Tutor MathsGuru: Ask me for your burning Maths questions!

[Cheerfuldad]

Dear all,


Please help!

P5 Question:

Q. Four girls, Alice, Bibi, Carol and Delia, each have some stickers. the number of stickers Alice has is 1/2 of the total number of the stickers Bibi, Carol and Delia have. The number of stickers Bibi has is 1/4 of the number of stickers Alice, Carol and Delia have. The number of stickers Carol has is 2/3 of the total number of stickers Alice, Bibi and Delia have. If Delia has 30 stickers, Find the total number of stickers Bibi and Carol have altogether. :?:

TIA

[mujin]

Cheerfuldad:

Dear all,


Please help!

P5 Question:

Q. Four girls, Alice, Bibi, Carol and Delia, each have some stickers. the number of stickers Alice has is 1/2 of the total number of the stickers Bibi, Carol and Delia have. The number of stickers Bibi has is 1/4 of the number of stickers Alice, Carol and Delia have. The number of stickers Carol has is 2/3 of the total number of stickers Alice, Bibi and Delia have. If Delia has 30 stickers, Find the total number of stickers Bibi and Carol have altogether. :?:

TIA

Let me try..

Alice = (1/2)/(1+1/2) = 1/3 of total
Bibi = (1/4)/ (1+1/4) = 1/5 of total
Carol = (2/3)/(1+2/3) = 2/5 of total
Delia = 1-[(1/3)+(1/5)+(2/5)] = 1/15 of total = 30 stickers
Total stickers = 30x15 = 450

Ans
Bibi has 450 x (1/5) = 90
Carol has 450 x (2/5) = 180

Bibi + Carol = 90+180 = 270 stickers

[Dharma]

trytry:

I need help with this problem.


Alice is going up an escalator.
When she takes 2 steps per second, she reaches the top in 24 steps.
When she takes 1 step per second, she reaches the top in 16 steps.
How long will she take to reach the top if she just stands on the escalator?

TIA!

If Alice runs up 24 steps to reach the top; she takes 12 seconds (24/2)
If Alice runs up 16 steps to reach the top; she takes 16 seconds (16/1)

Each additional step takes (16 – 12)/(24 – 16) = 0.5 seconds

Total no. of steps on the escalator = 24 + 12/0.5 = 48 steps

If Alice stood on the escalator;

Time taken = 48 steps x 0.5 seconds/steps = 24 seconds

OR

Let no. of steps on escalator be x

Speed of escalator = (x – 24)/12 = (x – 16)/16

16(x – 24) = 12(x – 16)
16x – 384 = 12x – 192
4x = 192
X = 48

Speed of escalator = (48 – 24)/ 12 = 2 step/ sec

Time taken = 48 steps/ 2 step/sec = 24 sec

[Muffins]

Got a question for you guys to answer. It's from a primary school test paper. I need the working in models, if you don't mind...


In a conference, there were some men and women. In the first day, there were 80 less women than men. In the second day, the number of men who came decreased by 10%, and the number of women who had arrived increased by 20%. The total number of people who had arrived for the second day was 1542.

How many men and women were there for the first and second day?

TIA.

[singalion]

In a conference, there were some men and women. In the first day, there were 80 less women than men. In the second day, the number of men who came decreased by 10%, and the number of women who had arrived increased by 20%. The total number of people who had arrived for the second day was 1542.


How many men and women were there for the first and second day?


I can give you the answer without models - in ratio instead:

Hope this helps:


http://www.postimage.org/image.php?v=Pqg8tNr

[biscuitqueen]

Hi there, please help me solve this Maths questn for my daughter.

I have no idea how to solve. Thanx!


Mary and Ken travelled from Town A to Town B. Mary left Town A at 0915 and took 4h to reach Town B. Ken left Town A at 1000 and took 2h 45min to reach Town B. At what time did Ken pass Mary?

[optimistforum]

optimistforum:

Hi Maths Guru


Can you look at this Clock Question, please?

Please help on the answer to the question below.

John and Tom race around a circular track, divided like the face of a clock, into 12 sections. If John gives Tom four sections start and runs half as fast again as Tom, at what point on the track will he overtake Tom? (Assume on the clock face that John and Tom start at 12 and 4, respectively).

The answer is 12, however, if John gives Tom four sections starts and is half as fast, surely does not half as fast mean that John is running at half the speed of Tom. And if he is 4 sections behind, surely Tom will win. Unless half as fast means that John runs at 1.5 times of Tom. Tearing my hair out here. Please help!!!

Hi, do all questions get answered, as I have checked on here, and my PM to see if the above question has been answered - and it has not :?

[markfch]

The qn is:


The total age of Danny and Mike is 37 yrs old. Danny is 9 yrs older than Mike. What was Mike’s age 5 yrs ago?

Of course mentally I know the ans. If I say 2y + 9 = 37, I’m afraid it’s hard for ds to follow.

How do I present the working in a simplier way so that ds can follow? (as long as I can present it systematically, I’m sure he will understand). Thanks.

[ChiefKiasu]

markfch:

The qn is:


The total age of Danny and Mike is 37 yrs old. Danny is 9 yrs older than Mike. What was Mike's age 5 yrs ago?

Of course mentally I know the ans. If I say 2y + 9 = 37, I'm afraid it's hard for ds to follow.

How do I present the working in a simplier way so that ds can follow? (as long as I can present it systematically, I'm sure he will understand). Thanks.

markfch, welcome to the world of model drawing.

Let current age of Mike be M.

So (M) and (M+9) will total 37, which means M = 14
So 5 years ago, Michael is 14-5 = 9 years old

[Dharma]

biscuitqueen:

Hi there, please help me solve this Maths questn for my daughter.

I have no idea how to solve. Thanx!


Mary and Ken travelled from Town A to Town B. Mary left Town A at 0915 and took 4h to reach Town B. Ken left Town A at 1000 and took 2h 45min to reach Town B. At what time did Ken pass Mary?

For fixed distance from Town A to Town B,

Time ratio => Mary : Ken = 240 : 165 = 48 : 33
Speed ratio => Mary : Ken = 33 : 48

At 1000hrs, Mary had travelled (33u x ¾)km = 99/4 km
Ken starts at 1000hrs and needs to catch up this distance.

Time taken by Ken to catch up with Mary
= 99u/4/(48u – 33u)
= 33/20 hrs
= 99 mins ( 1 hr 39 mins)

Ken passed Mary at 1139hrs