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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • H Offline
      hamsterss
      last edited by

      Can someone help me with this question?


      Jason and Carl cycled from Westpoint to Spring Mall at 11km/h and 8km/h repectively. Jason left Westpoint an hour later than Carl and arrived at Spring Mall 0.5h later than Carl. How long did Jason took?

      Thanks 😄

      1 Reply Last reply Reply Quote 0
      • V Offline
        Vanilla Cake
        last edited by

        hamsterss:
        Can someone help me with this question?


        Jason and Carl cycled from Westpoint to Spring Mall at 11km/h and 8km/h repectively. Jason left Westpoint an hour later than Carl and arrived at Spring Mall 0.5h later than Carl. How long did Jason took?

        Thanks 😄
        Hi hamsterss,
        I am the mum of VC and are you a parent? Not sure whether the method used is applicable for you or not?

        Constant distance concept where speed is inversely proportional to time.

        Ratio of speed
        Jason : Carl
        11 : 8

        Ratio of time
        Jason : Carl
        8 : 11

        Difference in time = 1 h - 0.5h = 0.5h
        Difference in time in terms of unit = 11u-8u = 3u
        3u-> 0.5h
        u -> 1/6 of h = 10 min

        Time taken by Jason -> 8u = 8x10min = 80 min

        VC's mum

        1 Reply Last reply Reply Quote 0
        • H Offline
          hamsterss
          last edited by

          Vanilla Cake:
          hamsterss:

          Can someone help me with this question?


          Jason and Carl cycled from Westpoint to Spring Mall at 11km/h and 8km/h repectively. Jason left Westpoint an hour later than Carl and arrived at Spring Mall 0.5h later than Carl. How long did Jason took?

          Thanks 😄

          Hi hamsterss,
          I am the mum of VC and are you a parent? Not sure whether the method used is applicable for you or not?

          Constant distance concept where speed is inversely proportional to time.

          Ratio of speed
          Jason : Carl
          11 : 8

          Ratio of time
          Jason : Carl
          8 : 11

          Difference in time = 1 h - 0.5h = 0.5h
          Difference in time in terms of unit = 11u-8u = 3u
          3u-> 0.5h
          u -> 1/6 of h = 10 min

          Time taken by Jason -> 8u = 8x10min = 80 min

          VC's mum

          Really thanks for your help! Nope,im a student ^o^
          I was stuck after this : [quote]Ratio of speed
          Jason : Carl
          11 : 8

          Ratio of time
          Jason : Carl
          8 : 11[/quote]My teacher just taught us but can't really understand the method >o< Can you explain to me how come the ratio can be exchangable?

          1 Reply Last reply Reply Quote 0
          • P Offline
            pecalis
            last edited by

            [/quote]

            Really thanks for your help! Nope,im a student ^o^
            I was stuck after this : [quote]Ratio of speed
            Jason : Carl
            11 : 8

            Ratio of time
            Jason : Carl
            8 : 11[/quote]My teacher just taught us but can't really understand the method >o< Can you explain to me how come the ratio can be exchangable?[/quote]

            Speed = Distance / time
            So speed increases, distance increases the same proportion
            BUT
            When speed increases, the time taken is less by the same ratio.
            Ratio of speed of A : Speed of B
            = Ratio of distance travelled by A : distance travelled by B

            BUT
            Time taken by A: time taken by B
            = speed of B : speed of A

            1 Reply Last reply Reply Quote 0
            • C Offline
              CJM
              last edited by

              Hi all,


              need ur help on this question : -

              Mr Lim sold a total of 96 papayas and watermelons for $560.
              He sold each papaya for $3 and each watermelon for $7.
              How many watermelons did Mr Lim sell ?

              1 Reply Last reply Reply Quote 0
              • L Offline
                little_twin_stars
                last edited by

                Hi there…


                There is this question:

                At 9.20 am, Terence left Town X for Town Y at a constant speed. 1 hour larer, Gary started travelling from Town X on the same road at a constant speed. Gary overtook Terence at 12.20 pm. The speed which Gary was travelling at was 40km/h faster than Terence. Find the speed that Terence was travelling at.

                The solution given is as follows:

                Time (Terence): Time (Gray) -> 3 : 2
                Speed (Terence = D/3
                Speed (Gary) = D/2
                D/2-D/3 = 1/6 D
                1/6 D = 40 km
                D = 40km x 6
                =240 km/h
                Average Speed (T) = 240/3
                = 80 km/h


                However, I worked it out another way. I would like to know if it is also correct.

                Time taked for Gary to overtake Terence -> 2 h
                The extra distance that Gary could cover in the 2 h -> 40 x 2
                = 80 km
                Speed of Terence -> D/T = 80/1
                = 80 km/h

                Thanks in advance

                1 Reply Last reply Reply Quote 0
                • C Offline
                  corvette
                  last edited by

                  …

                  1 Reply Last reply Reply Quote 0
                  • corneyAmberC Offline
                    corneyAmber
                    last edited by

                    CJM:
                    Hi all,


                    need ur help on this question : -

                    Mr Lim sold a total of 96 papayas and watermelons for $560.
                    He sold each papaya for $3 and each watermelon for $7.
                    How many watermelons did Mr Lim sell ?
                    P = 96-W
                    3(96-W) + 7W = 560
                    4W = 560-288 = 272
                    W = 68

                    Mr Lim sold 68 watermelons.

                    1 Reply Last reply Reply Quote 0
                    • T Offline
                      tianzhu
                      last edited by

                      little_twin_stars:
                      Hi there...


                      There is this question:

                      At 9.20 am, Terence left Town X for Town Y at a constant speed. 1 hour larer, Gary started travelling from Town X on the same road at a constant speed. Gary overtook Terence at 12.20 pm. The speed which Gary was travelling at was 40km/h faster than Terence. Find the speed that Terence was travelling at.

                      The solution given is as follows:

                      Time (Terence): Time (Gray) -> 3 : 2
                      Speed (Terence = D/3
                      Speed (Gary) = D/2
                      D/2-D/3 = 1/6 D
                      1/6 D = 40 km
                      D = 40km x 6
                      =240 km/h
                      Average Speed (T) = 240/3
                      = 80 km/h


                      However, I worked it out another way. I would like to know if it is also correct.

                      Time taked for Gary to overtake Terence -> 2 h
                      The extra distance that Gary could cover in the 2 h -> 40 x 2
                      = 80 km
                      Speed of Terence -> D/T = 80/1
                      = 80 km/h

                      Thanks in advance
                      Hi little_twin_stars

                      It’s good to have a line diagram when you’re doing speed questions.

                      You’re right.

                      Best wishes

                      1 Reply Last reply Reply Quote 0
                      • V Offline
                        Vanilla Cake
                        last edited by

                        ksi:
                        CJM:

                        Hi all,


                        need ur help on this question : -

                        Mr Lim sold a total of 96 papayas and watermelons for $560.
                        He sold each papaya for $3 and each watermelon for $7.
                        How many watermelons did Mr Lim sell ?

                        P = 96-W
                        3(96-W) + 7W = 560
                        4W = 560-288 = 272
                        W = 68

                        Mr Lim sold 68 watermelons.

                        Hi CJM,
                        You may wish to refer to this http://p4mathsquestions.blogspot.com/2009/08/maths-decimals-solutions_21.html and apply the same concept to solve your question.

                        Selling price of 96 payayas -> 96x$3 = $288
                        Total amount of money collected for selling 96 papayas and watermelons = $560
                        Difference (total)= $(560-288) = $272
                        Difference (1 watermelon and 1 payaya) = $(7-3) = $4
                        1 payaya + $4 -> 1 watermelon
                        $272÷4= 68 (This step is enough and follow by the answer statement)
                        68 payayas + $272 -> 68 watermelons (Additional step to aid your understanding and is not necessary in actual workings.)
                        96-68 = 28 payayas (Additional step if the question asks for the number of payayas sold.)

                        Number of watermelons sold by Mr Lim = 68.

                        Check
                        Amount collected for selling 68 watermelons @ $7/each -> 68x$7=$476
                        Amount collected for selling 28 payayas @ $3/each -> 28x$3 = $84
                        Total amount collected -> $(476+84) = $560

                        I think this should be a P4 question and there are more examples over http://p4mathsquestions.blogspot.com/.Good luck.
                        Thanks

                        PS : Sorry for the above long-winded explanation. 😞

                        VC's mum

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