, surely Tom will win. Unless half as fast means that John runs at 1.5 times of Tom. Tearing my hair out here. Please help!!!
                        Hi, do all questions get answered, as I have checked on here, and my PM to see if the above question has been answered - and it has not :?

                        1 Reply Last reply Reply Quote 0

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