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    Tutor MathsGuru: Ask me for your burning Maths questions!

    Scheduled Pinned Locked Moved Primary Schools - Academic Support
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    • S Offline
      Superbugs
      last edited by

      Dharma:
      Total No. of Ducks = D

      Total No. of Cows = C
      Total no. of legs = 2D + 4C

      Ratio of the no. of legs of ducks : no. of legs of cows = 2D : 4C = 5 : 9
      18D = 20C
      D : C = 20 : 18

      Total no. of ducks and cows = 20 + 18 = 38
      How did you derive at 18D:20C? You mean cross multiply 2D with 9 and 4C with 5? If yes, why?

      1 Reply Last reply Reply Quote 0
      • S Offline
        Superbugs
        last edited by

        MathIzzzFun:
        Superbugs:

        Hi there, someone pls help me with the following questions:


        Mdm Lek had 57 apples and oranges altogether. There were 3 fewer oranges than apples. Sh egave away half as many oranges as apples and was left with twice as many oranges as apples. How many apples did she give away?

        I can only do up to here:
        2U+3 => 57
        1U=>27
        Oranges =>27
        Apples => 27+3 => 30

        Hi

        Hope this helps :lol:

        http://www.flickr.com/photos/62167097@N02/5705956596/in/photostream

        cheers.

        Wow impressive. I got it. Tks a lot.
        Can anyone help with my earlier two questions pls. Tks

        1 Reply Last reply Reply Quote 0
        • S Offline
          Superbugs
          last edited by

          Hi I have another question, kindly assist:


          Four containers A,B,C & D contained a total of 230 buttons at first. Then the no. of buttons in A was increased by 55, the no. in B was decreased by 15, the no. in C was doubled and the no. in D was halved. As a result, the no. of buttons in each container was the same. Find the no. of buttons in D at first?

          If the no. of buttons in each container was the same at the end, why can’t I use 230/4=57.5 (not a whole no???)

          I used the model method but not sure if this is correct understanding:

          At first
          A=>2U-55
          B=>2U+15
          C=>U
          D=>4U

          9U=230-15+55
          9U=270
          1U=30
          4U=120

          1 Reply Last reply Reply Quote 0
          • CoffeeCatC Offline
            CoffeeCat
            last edited by

            bleeze:
            Hi, someone pls help me with the following question:


            There were 1260 boys and girls in an amusement park. When 5/8 of the girls and 7/13 of the boys left the amusement park, the number of boys and the number of girls remaining in the park is the same. How many more girls than boys were there in the amusement park at first?

            Ans: 140

            Thanks
            There is something wrong with this question. Working backwards, there are 700 girls and 560 boys at first. But 700 is not divisible by 8.
            But otherwise this is my working for such qns...
            This is an equal concept question, because
            3/8 of the girls = 6/13 of the boys
            What we want is the ratio of girls to boys, there are different methods, mine is to make the numerator equal.
            6/16 of girls = 6/13 of boys.
            So there are 16 units of girls and 13 units of boys.
            1 unit ->1260/29 = ???

            1 Reply Last reply Reply Quote 0
            • CoffeeCatC Offline
              CoffeeCat
              last edited by

              Superbugs:
              Hi I have another question, kindly assist:


              Four containers A,B,C & D contained a total of 230 buttons at first. Then the no. of buttons in A was increased by 55, the no. in B was decreased by 15, the no. in C was doubled and the no. in D was halved. As a result, the no. of buttons in each container was the same. Find the no. of buttons in D at first?

              If the no. of buttons in each container was the same at the end, why can't I use 230/4=57.5 (not a whole no???)

              I used the model method but not sure if this is correct understanding:

              At first
              A=>2U-55
              B=>2U+15
              C=>U
              D=>4U

              9U=230-15+55
              9U=270
              1U=30
              4U=120
              Your model method is correct =).
              You cant use 230/4 initially after the total number of buttons after the changes is not guaranteed to be still 230.

              1 Reply Last reply Reply Quote 0
              • CoffeeCatC Offline
                CoffeeCat
                last edited by

                Superbugs:
                Hi there, appreciate it that someone can assist me on the following questions:


                Q1) There are 8 stacks of chairs and 12 chairs in each stack. Each chair is equally spaced apart to form the perimeter of a rectangle. If the no. of chairs placed along its length is thrice the no. of chairs placed along its breadth, how many chairs are placed equally along one of the length of the rectangle.

                12x9 = 108
                108-4 (4 corners) = 104
                108/8 = 13
                13x3=39
                39+2 (2 corners) = 41

                But the answer is 42 and instead of minusing the 4 corners, they add the 4 corners
                108+4=112
                112/8=42
                Why is that so?

                Q2) J bought some strawberries and wanted to put them in boxes. If she put 4 strawberries into each box, there would be 3 strawberries left. If she put 6 strawberries into eah box, she would have 5 strawberries left.

                If the no. of strawberries was between 100 and 150, how many strawberries did J buy?

                I used the common multiple method but got many answers:

                Common Multiple of 4, starting with 100 plus 3 excess:
                103, 107, 111, 114, 119, 123, 127, 131, 135 etc

                Common Multiple of 6, starting with 102 plus 5 excess:
                107, 113, 119, 125, 131, 137

                Why the answer is not 107 or 119 but 131? If this is not the correct method to apply, any other method?
                Qns 1)
                \"If the no. of chairs placed along its length is thrice the no. of chairs placed along its breadth\".
                The 4 corners....the 4 chairs are only counted once. So you have to add 4 so that you really get the total no. of chairs for length + breadth. If you minus the 4, then the above sentence is no longer true.
                Qns 2)
                Maybe there is a typo with the question. Your method is correct. Although the fastest direct method is to notice that any number which is 1 less than a multiple of 12 will satisfies the 2 conditions.
                (let the ans be x. Notice x+1 will be a common multiple of 4 and 6, implying x+1 must be a multiple of 12)

                1 Reply Last reply Reply Quote 0
                • S Offline
                  Superbugs
                  last edited by

                  CoffeeCat:
                  Superbugs:

                  Hi there, appreciate it that someone can assist me on the following questions:


                  Q1) There are 8 stacks of chairs and 12 chairs in each stack. Each chair is equally spaced apart to form the perimeter of a rectangle. If the no. of chairs placed along its length is thrice the no. of chairs placed along its breadth, how many chairs are placed equally along one of the length of the rectangle.

                  12x9 = 108
                  108-4 (4 corners) = 104
                  108/8 = 13
                  13x3=39
                  39+2 (2 corners) = 41

                  But the answer is 42 and instead of minusing the 4 corners, they add the 4 corners
                  108+4=112
                  112/8=42
                  Why is that so?

                  Q2) J bought some strawberries and wanted to put them in boxes. If she put 4 strawberries into each box, there would be 3 strawberries left. If she put 6 strawberries into eah box, she would have 5 strawberries left.

                  If the no. of strawberries was between 100 and 150, how many strawberries did J buy?

                  I used the common multiple method but got many answers:

                  Common Multiple of 4, starting with 100 plus 3 excess:
                  103, 107, 111, 114, 119, 123, 127, 131, 135 etc

                  Common Multiple of 6, starting with 102 plus 5 excess:
                  107, 113, 119, 125, 131, 137

                  Why the answer is not 107 or 119 but 131? If this is not the correct method to apply, any other method?

                  Qns 1)
                  \"If the no. of chairs placed along its length is thrice the no. of chairs placed along its breadth\".
                  The 4 corners....the 4 chairs are only counted once. So you have to add 4 so that you really get the total no. of chairs for length + breadth. If you minus the 4, then the above sentence is no longer true.
                  Qns 2)
                  Maybe there is a typo with the question. Your method is correct. Although the fastest direct method is to notice that any number which is 1 less than a multiple of 12 will satisfies the 2 conditions.
                  (let the ans be x. Notice x+1 will be a common multiple of 4 and 6, implying x+1 must be a multiple of 12)

                  Hi Coffeecat,

                  Tks for your prompt reply but why add 4 where the total no. of chairs is only 108? This is something which I do not understand.

                  The sec question was correctly listed but ans is only 131...

                  1 Reply Last reply Reply Quote 0
                  • CoffeeCatC Offline
                    CoffeeCat
                    last edited by

                    Superbugs:


                    Hi Coffeecat,

                    Tks for your prompt reply but why add 4 where the total no. of chairs is only 108? This is something which I do not understand.

                    The sec question was correctly listed but ans is only 131...
                    Ar, this is a bit hard to explain.
                    Why do u choose to minus 4?
                    From your working, I think u kinda understand what u r supposed to do.
                    To find the total number of chairs along the length + total number of chairs along the breadth
                    Minus-ing the 4 corners isnt going to be correct.... We add the four corners because ...

                    maybe you wana draw a diagram
                    X X X X X X X X X
                    X X
                    X X X X X X X X X
                    (please imagine the 2nd X in the 2nd row as to the far right...)
                    In this diagram, there are 9 X along the length, 3 along the breadth.
                    What's the total?
                    7 + 7 + 1 + 1 + 4 (corners) = 20
                    But length = 9 breadth =3.
                    2 length + 2 breadth = 24
                    There is a shortage of 4 because the 4 corners are only counted once in the first scenario when they are in fact double counted in the second scenario.

                    1 Reply Last reply Reply Quote 0
                    • D Offline
                      Dharma
                      last edited by

                      Superbugs:
                      Dharma:

                      Total No. of Ducks = D

                      Total No. of Cows = C
                      Total no. of legs = 2D + 4C

                      Ratio of the no. of legs of ducks : no. of legs of cows = 2D : 4C = 5 : 9
                      18D = 20C
                      D : C = 20 : 18

                      Total no. of ducks and cows = 20 + 18 = 38

                      How did you derive at 18D:20C? You mean cross multiply 2D with 9 and 4C with 5? If yes, why?

                      You can use fractions instead of ratios.
                      2D/4C = 5/9
                      Cross multiply to get
                      18D = 20C

                      D/C = 20/18 => Ratio of D : C = 20 : 18

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                      • 2 Offline
                        2cutis
                        last edited by

                        Please help :imdrowning: ,


                        We know 2 sq is 2x 2 and 2 cube is 2x2x2 but what's the solution
                        to 2 to the power of 50?

                        1 Reply Last reply Reply Quote 0

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