Tutor MathsGuru: Ask me for your burning Maths questions!

[tinasen]

I got it. Thank you Eddow.

Eddow:

basket + 65 sweets = 3200
basket _ 40 sweets = 2125

So if you take 3200- 2125 = 1075, the result will be for the 25 sweets
then, 1 sweet will be 1075 divide by 25 = 43g

take 43 x 40 sweets =1720g
2125 - 1720 = 405g (mass of basket)

[lin_bb2000.021981yahoo.021981com.021981sg]

Dear Maths Guru-

Have been finding help all over but i cannot solve this. Can you please help?

:? Amelia, Beatrice and Casey had $738 at first. After Amelia gave 3/8 of her money to Beatrice, Beatrice found that she had $18 less than Amelia. If Casey had 7/10 of what Amelia had left, how much did Beatrice have at first?

[iFruit]

LL:

Dear Maths Guru-

Have been finding help all over but i cannot solve this. Can you please help?

:? Amelia, Beatrice and Casey had $738 at first. After Amelia gave 3/8 of her money to Beatrice, Beatrice found that she had $18 less than Amelia. If Casey had 7/10 of what Amelia had left, how much did Beatrice have at first?

Assume at the end, Amelia = 10u.

Then Casey = 7u, Beatrice = 10u -18

10u + 7u + 10u - 18 = 738

27u = 756---> u = 28

So Amelia at the end = 10u = 280

Beatrice at the beginning = 280 - 3/8 x 448 -18 = 280 - 168 - 18 = 94

HTH.

[Yu Xuan]

LL:

Dear Maths Guru-

Have been finding help all over but i cannot solve this. Can you please help?

:? Amelia, Beatrice and Casey had $738 at first. After Amelia gave 3/8 of her money to Beatrice, Beatrice found that she had $18 less than Amelia. If Casey had 7/10 of what Amelia had left, how much did Beatrice have at first?

Not a guru, but this is my solution;

At first
Amelia --> 16 units

After transfering 3/8 to Beatrice
Amelia --> 16u - 6u = 10u
Beatrice --> 10u - 18
Casey --> 7/10 * 10u = 7u

Working backward, Beatrice started off with;
10u - 18 - 6u --> 4u - 18

10u + 10u + 7u --> 738 + 18
1u --> 756 / 27 = 28

Beatrice at first --> 4*28 - 18 = $94

Is that the answer?

[sall]

Hi. My answer is 94, method slightly diff, but I'm sure this is the answer.

[Dharma]

sall:

Hi. My answer is 94, method slightly diff, but I'm sure this is the answer.

At last
Amelia : 16u – 6u = 10u
Beatrice : 10u - $18
Casey : 7u

27u - $18 = $738
27u = $756
1u = $28

Amount Beatrice had at first = 10($ 28 ) - $18 - 6($28 ) = $94

[wkong]

Hi All,


Need help for the following:

Jenny offered 23 dolls and 17 teddy bears at a discount of 15% for each item. Her total collection for all the items sold was $819.40. Her original sale price of each doll was $7 less than each teddy bear. What was the amount collected from the sale if all the teddy bears? (express your answer to the nearest dollar)

Thanks,
wkong

[charsen]

Hi Mathguru,


Kindly help me with my math problem.
Colin and Rosdin had the same amount of pocket money. Each day, Colin spent $12 and Rosdin spent $15. When Rosdin had $18 left Colin had 5 times as much money left as Rosdin. How much was each boy’s pocket money?

It will be of great help if you show me the solution by model method.

TIA
charsen

[Yu Xuan]

charsen:

Hi Mathguru,


Kindly help me with my math problem.
Colin and Rosdin had the same amount of pocket money. Each day, Colin spent $12 and Rosdin spent $15. When Rosdin had $18 left Colin had 5 times as much money left as Rosdin. How much was each boy's pocket money?

It will be of great help if you show me the solution by model method.

TIA
charsen

Not a guru, but this is my solution while waiting for the model solution;

Difference in their spending per day --> $15 - $12 = $3
Difference in their money --> $18 * 4 = $72

To find out the number to days of spending in order to arrive at a situation when Colin has $72 more than Rosdin,
$72 / $3 = 24 days

Hence, their pocket money is;
Using Rosdin
( $15 * 24 ) + $18 = $378
Alternatively, using Colin;
( $12 * 24 ) + ( $18 * 5) = $378

[autolycus]

charsen:

Hi Mathguru,


Kindly help me with my math problem.
Colin and Rosdin had the same amount of pocket money. Each day, Colin spent $12 and Rosdin spent $15. When Rosdin had $18 left Colin had 5 times as much money left as Rosdin. How much was each boy's pocket money?

It will be of great help if you show me the solution by model method.

TIA
charsen

Each day, Colin is saving $3. Per day, it looks like this.

Colin: UUUU3
Rosdin: UUUUU

Colin is spending 4U per day, Rosdin is spending 5U per day. Each U is $3.

At the end, Rosdin has $18, Colin has 5 x $18 = $90.

So how many Us were there?

Colin has 30U saved.
Rosdin has 6U saved.

Since Colin has been saving 1U per day, he has been saving for 24 days if he has that much more than Rosdin.

So Colin had 24 UUUU + 90 = 24(12) + 90 = $378
Rosdin had 24 UUUUU + 18 = 24(15) + 18 = $378

Actually, it's horrible not being able to draw these things, and the model is not as easy as just to think of it this way:

Colin has saved $72 more than Rosdin and he is saving $3 a day.
That means 72/3 = 24 days of saving.
So Colin had 24x12 + 90 = $378.
Rosdin had the same amount at the beginning = $378.