Tutor MathsGuru: Ask me for your burning Maths questions!

[Daddy]

Thanks Tianzhu & Dharma.


Tianzhu Question:
"Mr Ong had 5kg of rice. After he sold 5/12 of it, he repacked the remaining rice into smaller packets of 2/3kg each. How much rice had he left? "

Above question is difficult than I had asked. I tried.

Left => 1- 5/12 = 7/12

5 Kg x 7/12 = 35/12kg left

Is it the answer?

[maths6a]

you are right. so plus first tree so it should also be 21. pai say!

[tianzhu]

Daddy:

Thanks Tianzhu & Dharma.


Tianzhu Question:
\"Mr Ong had 5kg of rice. After he sold 5/12 of it, he repacked the remaining rice into smaller packets of 2/3kg each. How much rice had he left? \"

Above question is difficult than I had asked. I tried.

Left => 1- 5/12 = 7/12

5 Kg x 7/12 = 35/12kg left

Is it the answer?

Hi

You're welcome.

5 Kg x 7/12 = 35/12kg left
You’ve answered the first part of the question.
From the remainder of 35/12kg, you have to take into account the repacking of the remaining rice into smaller packets of 2/3kg each to get the answer.

Like your earlier question, this one also touches on product of proper fractions. Such questions may look easy at first glance, but may trip some students as they can be tricky.

The answer is 1/4kg.

Best wishes

[Yu Xuan]

Daddy:

Thanks Tianzhu & Dharma.


Tianzhu Question:
\"Mr Ong had 5kg of rice. After he sold 5/12 of it, he repacked the remaining rice into smaller packets of 2/3kg each. How much rice had he left? \"

Above question is difficult than I had asked. I tried.

Left => 1- 5/12 = 7/12

5 Kg x 7/12 = 35/12kg left

Is it the answer?

Here's my humble version;

7/12 * 5 kg = 2 11/12

2 11/12 / 2/3 = approx 4

2 11/12 - (4 * 2/3) = 1/4

Ans : 1/4 kg

[Nebbermind]

Yu Xuan:

Daddy:

Thanks Tianzhu & Dharma.


Tianzhu Question:
\"Mr Ong had 5kg of rice. After he sold 5/12 of it, he repacked the remaining rice into smaller packets of 2/3kg each. How much rice had he left? \"

Above question is difficult than I had asked. I tried.

Left => 1- 5/12 = 7/12

5 Kg x 7/12 = 35/12kg left

Is it the answer?

Here's my humble version;

7/12 * 5 kg = 2 11/12

2 11/12 / 2/3 = approx 4

2 11/12 - (4 * 2/3) = 1/4

Ans : 1/4 kg

what a confusing qn!!

[2DMommy]

Pls help me with this question.


5 children baked some cookies.
Angela baked 40 more cookies than Josephine but 1/2 as many cookies as Grace. Grace baked 4 times as many cookies as Mary. Mary baked 3/4 as many cookies as Josephine. Christina baked thrice as many cookies as Mary.

How many cookies does each child have :
Angela ?
Josephine ?
Grace ?
Mary ?
Christina ?

[starlight1968sg]

2DMommy:

Pls help me with this question.


5 children baked some cookies.
Angela baked 40 more cookies than Josephine but 1/2 as many cookies as Grace. Grace baked 4 times as many cookies as Mary. Mary baked 3/4 as many cookies as Josephine. Christina baked thrice as many cookies as Mary.
How many cookies does each child have :
Angela ?
Josephine ?
Grace ?
Mary ?
Christina ?

What is the ans?
Mine is J:80, M:60, A:120, G:240 and 180.

[Yu Xuan]

starlight1968sg:

2DMommy:

Pls help me with this question.


5 children baked some cookies.
Angela baked 40 more cookies than Josephine but 1/2 as many cookies as Grace. Grace baked 4 times as many cookies as Mary. Mary baked 3/4 as many cookies as Josephine. Christina baked thrice as many cookies as Mary.
How many cookies does each child have :
Angela ?
Josephine ?
Grace ?
Mary ?
Christina ?

What is the ans?
Mine is J:80, M:60, A:120, G:240 and 180.

Hi ... I have got the same answer too.

Using a model ;
J = 4 units
M = 3 units
G = 12 units
A = 4 units + 40

Since Angela should have half as much as Grace, she should have 6 units in total. Hence the 2 units is equal to 40.

1 unit = 20
J - 4 * 20 = 80
M - 3 * 20 = 60
G - 12 * 20 = 240
A - 4 * 20 + 40 = 120
:celebrate:

[trytry]

Hi can anyone help to solve this type of question:


There are 5 boys A. B, C, Dand E. Each time 2 boys will pair up to have their mass taken. The ten readings in kg are 105, 113 116, 117, 118,124,125,130,137 and 139. What is the mass of the third heaviest boy?
TIA.

[Dharma]

trytry:

Hi can anyone help to solve this type of question:


There are 5 boys A. B, C, Dand E. Each time 2 boys will pair up to have their mass taken. The ten readings in kg are 105, 113 116, 117, 118,124,125,130,137 and 139. What is the mass of the third heaviest boy?
TIA.

Mass of all 5 boys
= (105 + 113 + 116 + 117 + 118 + 124 + 125 + 130 + 137 + 139)/4
= 306

Sum of the mass of the 2 lightest boys and 2 heaviest boys
= 105 + 139
= 244

The mass of the 3rd heaviest boy = 306 – 244 = 62